A wire is 1m long, 0.2mm in diameter and has resistance of 10?. Calculate its resistivity.

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Let L= length of wire d=daimeter of wire R= resistance of wire in ohms Give data L= 1m d= 0.2mm converted mm into meter d=0.2×10^-3 m R= 10Ω R=p L/A Area=pi×(d/2)^2 =3.14× (0.2×10^-3/2)^2 =3.1415×10^-08 R=p L/A R=pL/A 10=p×(1/3.1415×10^-08) Resistivity =3.14×10^-07 Ωm
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Maths Tutor

l=1m,R=10ohms,d=0.2mm=0.0002m a=? a=πR2 then,radius is half of diameter R=0.0001m a=3.14*0.0001*0.0001=3.14e-8 m2 resistivity = resistance x (area/length) resistivity=10*(3.14e-8/1) resistivity=3.14e-7 answer
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0.3142 Ohm-mm
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Mathematics Tutor

Resistivity=R*A/l =10*22/7*10^-8/1 =31.42*10^-8
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Tutor

R=resistivity*lenghth/area So resistivity=R×A/L Therefore resistivity=5.026×10^-6
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Tutor

Resistivity=(Resistance*Area of the wire)/Length of the wire=3.141*10^(-7) ohm-m Where, * means multiplication L=length of the wire=1m R=Resistance=1o ohm A=Pi*r^2 and r=d/2=0.1mm
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