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Class 10 Tuition > Class 10 Tuition in Shikohabad > Aman Kumar Gupta

Aman Kumar Gupta Class 10 trainer in Shikohabad

Aman Kumar Gupta

locationImg Municipal Council Rd Shikohabad, Shikohabad
2 yrs of Exp
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Teaching is my passion and i am doing this from many years but professionally i have experience of 2 years. I am giving tuition at my and student's home. I got many prizes in different-2 activities during my schooling which enriched my understanding and knowledge as well.
During teaching i use different-2 tricks methods techniques to make student understand instead of learning. I think way of teaching matters instead of written things. Because a good mentor/guide/teacher/ is really a concerning thing.

Languages Spoken

Hindi Mother Tongue (Native)

English Basic

Education

IGNOU 2014

Bachelor of Technology (B.Tech.)

Address

Municipal Council Rd Shikohabad, Shikohabad, India - 283135

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Teaches

Class 10 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

2

Board

CBSE

Experience in School or College

I enjoy so i love teaching. I always give my best and try to use different-2 ways to make students to understand the concept instead of learning. I taught 1 year but my experience was too good. And students was happy with me.

Subjects taught

Mathematics, Science

Taught in School or College

Yes

Class 9 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

2

Board

CBSE

Experience in School or College

Teaching is my passion. I taught in different-2 ways just to make students understood the concepts. Students were satisfied with my way of teaching and this was a great experience.

Subjects taught

Science, Mathematics

Taught in School or College

Yes

Teaching Experience in detail in Class 9 Tuition

I teach in very well manner with lots of examples in different-2 ways on several topics that opens the mind of students and s/he becomes to think more about concepts. I always try to make understand in simple ways thus students can remember the topic. In this manner i enjoy when i teach as i did in the past. Students make me feel special and that is a great experience for me.

Class 8 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

2

Board

CBSE

Subjects taught

Mathematics, Science

Taught in School or College

No

Reviews

No Reviews yet!

Answers by Aman Kumar Gupta

Answered on 09/08/2019 Learn CBSE - Class 10/Mathematics/Quadratic Equations/NCERT Solutions/Exercise 4.3

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Post a Lesson

The sum of the reciprocals of Rehman’s ages, (in years) 3 years ago and 5 years from now is 1/3... ...more
The sum of the reciprocals of Rehman’s ages, (in years) 3 years ago and 5 years from now is 1/3...

Let Rehman's present age be x So before 3 years age=(x-3) years His age after 5 years= (x+5) years So a/c to given data x(x-7)+3(x-7)=0 (x-7)(x+3)=0 So, x=7 or -3 Age can not be negative soRehman's present age is 7 years. ...more

Let Rehman's present age be x

So before 3 years age=(x-3) years

His age after 5 years= (x+5) years

So a/c to given data

 

 

 

 

x(x-7)+3(x-7)=0

(x-7)(x+3)=0

So, x=7 or -3

Age can not be negative soRehman's present age is 7 years.

 

Answers 6 Comments
Dislike Bookmark

Answered on 09/08/2019 Learn CBSE - Class 10/Mathematics/Quadratic Equations/NCERT Solutions/Exercise 4.3

Ask a Question

Post a Lesson

Find the roots of the following equations: ...more
Find the roots of the following equations:

1) x^2-1=3x x^2-3x-1=0 Apply quadratic formula i.e. {-b±√(b^2-4ac)}/2a So, roots= {3±√(9+4)}/2 = {3±√13}/2 So roots are {3+√13}/2 and {3-√13}/2 i.e. and 2) (x-7-x-4)×30 =11×(x+4)(x-7) -330=11×(x^2-3x-28) x^2-3x-28+30=0 X^2-3x+2=0 X^2-2x-x+2=0 x(x-2)-1(x-2)=0 (x-2)(x-1)=0 x=1,2... ...more

1) x^2-1=3x

x^2-3x-1=0

Apply quadratic formula i.e. {-b±√(b^2-4ac)}/2a

So, roots= {3±√(9+4)}/2 = {3±√13}/2  

So roots are {3+√13}/2 and {3-√13}/2  i.e. and

 

2)  (x-7-x-4)×30 =11×(x+4)(x-7)

-330=11×(x^2-3x-28)

x^2-3x-28+30=0

X^2-3x+2=0

X^2-2x-x+2=0

x(x-2)-1(x-2)=0

(x-2)(x-1)=0

x=1,2 i.e. ans

Answers 7 Comments
Dislike Bookmark

Answered on 09/08/2019 Learn CBSE - Class 10/Mathematics/Arithmetic Progression/NCERT Solutions/Exercise 5.3

Ask a Question

Post a Lesson

A spiral is made up of successive semicircles, with centres alternatively at A and B, starting with centre... ...more
A spiral is made up of successive semicircles, with centres alternatively at A and B, starting with centre...

