Atharv Aundhekar

Ashoknagar, Nanded, India - 431605

Atharv Aundhekar photo

Atharv Aundhekar

Tutor

Ashoknagar, Nanded, India - 431605.

3.9

UrbanPro Rating

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Overview

I am a B.Tech student who has command on maths,mental ability and willing to teach. I will help you to get easy in mathematics and metal ability.

Languages Spoken

Marathi

English

Hindi

Education

SGGSIE&T, NANDED Pursuing

Bachelor of Technology (B.Tech.)

Address

Ashoknagar, Nanded, India - 431605

Verified Info

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Demo Class

No

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NTSE exam Coaching classes Overview

NTSE exam Coaching classes

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Reviews

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Answers by Atharv Aundhekar (5)

Answered on 08/12/2017 CBSE/Class 9/Mathematics Tuition/Class IX-X Tuition

Mean of 100 observation=50 So total sum =50 100=5000 Now one observation is replaced having value 50 by 150 So change in sum=150-50=100 Therefore change in sum=100 So new sum is 5100 Therefore new mean is 5100/100=51
Answers 49 Comments
Dislike Bookmark

Answered on 08/12/2017 CBSE/Class 10/Science Tuition/Class IX-X Tuition

R=resistivity*lenghth/area So resistivity=R A/L Therefore resistivity=5.026 10^-6
Answers 6 Comments
Dislike Bookmark

Answered on 05/12/2017 CBSE/Class 9/Science Tuition/Class IX-X Tuition

Molecular mass of O=16 and H=2 so molecular mass of H2O=18
Answers 24 Comments
Dislike Bookmark

Answered on 05/12/2017 CBSE/Class 10/Science Tuition/Class IX-X Tuition

Potential difference is simply the level difference between two points. In the case of charge it is measured in volts
Answers 19 Comments
Dislike Bookmark

Answered on 04/12/2017 Tuition/Class IX-X Tuition

Newton's second law is simply stated as F=ma where F is the force applied m is the mass and a is acceleration
Answers 206 Comments
Dislike Bookmark

Atharv AundhekarDirections

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NTSE exam Coaching classes 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Class 9 Tuition 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Board

CBSE, State

CBSE Subjects taught

Mathematics, Science, Marathi

Taught in School or College

No

State Syllabus Subjects taught

Social Science, Marathi, English, Science, Mathematics

Class 10 Tuition 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Board

CBSE, State

CBSE Subjects taught

Mathematics, Science, Marathi

Taught in School or College

No

State Syllabus Subjects taught

Social Science, Marathi, English, Science, Mathematics

Class 6 Tuition 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Board

State, CBSE

CBSE Subjects taught

Science, Marathi, Mathematics, English

Taught in School or College

No

State Syllabus Subjects taught

Science, Mathematics, Marathi, English

Class 7 Tuition 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Board

State, CBSE

CBSE Subjects taught

Science, Marathi, Mathematics, English

Taught in School or College

No

State Syllabus Subjects taught

Science, Mathematics, Marathi, English

Class 8 Tuition 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Board

State, CBSE

CBSE Subjects taught

Science, Marathi, Mathematics, English

Taught in School or College

No

State Syllabus Subjects taught

Science, Mathematics, Marathi, English

National Scholarship Exam(NSE) Coaching classes 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Math Olympiad classes 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Science Olympiad classes 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

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No Reviews yet! Be the first one to Review

Answers by Atharv Aundhekar (5)

Answered on 08/12/2017 CBSE/Class 9/Mathematics Tuition/Class IX-X Tuition

Mean of 100 observation=50 So total sum =50 100=5000 Now one observation is replaced having value 50 by 150 So change in sum=150-50=100 Therefore change in sum=100 So new sum is 5100 Therefore new mean is 5100/100=51
Answers 49 Comments
Dislike Bookmark

Answered on 08/12/2017 CBSE/Class 10/Science Tuition/Class IX-X Tuition

R=resistivity*lenghth/area So resistivity=R A/L Therefore resistivity=5.026 10^-6
Answers 6 Comments
Dislike Bookmark

Answered on 05/12/2017 CBSE/Class 9/Science Tuition/Class IX-X Tuition

Molecular mass of O=16 and H=2 so molecular mass of H2O=18
Answers 24 Comments
Dislike Bookmark

Answered on 05/12/2017 CBSE/Class 10/Science Tuition/Class IX-X Tuition

Potential difference is simply the level difference between two points. In the case of charge it is measured in volts
Answers 19 Comments
Dislike Bookmark

Answered on 04/12/2017 Tuition/Class IX-X Tuition

Newton's second law is simply stated as F=ma where F is the force applied m is the mass and a is acceleration
Answers 206 Comments
Dislike Bookmark

Atharv Aundhekar describes himself as Tutor. He conducts classes in Class 10 Tuition, Class 6 Tuition and Class 7 Tuition. Atharv is located in Ashoknagar, Nanded. Atharv takes Regular Classes- at his Home. Atharv is pursuing Bachelor of Technology (B.Tech.) from SGGSIE&T,NANDED. HeĀ is well versed in Marathi, English and Hindi.

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