Find the number of terms of the A.P: 7, 13, 19, ...., 205?

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The first term, t1=a = 7. The common difference, b=13 - 7=6. Last term or the nth term, tn=a + (n-1)b = 205. So, we have, 7 + (n - 1)6 = 205 --> (n - 1) = (205 - 7)/6 = 33 --> n = 34. Answer: Number of terms is 34.
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a = 7; d = 13 - 7 = 6; l = 205 n = + 1 = + 1 = (198/6) + 1 = 33 + 1 = 34 There are 34 terms in the given AP.
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Number of terms = 34
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n=34
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n= 34.
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a=7, l=205, d=6 then number of terms in A.P =(l-a)/d +1 =(205-7)/6 +1 =198/6 +1 =33...
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a=7, l=205, d=6 then number of terms in A.P =(l-a)/d +1 =(205-7)/6 +1 =198/6 +1 =33 +1 n=34. read less
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