Length of semicircle=circumference/2 = 2Πr/2=Πr There are 13 semicircles with radius 0.5,1,1.5,2,2.5,3,3.5,4,4.5,5,5.5,6,6.5 I.e. in AP whose 1St term=0.5 & common difference=0.5 Now, total length of spiral=Π(0.5+1+1.5+2+2.5+3+3.5+4+4.5+5+5.5+6+6.5) As we know sum of an AP is= no. of terms(1St... ...more

Length of semicircle=circumference/2 = 2Πr/2=Πr

There are 13 semicircles with radius

0.5,1,1.5,2,2.5,3,3.5,4,4.5,5,5.5,6,6.5

I.e. in AP whose 1St term=0.5 &

common difference=0.5

Now, total length of spiral=Π(0.5+1+1.5+2+2.5+3+3.5+4+4.5+5+5.5+6+6.5)

As we know sum of an AP is=

no. of terms(1St term+last term)/2= 13(0.5+6.5)/2=13×7/2=91/2

Now put value

Total length of spiral =(22/7)×(91/2)=11×13=143cm i.e. ans

Answers 3 Comments
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Answered on 07/08/2019

Ask a Question

Post a Lesson

<p>Verify whether (1,-2)is a solution of 2x-3y =8 or not</p> <p>&nbsp;</p>

To verify the solution of the question.just put either value of x or y then you all get another's value i.e. y or x or put value of both x and y in the equation you will get the LHS=RHS. Put x=1 2×1-3y=8 2-3y=8 2-8=3y y=(-6/3) y=-2 i.e. given so verified. Similarly when you put y=-2 you all get... ...more

To verify the solution of the question.just put either value of x or y then you all get another's value i.e. y or x or put value of both x and y in the equation you will get the LHS=RHS.

Put x=1

2×1-3y=8

2-3y=8

2-8=3y

y=(-6/3)

y=-2 i.e. given so verified.

Similarly when you put y=-2 you all get x=1.

Now, put both x=1 & y=-2

2×1-3×(-2)=8

2+6=8

8=8

LHS=RHS so verified.

Answers 294 Comments
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Teaches

Class 10 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

2

Board

CBSE

Experience in School or College

I enjoy so i love teaching. I always give my best and try to use different-2 ways to make students to understand the concept instead of learning. I taught 1 year but my experience was too good. And students was happy with me.

Subjects taught

Mathematics, Science

Taught in School or College

Yes

Class 9 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

2

Board

CBSE

Experience in School or College

Teaching is my passion. I taught in different-2 ways just to make students understood the concepts. Students were satisfied with my way of teaching and this was a great experience.

Subjects taught

Science, Mathematics

Taught in School or College

Yes

Teaching Experience in detail in Class 9 Tuition

I teach in very well manner with lots of examples in different-2 ways on several topics that opens the mind of students and s/he becomes to think more about concepts. I always try to make understand in simple ways thus students can remember the topic. In this manner i enjoy when i teach as i did in the past. Students make me feel special and that is a great experience for me.

Class 8 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

2

Board

CBSE

Subjects taught

Mathematics, Science

Taught in School or College

No

No Reviews yet!

Answers by Aman Kumar Gupta

Answered on 09/08/2019 Learn CBSE - Class 10/Mathematics/Quadratic Equations/NCERT Solutions/Exercise 4.3

Ask a Question

Post a Lesson

The sum of the reciprocals of Rehman&rsquo;s ages, (in years) 3 years ago and 5 years from now is 1/3... ...more
The sum of the reciprocals of Rehman&rsquo;s ages, (in years) 3 years ago and 5 years from now is 1/3...

