x+1=?

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Debmalya Bhattacharyya

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x+1= 5, as x=4 here (derived through Pythagorus theorem)
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Okay Poornima, let me elaborate it.Any Rhombus's property says that - it's diagonals intersect at right angles.If the diagonal's intersection point is O, then considering the triangle TLO, & applying Pythagoras Theorem in it, we get:X^2 + (x-1)^2 = (x+1)^2Simplify this equation, & you'll get:...
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Okay Poornima, let me elaborate it.Any Rhombus's property says that - it's diagonals intersect at right angles.If the diagonal's intersection point is O, then considering the triangle TLO, & applying Pythagoras Theorem in it, we get:X^2 + (x-1)^2 = (x+1)^2Simplify this equation, & you'll get: x=4 ( all three sides of this triangle TLO is 4,3 & 5 units respectively...Hence, (x+1) = 5Hope, it's clear now. read less
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(x+1)^2 =x^2+(x-1)^2 X=4 X+1=5
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X+1=5
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Diagonals bisect each other at right angles. (X+1)^2=x^2+(x-1)^2 On solving we get, x^2=4x or X=4 Therefore X+1=5.
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Home Tutor With 15yrs of Rich Experience - Online + Offline classes taken...

as x=4, here x+1 = 5.
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Eco, Maths and Stats Tutor

x+1 By is the hypotenuse of the right angles triangle. By Pythagoras Theorem, x=4 .
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X+1= 5
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X and x-1 are the perpendicular and base with x+1 as its hypotenuse. After using pythagoras theorem you get sum of squares of perpendicular and base is equal to the square of its hypotenuse. Therefore, x+1=5
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