She is an exceptional and patient teacher. I would definitely recommend her tuition to students of any level.
Super Tutor Super Tutor 
7 yrs of Exp 
50 students 
793 hrs of classes 
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Tutor's home She is an exceptional and patient teacher. I would definitely recommend her tuition to students of any level.
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DCRUST, MURTHAL(131039) 2018
Master of Science (M.Sc.)
Shastri Colony, Panipat, India - 132103
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11 Students 
UrbanPro Certified Tutor
For NEET-UG Coaching
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in NEET-UG Coaching Classes
7
NEET Subjects
Physics
17 Students Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
7
Board
CBSE, ISC/ICSE
Preferred class strength
Group Classes, One on one/ Private Tutions
Subjects taught
Physics
Taught in School or College
Yes
2 Students Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Engineering Entrance Coaching classes
5
Engineering Entrance Exams
IIT JEE Coaching Classes
IITJEE Coaching
IIT JEE Crash Course, IIT JEE Mains Coaching, IIT JEE Integrated Coaching, IIT JEE Foundation Course
Type of class
Crash Course, Regular Classes
IIT-JEE Subjects
Physics
5 out of 5 21 reviews
V Shothish kumar
"She is an exceptional and patient teacher. I would definitely recommend her tuition to students of any level. "
Bhaskar
Class 11 Tuition
"A good, kind and a patient teacher, who creates a positive and a supportive environment for her students. "
Ishant Sharma
"Very supportive and hardworking teacher always clear doubts first and always attentive and punctual in class. "
Mariyam
"It's great experience in learning physics from mam, mam helped me to revise chapters in concise way and cleared my concepts precisely to complete chapters. "
Have you attended any class with Sandhya?
Answered on 03/04/2025 Learn CBSE - Class 11/Physics
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Terminal velocity is defined as the highest velocity attained by an object falling through a fluid. It is observed when the sum of drag force and buoyancy is equal to the downward gravity force acting on the object. The acceleration of the object is zero as the net force acting on the object is zero.
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Comments Answered on 03/12/2024 Learn CBSE - Class 11/Physics
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Like 0 Answers 21 Comments Answered on 06/11/2023 Learn CBSE - Class 11/Physics
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Like 0 Answers 92 Comments Answered on 19/05/2023
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Like 0 Answers 669 Comments Answered on 16/05/2023
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11 Students UrbanPro Certified Tutor
For NEET-UG Coaching
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in NEET-UG Coaching Classes
7
NEET Subjects
Physics
17 Students Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
7
Board
CBSE, ISC/ICSE
Preferred class strength
Group Classes, One on one/ Private Tutions
Subjects taught
Physics
Taught in School or College
Yes
2 Students Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Engineering Entrance Coaching classes
5
Engineering Entrance Exams
IIT JEE Coaching Classes
IITJEE Coaching
IIT JEE Crash Course, IIT JEE Mains Coaching, IIT JEE Integrated Coaching, IIT JEE Foundation Course
Type of class
Crash Course, Regular Classes
IIT-JEE Subjects
Physics
Answered on 03/04/2025 Learn CBSE - Class 11/Physics
Ask a Question
Post a Lesson
Terminal velocity is defined as the highest velocity attained by an object falling through a fluid. It is observed when the sum of drag force and buoyancy is equal to the downward gravity force acting on the object. The acceleration of the object is zero as the net force acting on the object is zero.
Like 0 Answers 23 Comments Answered on 03/12/2024 Learn CBSE - Class 11/Physics
Ask a Question
Post a Lesson
Like 0 Answers 21 Comments Answered on 06/11/2023 Learn CBSE - Class 11/Physics
Ask a Question
Post a Lesson
Like 0 Answers 92 Comments Answered on 19/05/2023
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Post a Lesson
Like 0 Answers 669 Comments Answered on 16/05/2023
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Post a Lesson
Like 0 Answers 669 Comments Ask a Question
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