Atharv Aundhekar

Ashoknagar, Nanded, India - 431605

# Atharv Aundhekar

## Tutor

Ashoknagar, Nanded, India - 431605.

3.9

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## Overview

I am a B.Tech student who has command on maths,mental ability and willing to teach. I will help you to get easy in mathematics and metal ability.

Marathi

English

Hindi

## Education

SGGSIE&T, NANDED Pursuing

Bachelor of Technology (B.Tech.)

Ashoknagar, Nanded, India - 431605

Phone Verified

Email Verified

## Demo Class

No

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## NTSE exam Coaching classes Overview

NTSE exam Coaching classes

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

## Reviews

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## Answers by Atharv Aundhekar (5)

Mean of 100 observation=50 So total sum =50 100=5000 Now one observation is replaced having value 50 by 150 So change in sum=150-50=100 Therefore change in sum=100 So new sum is 5100 Therefore new mean is 5100/100=51
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R=resistivity*lenghth/area So resistivity=R A/L Therefore resistivity=5.026 10^-6
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Molecular mass of O=16 and H=2 so molecular mass of H2O=18
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Potential difference is simply the level difference between two points. In the case of charge it is measured in volts
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Newton's second law is simply stated as F=ma where F is the force applied m is the mass and a is acceleration
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Atharv AundhekarDirections

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NTSE exam Coaching classes 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Class 9 Tuition 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Board

CBSE, State

CBSE Subjects taught

Mathematics, Science, Marathi

Taught in School or College

No

State Syllabus Subjects taught

Social Science, Marathi, English, Science, Mathematics

Class 10 Tuition 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Board

CBSE, State

CBSE Subjects taught

Mathematics, Science, Marathi

Taught in School or College

No

State Syllabus Subjects taught

Social Science, Marathi, English, Science, Mathematics

Class 6 Tuition 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Board

State, CBSE

CBSE Subjects taught

Science, Marathi, Mathematics, English

Taught in School or College

No

State Syllabus Subjects taught

Science, Mathematics, Marathi, English

Class 7 Tuition 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Board

State, CBSE

CBSE Subjects taught

Science, Marathi, Mathematics, English

Taught in School or College

No

State Syllabus Subjects taught

Science, Mathematics, Marathi, English

Class 8 Tuition 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Board

State, CBSE

CBSE Subjects taught

Science, Marathi, Mathematics, English

Taught in School or College

No

State Syllabus Subjects taught

Science, Mathematics, Marathi, English

National Scholarship Exam(NSE) Coaching classes 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

this is test message this is test message this is test message this is test message this is test message this is test message this is test message

No Reviews yet! Be the first one to Review

## Answers by Atharv Aundhekar (5)

Mean of 100 observation=50 So total sum =50 100=5000 Now one observation is replaced having value 50 by 150 So change in sum=150-50=100 Therefore change in sum=100 So new sum is 5100 Therefore new mean is 5100/100=51
Dislike Bookmark

R=resistivity*lenghth/area So resistivity=R A/L Therefore resistivity=5.026 10^-6
Dislike Bookmark

Molecular mass of O=16 and H=2 so molecular mass of H2O=18
Dislike Bookmark

Potential difference is simply the level difference between two points. In the case of charge it is measured in volts
Dislike Bookmark

Newton's second law is simply stated as F=ma where F is the force applied m is the mass and a is acceleration
Dislike Bookmark

Atharv Aundhekar describes himself as Tutor. He conducts classes in Class 10 Tuition, Class 6 Tuition and Class 7 Tuition. Atharv is located in Ashoknagar, Nanded. Atharv takes Regular Classes- at his Home. Atharv is pursuing Bachelor of Technology (B.Tech.) from SGGSIE&T,NANDED. HeĀ is well versed in Marathi, English and Hindi.

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