loading......

coming soon

Coming Soon

We are in process of building the inventory of good professionals in this category

Got it!

Where do you need ?

location

Please select a Location.

Ask a Progressions Question

Get your questions answered by Progressions Professionals.

+ Follow 24 Followers

Top Contributors

Sarvajeet

187 Answers

Tapas

61 Answers

Ankit

46 Answers

Chandan

40 Answers

Shikha

35 Answers

Mamata

30 Answers

Ram Mohan

30 Answers

Sreedevi

28 Answers

Rajendran

27 Answers

Thousands of experts Tutors, Trainers & other Professionals are available to answer your questions

Showing 1 to 25 of 30
Sort By: 
S

Show previous answers

Saurabh replied | 04/12/2016

n= 34.

0 0

Manikandan replied | 08/12/2016

a=7, l=205, d=6 then number of terms in A.P =(l-a)/d +1
=(205-7)/6 +1
=198/6 +1
=33 +1
n=34.

0 0

Answer

You can add upto 6 Images

U

User 03/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Progressions

Find the A.P whose 10th term is 5 and 18th term is 77?

0 0

Tapas replied | 01/12/2016

Let the first term be a and the common difference be b.
So, the 10th term: t10 = a + 9b = 5.
and, the 18th term: t18 = a + 17b = 77.
So, from t17 - t10 we get: 8b = 77 - 5 = 72.
This gives: b = 9.
From t10 we get: a = 5 - 9b = 5 - 9x9 = -76.
So, a = -76, b = 9 and the A.P is:-
-76, -67, -58, -49, ..... (Answer).

0 0

Answer

You can add upto 6 Images

S

Suresh 03/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Progressions

In a certain A.P the 24th term is twice the 10th term. Prove that the 72nd term is twice the 34th term?

0 0

Tapas replied | 01/12/2016

Let the first term be a and the common difference be b.
So, by the given condition:-
t24 = 2 x t10 --> a + 23 b = 2 ( a + 9b) = 2a + 18b.
This gives: a = 5b.
So, the 72nd term: t72 = a +71b = 5b + 71b = 76b.
and the 34th term: t34 = a + 33b = 5b + 33b = 38b = 76b/2 = t72/2.
So, the 72nd term is twice the 34th term. (Proved)

0 0

Answer

You can add upto 6 Images

P

Preeti 03/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Progressions

If 9th term of an A.P is zero, prove that its 29th term is double the 19th term?

0 0

Ram Mohan replied | 22/11/2016

Let 'a' be the first term and 'd' be the common difference of the given A P. If Tn stands for nth term of this A P, then we get T9 = a + 8d= 0 ( Given).
T19 = a + 18 d = ( a + 8 d) + 10 d = T9 + 10 d = 0 +10 d = 10d
T29 = a + 28 d = (a + 8 d) +20 d = T9 + 20 d = 0 + 20 d = 20d =2 *10 d= 2 * T19.

0 0

Answer

You can add upto 6 Images

P

Prakash 03/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Progressions

Determine the A.p whose third term is 16 and the difference of 5th from 7th term is 12?

0 0

Chandan replied | 22/11/2016

an= a+(n-1)d
an=10+(30-1)*(-3)
=10-87=-77
30th term is -77

a + (3 ? 1) d = 16
a + 2d = 16 ... (i)
a7 ? a5 = 12
[a+ (7 ? 1) d] ? [a + (5 ? 1) d]= 12
(a + 6d) ? (a + 4d) = 12
2d = 12
d = 6
From equation (i), we get,
a + 2 (6) = 16
a + 12 = 16
a = 4
Therefore, A.P. will be
4, 10, 16, 22, …

0 0

Answer

You can add upto 6 Images

G

Granth 03/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Progressions

The sum of the first six terms of an A.p is zero and the fourth term is 2. Find the sum of its first 30 terms?

