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x+1=?

Home Tutor With 12+ Yrs of Rich Experience

x+1= 5, as x=4 here (derived through Pythagorus theorem)

Home Tutor With 12+ Yrs of Rich Experience

Okay Poornima, let me elaborate it.Any Rhombus's property says that - it's diagonals intersect at right angles.If the diagonal's intersection point is O, then considering the triangle TLO, & applying Pythagoras Theorem in it, we get:X^2 + (x-1)^2 = (x+1)^2Simplify this equation, & you'll get:... read more

Okay Poornima, let me elaborate it.
Any Rhombus's property says that - it's diagonals intersect at right angles.
If the diagonal's intersection point is O, then considering the triangle TLO, & applying Pythagoras Theorem in it, we get:
X^2 + (x-1)^2 = (x+1)^2
Simplify this equation, & you'll get:
x=4 ( all three sides of this triangle TLO is 4,3 & 5 units respectively...
Hence, (x+1) = 5
Hope, it's clear now.

Mathematics faculty for iitjee and boards

X and x-1 are the perpendicular and base with x+1 as its hypotenuse. After using pythagoras theorem you get sum of squares of perpendicular and base is equal to the square of its hypotenuse. Therefore, x+1=5

X+1=5

Home Tutor With 12+ Yrs of Rich Experience

as x=4, here x+1 = 5.

Tutor

X+1= 5

Tutor

(x+1)^2 =x^2+(x-1)^2 X=4 X+1=5

Tutor

x+1 By is the hypotenuse of the right angles triangle. By Pythagoras Theorem, x=4 .

Tutor.

5

Tutor

Diagonals bisect each other at right angles. (X+1)^2=x^2+(x-1)^2 On solving we get, x^2=4x or X=4 Therefore X+1=5.

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