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Answered on 03 Jul Tuition

Neha Kumari

Yes, if the teacher can make good communication on the online platform.
Answers 2244 Comments 2
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Answered on 20 Aug Tuition Tuition/Class 6 Tuition Tuition/Class 7 Tuition

Abdul Basit

Final MBBS student and can help high school students in biology

The conventional method of teaching, i.e. Chalk and talk (whiteboard) remains the best for a primary school teacher. But using some exciting animations may also be helpful.
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Answered on 05 Jul Tuition

Shijo Francis

Tutor

It depends upon your understanding and way you adopted. You can listen to youtube classes. Generally, it will take months.
Answers 607 Comments
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Answered on 04 Sep Tuition

V K Mittal

For your requirements as per question asked by you, you should join the graduate course as per your choice and exciting field for work experience. As per your query, there are various areas in which you can work as well as study at graduate level viz hospitality, tourism and travel, hospital management,... read more

For your requirements as per question asked by you, you should join the graduate course as per your choice and exciting field for work experience. As per your query, there are various areas in which you can work as well as study at graduate level viz hospitality, tourism and travel, hospital management, library management, supply chain management, office management. So you can choose one of them, study for three years, and in the fourth year,  you may appear for CAT EXAM  as a target for a career with full zeal and dedicative efforts.

You can get success in a time Bound framework.

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Lesson Posted 6 days ago Tuition/Class I-V Tuition

Lesson on EVS

Shilpi

EVS FOR CLASS III STANDARD Chapter: Living and non-living things Introduction: We observe many things in nature, outside and inside of our house. All these things are categorised into two essential parts - 'Living' and 'Non-living'. Aims and objective of this study : After learning this topic child... read more

EVS FOR CLASS III STANDARD

Chapter: Living and non-living things

Introduction: We observe many things in nature, outside and inside of our house. All these things are categorised into two essential parts - 'Living' and 'Non-living'.

Aims and objective of this study : 

After learning this topic child will be able to identify living and non-living things. They will also know the difference in handling a living creature and a non-living substance.

Definition :

  • Living thing - A thing which has life and gives a response to a particular situation is called a living thing.
  • Non-living thing - A thing which does not have life is called a non-living thing. A non-living thing gives a response to a particular stimulation.

Examples :

  • Living things - Human being, trees, insects, birds, fish, frog etc.
  • Non-living things - Table, chair, clothes, metals, mountains, rivers, water, air etc.

Features :

  • Living things
  1. Living things need air to live.
  2. Living things need food and water.
  3. Living things can grow.
  4. Living things can reproduce. They can give birth to their babies.
  5. Living things can move.
  6. Living things can feel and give a response.
  7. All living things will die.
  • Non-living things
  1. They do not have life; so they neither grow nor give a response to any stimulation.
  2. They can not reproduce.
  3. They only occupy space.
  4. They are of three types - solid, liquid and gas.
  5. They can not move on their own.
  6. They do not have a definite life span.

Difference between living and non-living things :

           Living things                     Non-living things
Living things have life. Non-living things do not have life.
They need food to grow. They do not grow.
They give a response. They do not give a response.
They can move. They can not move on their own.
They have a definite life span. They do not have a definite life span.
Examples-trees, animals, insects, fish etc. Examples- Chair, table, air, water mountain river etc.

 

Summary :

         Living and non-living things create our nature. Living things grow, take food and water from nature, move from one space to another, reproduce and die at a definite time. Non-living things are also a part of our nature. As they have no life, they do not need food and water to grow. They do not have self-movement. They do not reproduce. They may change, but they do not die.

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Lesson Posted 2 days ago Tuition

Make Your Daily Routine Easy With These Tricks.

Dr. Juhi Jain

I am a doctor, recently finished my graduation. I'm preparing for my post graduation alongside teaching....

Alongside your various appointments of the days, sometimes it gets monotonous to continue with the academics, and that's the only difference a student can make from being average to a topper. During days when you dont have exam pressure, or months before exams, when your life is easy, you must take... read more

Alongside your various appointments of the days, sometimes it gets monotonous to continue with the academics, and that's the only difference a student can make from being average to a topper.

During days when you dont have exam pressure, or months before exams, when your life is easy, you must take some time, say just an hour and just read the following syllabus just like you read any other post on Instagram; you dont have to learn or put your brains int it, do it as a routine. Your key should be CONSISTENCY.

These improve your endurance and gives you an extra edge, as who are we kidding, we all like to finish at the verge of exams. These little changes will make a big difference.

More update sooner.