0 0

Tapas replied | 01/12/2016

Let the first term be (a - 5b) and the common difference be 2b.
So the six terms are: (a - 5b), (a - 3b), (a - b), (a + b), (a + 3b), (a + 5b).
By the given conditions:-
Sum of six terms = (a - 5b) + (a - 3b) + (a - b) + (a + b) + (a + 3b) + (a + 5b) = 6a = 0.
So, a = 0.
The fourth term = a + b = 2 --> 0 + b = 2 --> b = 2.
So, for the A.P. the first term...  more»
Let the first term be (a - 5b) and the common difference be 2b.
So the six terms are: (a - 5b), (a - 3b), (a - b), (a + b), (a + 3b), (a + 5b).
By the given conditions:-
Sum of six terms = (a - 5b) + (a - 3b) + (a - b) + (a + b) + (a + 3b) + (a + 5b) = 6a = 0.
So, a = 0.
The fourth term = a + b = 2 --> 0 + b = 2 --> b = 2.
So, for the A.P. the first term x = (a - 5b) = -10. The common difference, y = 2b = 4.
Sum of 1st 30 terms, S30 = (n/2)[2x + (n-1)y] = 15 x [ -20 + 29 x 4] = 1440. (Answer) «less

0 0

Answer

You can add upto 6 Images

S

Supriyo 03/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Progressions

An A.P consists of 60 terms. If the first and the last terms be 7 and 125 respectively, find 32nd term?

0 0

Tapas replied | 01/12/2016

Let the first term be a and the common difference be b. So,
t1 = a = 7 and t60 = a + 59b = 125.
From above, we get:-
t60 - t1 = 59b = 125 - 7 = 118.
So, b = 118/59 = 2.
Hence, the 32nd term, t32 = a + 31b = =7 + 31x2 = 69. (Answer)

0 0

Answer

You can add upto 6 Images

N

Nitesh 03/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Progressions

Three numbers are in A.P. If the sum of these numbers be 27 and the product 648, find the numbers?

0 0

Tapas replied | 01/12/2016

Let the 3 terms are (a - b), a, and (a + b).
So,
(a - b) + a + ( a + b) = 27
=> 3a = 27
=> a = 9.
Now the product is 648. So,
(9 - b) x 9 x (9 + b) = 648
=> (81 - b^2) = 648/9 = 72
=> b^2 = 81 - 72 = 9
=> b = =3 or b = -3.
For, b = 3, the numbers are:
(9 - 3), 9, (9 + 3) = 6, 9, 12
or
(9 - (-3)), 9 , (9 + (-3)) = 12, 9, 6
The...  more»
Let the 3 terms are (a - b), a, and (a + b).
So,
(a - b) + a + ( a + b) = 27
=> 3a = 27
=> a = 9.
Now the product is 648. So,
(9 - b) x 9 x (9 + b) = 648
=> (81 - b^2) = 648/9 = 72
=> b^2 = 81 - 72 = 9
=> b = =3 or b = -3.
For, b = 3, the numbers are:
(9 - 3), 9, (9 + 3) = 6, 9, 12
or
(9 - (-3)), 9 , (9 + (-3)) = 12, 9, 6
The three numbers are 6, 9, 12 or 12, 9, 6 (Answer) «less

0 0

Answer

You can add upto 6 Images

A

Anmol 03/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Progressions

Write the first four terms of the A.p, when the first term a and the common difference d are given: a = 10, d = 10?

0 0

Tapas replied | 01/12/2016

The first four terms are 10, 10 + 10, 10 + 2x10, and 10 + 3x10.
So, the terms are: 10, 20, 30, 40.

0 0

Answer

You can add upto 6 Images

S

Samskriti 03/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Progressions

For the given A.P write the first term and the common difference: 3, 1, -1, -3, …..?

0 0

Tapas replied | 01/12/2016

The first term is 3.
The common difference = 1-3 = -2.

0 0

Answer

You can add upto 6 Images

R

Ramya 03/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Progressions

What is the 30th term of a given A.P: 10, 7, 4,....?

0 0

Chandan replied | 22/11/2016

a3 = 16

a + (3 ? 1) d = 16
a + 2d = 16 ... (i)
a7 ? a5 = 12
[a+ (7 ? 1) d] ? [a + (5 ? 1) d]= 12
(a + 6d) ? (a + 4d) = 12
2d = 12
d = 6
From equation (i), we get,
a + 2 (6) = 16
a + 12 = 16
a = 4
Therefore, A.P. will be
4, 10, 16, 22, …

0 0

Answer

You can add upto 6 Images

S

Sarvepalli 03/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Progressions

Which term of the A.P: 3, 8, 13, 18, ……, is 78?

