Andheri West, Mumbai Details verified of Dr Kumar Atmjeet✕
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University of Delhi 2014
Doctor of Philosophy (Ph.D.)
Andheri West, Mumbai, India - 400053
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Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
CBSE, State, ICSE
Subjects taught
Sanskrit, Science, Mathematics, Hindi
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
4
Board
ICSE, State, CBSE
Subjects taught
Mathematics, Science, Physics, Hindi
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
4
Board
ICSE, State, CBSE
Subjects taught
Science, Physics, Mathematics, Hindi
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Subjects taught
Mathematics
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Subjects taught
Mathematics
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Subjects taught
Mathematics
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Subjects taught
Physics
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Subjects taught
Physics
Answered on 14/01/2018 Learn CBSE - Class 9/Science
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Answers 11 
Comments Answered on 10/01/2018 Learn CBSE - Class 12/Physics
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Like 0 Answers 1 Comments Answered on 06/01/2018 Learn CBSE - Class 10/Mathematics
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Using Pythagoras’s theorem;
Third side = (29^2-21^2)^(1/2)=20
Now angle B=Cos^-1 (20/21)
I assume next part asks cos^2B+Sin^2B, this will be 1 irrespective of what is B
Second with - sign this equals to cos 2B or 2cos^2(B)-1
Just put cos B value here and get the result.
Like 0 Answers 11 Comments Answered on 06/01/2018 Learn CBSE - Class 10/Mathematics
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I don’t think the question is correct. The product of three roots = - Const/ coefficient of cubic term which yields -(-6)/2=3.
Since product of two roots is 3 then the third one has to be 1. But 1 can’t be the root of equation. As one can easily subtitle x=1 in the equation and see it doesn’t yield 0.
However, the question will be correct if one says that the product of two root is -3. Then answers would be -1, -2 and 3/2.
Like 0 Answers 3 Comments Ask a Question
Also have a look at
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
CBSE, State, ICSE
Subjects taught
Sanskrit, Science, Mathematics, Hindi
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
4
Board
ICSE, State, CBSE
Subjects taught
Mathematics, Science, Physics, Hindi
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
4
Board
ICSE, State, CBSE
Subjects taught
Science, Physics, Mathematics, Hindi
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Subjects taught
Mathematics
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Subjects taught
Mathematics
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Subjects taught
Mathematics
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Subjects taught
Physics
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Subjects taught
Physics
Answered on 14/01/2018 Learn CBSE - Class 9/Science
Ask a Question
Post a Lesson
Like 0 Answers 11 Comments Answered on 10/01/2018 Learn CBSE - Class 12/Physics
Ask a Question
Post a Lesson
Like 0 Answers 1 Comments Answered on 06/01/2018 Learn CBSE - Class 10/Mathematics
Ask a Question
Post a Lesson
Using Pythagoras’s theorem;
Third side = (29^2-21^2)^(1/2)=20
Now angle B=Cos^-1 (20/21)
I assume next part asks cos^2B+Sin^2B, this will be 1 irrespective of what is B
Second with - sign this equals to cos 2B or 2cos^2(B)-1
Just put cos B value here and get the result.
Like 0 Answers 11 Comments Answered on 06/01/2018 Learn CBSE - Class 10/Mathematics
Ask a Question
Post a Lesson
I don’t think the question is correct. The product of three roots = - Const/ coefficient of cubic term which yields -(-6)/2=3.
Since product of two roots is 3 then the third one has to be 1. But 1 can’t be the root of equation. As one can easily subtitle x=1 in the equation and see it doesn’t yield 0.
However, the question will be correct if one says that the product of two root is -3. Then answers would be -1, -2 and 3/2.
Like 0 Answers 3 Comments Ask a Question
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