#triedandtested 

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Lesson Posted on 21 May Tuition Language/Marathi Speaking

Name of the dry fruits in marathi

Jayshree Dushing

I am a teacher.I am giving home and online tuition from 4 years.I have completed degree in Diploma in...

Names of dry fruits: ( ) 1. Almond Nut - 2. Apricot dried - 3. Betel-nut - 4. Cashew nut - 5. Chestnut - 6. Coconut - , 7. Cudpahnut - 8. Currant - 9. Dates Dried - 10. Fig - 11. Groundnuts, Peanuts - , ... read more

Names of dry fruits: (सुका मेवा ची नावे)

1. Almond Nut -बदाम
2. Apricot dried - जर्दाळू
3. Betel-nut - सुपारी
4. Cashew nut - काजू
5. Chestnut - छोटे अक्रोड
6. Coconut - खोबरे, नारळ
7. Cudpahnut - चारोळी
8. Currant - मनुका
9. Dates Dried - खारका
10. Fig - अंजीर
11. Groundnuts, Peanuts - भुईमूग, शेंगदाणे
12. Pine Nuts - पाईन काजू
13. Pistachio Nut - पिस्ता
14. Walnuts - अक्रोड

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Lesson Posted on 18/06/2017 CBSE/Class 10/Science Tuition/Class VI-VIII Tuition Tuition/Class IX-X Tuition +1 Tuition/Class VI-VIII Tuition/Science less

Numerical problems on force and pressure

Soumi Roy

I am an experienced, qualified tutor with over 8 years of experience in teaching maths and Science across...

Example 1: A force of 1200 N acts on the surface of area 10 cm2 normally. What would be the thrust and pressure on the surface?Given: Force F = 1200 N, Area A = 10 cm2 = 10 ×10-4 m2 = 10-3 m2Thrust = Normal pressure = F = 1200 NPressure P = F/A 1200N10−3m21200N10−3m2 ... read more

Example 1:

A force of 1200 N acts on the surface of area 10 cm2 normally. What would be the thrust and pressure on the surface?

Given:


Force F = 1200 N, Area A = 10 cm2 = 10 ×10-4 m2 = 10-3 m2

Thrust = Normal pressure = F = 1200 N

Pressure P = F/A 1200N103m21200N10−3m2
              
                      = 1.2 ×× 106 N/m2

Example 2:

The elephant weighs 20,000 N stands on one foot of area 1000 cm2. How much pressure would it exert on the ground?

Given:


Force applied by elephant F = 20,000 N, area A = 1000 cm2 = 1000/100×100m2 = 0.1 m2

The pressure is given by

Pressure P = F/A

      = 20,000N/0.1m2


        = 2,00,000 N/m2.

Example 3:

Calculate the pressure produced by a force of 800 N acting on an area of 2.0 m2.

Solution:

Pressure is defined as force per unit area or P = F / A
P = (800 N) / (2.0 m2
)
P = 400 N / m2
= 400 Pa

Example 4:

The pressure of a gas contained in a cylinder with a movable piston is 300 Pa. The area of the piston is 0.5 m2. Calculate the force that is exerted on the piston.

Solution

Pressure is defined as force per unit area or P = F / A
We multiply both sides of the equation by the area to solve for the force as
F = P A
F = (300 Pa) (0.5 m2
)
F = 150 (Pa) m2
= 150 (N / m2
) m2
F = 150 N

Example 5:

A swimming pool of width 9.0 m and length 24.0 m is filled with water to a depth of 3.0 m. Calculate pressure on the bottom of the pool due to the water.

Solution:

The pressure due to a column of fluid is calculated as the product of the height of the fluid times
the density of the fluid times the acceleration due to gravity. For water the density is d = 1000 kg /
m3
.
? P = d h g
? P = (1000 kg / m3
) (3.0 m) (9.8 m / s2
)
? P = 29400 kg m2 / m3
s2
To simplify the units we cancel one m term in the m2
term in the numerator and one m term in
the m3
term in the denominator to get
? P = 29400 kg m / s2
m2

We know that 1N = 1 kg m / s2
so we can write
? P = 29400 N / m2
= 29400 Pa

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Answered on 13/08/2015 Tuition/Class IX-X Tuition

Roop Narayan

Tutor

Better go through NCERT books.
Answers 26 Comments
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Answered on 10/02/2015 Tuition/Class VI-VIII Tuition

Jyoti Raina

Passionate about teaching and mentoring

1 coulomb is equal to the charge transfer in a metal in one second while contantly 1A of current flows through it
Answers 18 Comments
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