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NTSE exam Coaching classes Fees

Estimated Fees in India

₹ 400 to ₹ 800 per hour

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Top Questions about NTSE exam Coaching classes Fees

Lesson Posted on 06/02/2018 Learn CBSE/Class 10 +2 CBSE/Class 9 Exam Coaching/NTSE exam Coaching

Find The Length Of BF (Very Important Question)

Sujoy D.

1. Strong concept building classes. 2. Weekly tests in weak areas for students to improve their confidence. 3....

Question: Solution: read more

Question:

 

                                      

 

Solution:

 

                                                                    

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Lesson Posted on 06/02/2018 Learn Exam Coaching/NTSE exam Coaching +1 Exam Coaching/Math Olympiad

Find The Ratio AE: EC (Important For NTSE Olympiad)

Sujoy D.

1. Strong concept building classes. 2. Weekly tests in weak areas for students to improve their confidence. 3....

Question given below: Solution 1: Solution 2: Solution 3: Solution 4: Draw a line from D... read more

Question given below:

                           

 

Solution 1:

 

                                                       

Solution 2:

 

                                                               

Solution 3:

 

                                     

Solution 4:

Draw a line from D parallel to BE cutting AC at P.

CDP and CBE are similar.

EP/EC = BD/BC = 3:5

Also, AFE and ADP are similar.

AE/EP = AD/FD = 2:1

Multiply both the equation from the top, so AE/EC = 6:5.

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Lesson Posted on 31/01/2018 Learn CBSE/Class 9/Mathematics +2 CBSE/Class 10/Mathematics Exam Coaching/NTSE exam Coaching

ABC Is An Equilateral Triangle With Side Length 6. If x Is A Point On Side CA, What Is The Minimum Value...

Sujoy D.

1. Strong concept building classes. 2. Weekly tests in weak areas for students to improve their confidence. 3....

Q. ABC is an equilateral triangle with side length 6. If X is a point on side CA , what is the minimum value of BX² + XC² ? Answer: Let's D is mid point of CA (BD = height = 3√3) So, Bx^2 + Cx^2 = (3√3)^2 + Dx^2 + Cx^2 = 27 + Dx^2 + Cx^2 So minima = 27 + 2Dx.Cx... read more

Q. ABC is an equilateral triangle with side length 6. If X is a point on side CA , what is the minimum value of BX² + XC² ?

 

Answer: Let's D is mid point of CA (BD = height = 3√3)

So, Bx^2 + Cx^2 = (3√3)^2 + Dx^2 + Cx^2 = 27 + Dx^2 + Cx^2

So minima = 27 + 2Dx.Cx (from AM GM)

Now (Dx + Cx) = 3

DX^2 +CX^2 = (9-2DX.CX)

2Dx.Cx = 9-2Dx.Cx

2Dx.Cx = 9/2

Ans: 27+9/2 =  63/2

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