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Answered on 02 Jan Tuition/Class IX-X Tuition Tuition/Class IX-X Tuition/Mathematics Measures of Central Tendency

Tanvi Madbhavi

Highly Qualified Trainer

3 mean - 2 median

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Answers 5 Comments Answered on 26/11/2016 Tuition/Class IX-X Tuition Tuition/Class IX-X Tuition/Mathematics Measures of Central Tendency

Find the mean of first 15 natural numbers?

Ashwini

commerce

9

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Answers 2 Comments Answered on 29/11/2016 Tuition/Class IX-X Tuition Tuition/Class IX-X Tuition/Mathematics Measures of Central Tendency

Find the mode of the following data: 14, 25, 14, 28, 18, 17, 18, 14, 23, 22, 14, 18?

Mamta Mund

Maths Tutor, Certified Vedic Maths Teacher

14 has highest frequency i.e., 4. So, mode is 14.

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Answers 2 Comments Answered on 05/12/2016 Tuition/Class IX-X Tuition Tuition/Class IX-X Tuition/Mathematics Measures of Central Tendency

If the mean of 10, 12, 18, 13, x, 17 is 15. Find the value of x?

Chandan Singh

Math Learning In easy Way

Mean = Sum of total numbers/ total number of numbers 10+12+18+13+x+17/6=15 70+x=90 Hence, x=90-70=20 Ans.

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Answers 2 Comments Answered on 26/11/2016 Tuition/Class IX-X Tuition Tuition/Class IX-X Tuition/Mathematics Measures of Central Tendency

If the mean of 10 observations is 20 and that of another 15 observations is 16. Find the mean of all 25 observations?

Ashwini

commerce

440

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Answers 1 Comments Answered on 29/11/2016 Tuition/Class IX-X Tuition Tuition/Class IX-X Tuition/Mathematics Measures of Central Tendency

The mean of 13 items is 14. If the mean of first 7 items is 12 and that of the last 7 items is 16. Find the 7th item?

Tapas Bhattacharya

Tutor

Sum of 13 items=S = 13 x 14=182. Sum of 1st 7 items=S1 = 7 x 12=84. Sum of last 7 items=S2 = 7 x 16=112. So, S1 + S2=Sum of 13 items + the 7th item=S + 7th item --> 182 + 7th item=84 + 112=196. --> 7th item = 196 - 182 = 14 Answer: 14.

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Answers 1 Comments Answered on 27/11/2016 Tuition/Class IX-X Tuition Tuition/Class IX-X Tuition/Mathematics Measures of Central Tendency

For what value of x, the mode of the following data is 10: 7, 6, 10, x, 7, 5, 12, 14?

Mamta Mund

Maths Tutor, Certified Vedic Maths Teacher

10

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Answers 1 Comments Answered on 26/11/2016 Tuition/Class IX-X Tuition Tuition/Class IX-X Tuition/Mathematics Measures of Central Tendency

Find the mode of 3, 4, 6, 5, 7, 5, 8, 5, 3, 2. If one observation 5 is replaced by 3, will the modal... read more

Find the mode of 3, 4, 6, 5, 7, 5, 8, 5, 3, 2. If one observation 5 is replaced by 3, will the modal value change? If yes, find it? read less

Ashwini

commerce

Yes, mode = 3.

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Answers 1 Comments Answered on 29/11/2016 Tuition/Class IX-X Tuition Tuition/Class IX-X Tuition/Mathematics Measures of Central Tendency

Find the median of the following data 31, 15, 19, 12, 30, 45, 60, 50, 25, 40. If 40 is replaced by 20,... read more

Find the median of the following data 31, 15, 19, 12, 30, 45, 60, 50, 25, 40. If 40 is replaced by 20, what will be the new median? read less

Karuna Shankar Upadhyay

Complete Package

Arranging the data in ascending order, we get: 12, 15, 19, 25, 30, 31, 40, 45, 50, 60. As there are 10 values and 10 is an even number, the mean of 5th and 6th value will be the median. So, median=(30+31)/2 = 30.5 If 40 is replaced by 20, we get: 12, 15, 19, 20, 25, 30, 31, 45, 50, 60. So, median will... read more

Arranging the data in ascending order, we get: 12, 15, 19, 25, 30, 31, 40, 45, 50, 60. As there are 10 values and 10 is an even number, the mean of 5th and 6th value will be the median. So, median=(30+31)/2 = 30.5 If 40 is replaced by 20, we get: 12, 15, 19, 20, 25, 30, 31, 45, 50, 60. So, median will be (25+30)/2=27.5. read less

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Answers 1 Comments Answered on 05/12/2016 Tuition/Class IX-X Tuition Tuition/Class IX-X Tuition/Mathematics Measures of Central Tendency

What is the average of the data: 4, 5, 6, 8, 10, 11, 12?

Chandan Singh

Math Learning In easy Way

Average= (Sum of total data)/no. of data = (4+5+68+10+11+12)/7= 8 (Ans).

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