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# Time of the phone call is modeled with the expoential r.v with mean 12 minutes. calculate the probability that the call will last longer than half an hour.

Senior Statistics Teacher with 20 years of experience from University of Hyderabad

0.08208

Qualified teacher with overall 6 years of research and teaching experience.

Formula for exponential distribution is : f(x) = me–mx By replacing the variables with mean = 12 mins and by information call will last for 0.2 hours to 0.5 hours, we can get the required probability will be : 1-me–mx So, the answer is 0.082 read more

Formula for exponential distribution is : f(x) = memx

By replacing the variables with mean = 12 mins and by information call will last for 0.2 hours to 0.5 hours, we can get the required probability will be : 1-memx

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e^(-2.5) =0.082

20 years of experience as Maths Tutor

e^(-2.5) =0.082

Graduated from renowed Business school and expertise in teaching Mathematics and Physics

It is based on the concept of Exponential distribution. Continuous random variable as it is measured- If x is the amount of time the phone call lasts which is 30 min in this scenario As time is mean for decaying, the decaying parameter her is 1/mean = 1/12 = 0.08 So, the probability that phone call... read more

It is based on the concept of Exponential distribution.

Continuous random variable as it is measured- If x is the amount of time the phone call lasts which is 30 min in this scenario

As time is mean for decaying, the decaying parameter her is 1/mean = 1/12 = 0.08

So, the probability that phone call lasts for 30 minutes is = 0.08e^-0.08*30

Mental math for all competitive exams

e^(-2.5)=0.08208

e^(-2.5)=0.082

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0.082

10 Years experience of training Xth board students for CBSE and ICSE Xth Board exams.

0.082

Experienced Biology teacher from mumbai

e^(-2.5) =0.082

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