Vikrant Shome

Bhandup West, Mumbai, India - 400078

Vikrant Shome photo

Vikrant Shome

Bhandup West, Mumbai, India - 400078.

4.8

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Overview

I am an MBA graduate from IIM Indore currently working as an Area Manager at Asian Paints. I have done my B-Tech from NIT Durgapur and interned at IIT Kharagpur.

I am offering tuitions on the below subjects which fall in my skillset.

1. Mathematics: Achieved 99%ile + in CAT Quant and LR/DI. Consistently scored 95+ in Maths all throughout my academic career

2. English: Achieved 97%ile in CAT. Consistently scored 90+ in English Language & Literature all throughout academic career. Winner of multiple Essay competitions.

3. Physics: Achieved the highest scores in Physics paper for JEE Mains and 90+ in all School examinations.

4. Computer Science: Trained in C, C++, Java. Achieved 95+ in Computer Sc & Applications all throughout academic career

Languages Spoken

Hindi Mother Tongue (Native)

English Proficient

Education

Indian Institute of Management Indore 2019

Master of Business Administration (M.B.A.)

Address

Bhandup West, Mumbai, India - 400078

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Demo Class

No

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Class 10 Tuition Overview

Class 10 Tuition

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 10 Tuition

2

Board

State, ICSE, International Baccalaureate, CBSE, IGCSE

IB Subjects taught

Physics, Computers, English, Mathematics

CBSE Subjects taught

Computer Practices, Mathematics, Elements of business, Accountancy, English

ICSE Subjects taught

Computer Application, English, Mathematics, Physics

IGCSE Subjects taught

Physics, Information Technology, Business Studies, Mathematics, Economics, English

Experience in School or College

2 years Maths/Quant training in Career Launcher coaching institute

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, English

Reviews

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FAQs

1. Which classes do you teach?

I teach Class 10 Tuition Class.

2. Do you provide a demo class?

No, I don't provide a demo class.

3. How many years of experience do you have?

I have been teaching for 2 years.

Answers by Vikrant Shome (2)

Answered on 24 Jun Tuition

or, x^{2} + y^{2} +z^{2} - xy - yz - zx = 0 multiplying LHS and RHS by (x + y + z) ( x + y + z)(x^{2} + y^{2} +z^{2} - xy - yz - zx) = 0 opening brackets, we get: x^{3} + y^{3} +z^{3} - 3xyz = 0 or, x^{3} + y^{3} +z^{3}= 3xyz. Hence the value = 3xyz
Answers 276 Comments
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Answered on 24 Jun Tuition

or, x^{2} + y^{2} +z^{2} - xy - yz - zx = 0 multiplying LHS and RHS by (x + y + z) ( x + y + z)(x^{2} + y^{2} +z^{2} - xy - yz - zx) = 0 opening brackets, we get: x^{3} + y^{3} +z^{3} - 3xyz = 0 or, x^{3} + y^{3} +z^{3}= 3xyz. Hence the value = 3xyz
Answers 276 Comments
Dislike Bookmark

Vikrant ShomeDirections

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Class 10 Tuition 4.8

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 10 Tuition

2

Board

State, ICSE, International Baccalaureate, CBSE, IGCSE

IB Subjects taught

Physics, Computers, English, Mathematics

CBSE Subjects taught

Computer Practices, Mathematics, Elements of business, Accountancy, English

ICSE Subjects taught

Computer Application, English, Mathematics, Physics

IGCSE Subjects taught

Physics, Information Technology, Business Studies, Mathematics, Economics, English

Experience in School or College

2 years Maths/Quant training in Career Launcher coaching institute

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics, English

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No Reviews yet! Be the first one to Review

Answers by Vikrant Shome (2)

Answered on 24 Jun Tuition

or, x^{2} + y^{2} +z^{2} - xy - yz - zx = 0 multiplying LHS and RHS by (x + y + z) ( x + y + z)(x^{2} + y^{2} +z^{2} - xy - yz - zx) = 0 opening brackets, we get: x^{3} + y^{3} +z^{3} - 3xyz = 0 or, x^{3} + y^{3} +z^{3}= 3xyz. Hence the value = 3xyz
Answers 276 Comments
Dislike Bookmark

Answered on 24 Jun Tuition

or, x^{2} + y^{2} +z^{2} - xy - yz - zx = 0 multiplying LHS and RHS by (x + y + z) ( x + y + z)(x^{2} + y^{2} +z^{2} - xy - yz - zx) = 0 opening brackets, we get: x^{3} + y^{3} +z^{3} - 3xyz = 0 or, x^{3} + y^{3} +z^{3}= 3xyz. Hence the value = 3xyz
Answers 276 Comments
Dislike Bookmark

Vikrant Shome conducts classes in Class 10 Tuition. Vikrant is located in Bhandup West, Mumbai. Vikrant takes Regular Classes- at his Home. He has 2 years of teaching experience . Vikrant has completed Master of Business Administration (M.B.A.) from Indian Institute of Management Indore in 2019. HeĀ is well versed in English and Hindi.

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