0 0

Chandan replied | 22/11/2016

tn = a + (n - 1) d
78 = 3 + (n - 1)5
78 = 3 + 5n - 5
78 = - 2 + 5n
78 + 2 = 5n
80 = 5n
80/5 = n
16 = n
n= 16

0 0

Answer

You can add upto 6 Images

K

Krity 03/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Progressions

The 17th term of an A.P exceeds its 10th term by 7. Find the common difference?

0 0

Sarvajeet replied | 23/11/2016

1.

0 0

Answer

You can add upto 6 Images

S

Shreyansh 03/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Progressions

If the 3rd and the 9th terms of an A.P are 4 and -8 respectively, which term of this A.P is zero?

0 0

Tapas replied | 01/12/2016

Let the first term and the common difference are a and b.
So, the third term: t3 = a + 2b = 4.
and, the 9th term: t9 = a + 8b = -8.

So, t9 - t6 = 6b = -8 - 4 = -12 --> b = - 2.

So, from the expression of t3, we get:
a = 4 - 2b = 4 + 4 = 8.

Let us consider that the nth term is zero. So:

tn = a + (n-1)b = 0 --> 8 + (n-1)(-2)...  more»
Let the first term and the common difference are a and b.
So, the third term: t3 = a + 2b = 4.
and, the 9th term: t9 = a + 8b = -8.

So, t9 - t6 = 6b = -8 - 4 = -12 --> b = - 2.

So, from the expression of t3, we get:
a = 4 - 2b = 4 + 4 = 8.

Let us consider that the nth term is zero. So:

tn = a + (n-1)b = 0 --> 8 + (n-1)(-2) = 0 --> 8 -2n +2 = 0 --> 2n = 10 --> n = 5.

Answer: The 5th term of the series is zero. «less

0 0

Answer

You can add upto 6 Images

T

Thomas 03/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Progressions

Find the sum of the following A.P: 1, 3, 5, 7,......, 199?

0 0

Answer

You can add upto 6 Images

D

Deepak 03/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Progressions

A, b and c are in A.P. Prove that b + c, c + a and a + b are in A.P?

0 0

Answer

You can add upto 6 Images

A

Aishwarya 03/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Progressions

Find the sum of the series 51 + 50 + 49 +..... + 21?

0 0

Answer

You can add upto 6 Images

A

Abinaya 03/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Progressions

How many terms of A.P -10, -7, -4, -1,...... must be added to get the sum -104?

0 0

Answer

You can add upto 6 Images

M

Mukundan 03/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Progressions

If the sum of p terms of an A.P is 3(square of p) + 4p, find its nth term?

0 0

Answer

You can add upto 6 Images

H

Harish 03/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Progressions

If the given sequential is an A.P then find the common difference d and write three more terms: 2, 4, 8, 16,…… ?

0 0

Answer

You can add upto 6 Images

A

Amanbir 03/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Progressions

Find the missing term of an A.P: 2, __, 26?

0 0

Answer

You can add upto 6 Images

S

Shilpa 03/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Progressions

Check whether -150 is a term of the A.P: 11, 8, 5, 2, …..?

0 0

Answer

You can add upto 6 Images

P

Prakash 03/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Progressions

Find the 31st term of an A.P whose 11th term is 38 and the 16th term is 73?

0 0

Answer

You can add upto 6 Images

S

Sona 03/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Progressions

An A.P consist of 50 terms of which 3rd term is 12 and the last term is 106. Find the 29th term?

0 0

Answer

You can add upto 6 Images

N

Nagesh 03/11/2016 in  Class IX-X Tuition, Mathematics(Class IX-X Tuition), Progressions

Which term of the A.P: 3, 15, 27, 39,.......... will be 132 more than its 54th term?

0 0

Answer

You can add upto 6 Images

12Next

Find Best Class IX-X Tuition ?

Find Now »