Let Rehman's present age be x So before 3 years age=(x-3) years His age after 5 years= (x+5) years So a/c to given data x(x-7)+3(x-7)=0 (x-7)(x+3)=0 So, x=7 or -3 Age can not be negative soRehman's present age is 7 years. ...more

Let Rehman's present age be x

So before 3 years age=(x-3) years

His age after 5 years= (x+5) years

So a/c to given data

 

 

 

 

x(x-7)+3(x-7)=0

(x-7)(x+3)=0

So, x=7 or -3

Age can not be negative soRehman's present age is 7 years.

 

Answers 6 Comments
Dislike Bookmark

Answered on 09/08/2019 Learn CBSE - Class 10/Mathematics/Quadratic Equations/NCERT Solutions/Exercise 4.3

Ask a Question

Post a Lesson

Find the roots of the following equations: ...more
Find the roots of the following equations:

1) x^2-1=3x x^2-3x-1=0 Apply quadratic formula i.e. {-b±√(b^2-4ac)}/2a So, roots= {3±√(9+4)}/2 = {3±√13}/2 So roots are {3+√13}/2 and {3-√13}/2 i.e. and 2) (x-7-x-4)×30 =11×(x+4)(x-7) -330=11×(x^2-3x-28) x^2-3x-28+30=0 X^2-3x+2=0 X^2-2x-x+2=0 x(x-2)-1(x-2)=0 (x-2)(x-1)=0 x=1,2... ...more

1) x^2-1=3x

x^2-3x-1=0

Apply quadratic formula i.e. {-b±√(b^2-4ac)}/2a

So, roots= {3±√(9+4)}/2 = {3±√13}/2  

So roots are {3+√13}/2 and {3-√13}/2  i.e. and

 

2)  (x-7-x-4)×30 =11×(x+4)(x-7)

-330=11×(x^2-3x-28)

x^2-3x-28+30=0

X^2-3x+2=0

X^2-2x-x+2=0

x(x-2)-1(x-2)=0

(x-2)(x-1)=0

x=1,2 i.e. ans

Answers 7 Comments
Dislike Bookmark

Answered on 09/08/2019 Learn CBSE - Class 10/Mathematics/Arithmetic Progression/NCERT Solutions/Exercise 5.3

Ask a Question

Post a Lesson

A spiral is made up of successive semicircles, with centres alternatively at A and B, starting with centre... ...more
A spiral is made up of successive semicircles, with centres alternatively at A and B, starting with centre...

Length of semicircle=circumference/2 = 2Πr/2=Πr There are 13 semicircles with radius 0.5,1,1.5,2,2.5,3,3.5,4,4.5,5,5.5,6,6.5 I.e. in AP whose 1St term=0.5 & common difference=0.5 Now, total length of spiral=Π(0.5+1+1.5+2+2.5+3+3.5+4+4.5+5+5.5+6+6.5) As we know sum of an AP is= no. of terms(1St... ...more

Length of semicircle=circumference/2 = 2Πr/2=Πr

There are 13 semicircles with radius

0.5,1,1.5,2,2.5,3,3.5,4,4.5,5,5.5,6,6.5

I.e. in AP whose 1St term=0.5 &

common difference=0.5

Now, total length of spiral=Π(0.5+1+1.5+2+2.5+3+3.5+4+4.5+5+5.5+6+6.5)

As we know sum of an AP is=

no. of terms(1St term+last term)/2= 13(0.5+6.5)/2=13×7/2=91/2

Now put value

Total length of spiral =(22/7)×(91/2)=11×13=143cm i.e. ans

Answers 3 Comments
Dislike Bookmark

Answered on 07/08/2019

Ask a Question

Post a Lesson

<p>Verify whether (1,-2)is a solution of 2x-3y =8 or not</p> <p>&nbsp;</p>

To verify the solution of the question.just put either value of x or y then you all get another's value i.e. y or x or put value of both x and y in the equation you will get the LHS=RHS. Put x=1 2×1-3y=8 2-3y=8 2-8=3y y=(-6/3) y=-2 i.e. given so verified. Similarly when you put y=-2 you all get... ...more

To verify the solution of the question.just put either value of x or y then you all get another's value i.e. y or x or put value of both x and y in the equation you will get the LHS=RHS.

Put x=1

2×1-3y=8

2-3y=8

2-8=3y

y=(-6/3)

y=-2 i.e. given so verified.

Similarly when you put y=-2 you all get x=1.

Now, put both x=1 & y=-2

2×1-3×(-2)=8

2+6=8

8=8

LHS=RHS so verified.

Answers 294 Comments
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