Charishma Puli

# Charishma Puli

## English,maths,history, environmental science ,geography,civics,...

Powai Iit, Mumbai, India- 400076.

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## Overview

I can teach each and every topics very easily and make it stronger for the students.

## Languages Spoken

Hindi, English, English, Telugu

## Education

Bachelor of Technology (B.Tech.) from Chaitanaya bharthi institute of technology -Pursuing.

Powai Iit, Mumbai, India- 400076.

## SolidWorks Training Overview

SolidWorks Training

## Reviews

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## Answers by Charishma Puli (2)

"A block is kept on the floor of an elevator at rest. The elevator starts descending with an acceleration 12 m/s. Find the displacement of the block during the first 0.2 s after the start?" in   Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching, Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/Physics

As it is freely falling body because given acceleration a=12>g=9.8 m/s^2, so u=0,a=g=9.8,t=0.2s. So the required formula is s=ut+(1/2)at^2 => s=0.196 m is the required solution.

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"A block is kept on the floor of an elevator at rest. The elevator starts descending with an acceleration 12 m/s. Find the displacement of the block during the first 0.2 s after the start?" in   Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching, Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/Physics

As in the given question acceleration is more than the gravitational pull 'g' i.e., a=12>g=9.8m/s^2, this easily shows its a freely falling body such that a=g, u=0 (given at rest), t=0.2s (given). So substitute this in s=ut+(1/2)a(t^2) ad solve.

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|
0

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SolidWorks Training
Engineering Entrance Coaching classes

Engineering Entrance Exams

IIT JEE Coaching Classes

IITJEE Coaching

IIT JEE Mains Coaching, IIT JEE Advanced Coaching

Type of class

Regular Classes

Class Location

Online (video chat via skype, google hangout etc)

Years of Experience in Engineering Entrance Coaching classes

1

Teaching Experience in detail in Engineering Entrance Coaching classes

Worked in Toppr company. I'm good at teaching mathematics and can cover almost all topics in it.

Class I-V Tuition

Board

State, CBSE, ICSE

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

Experience in School or College

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Class IX-X Tuition

Board

ICSE, CBSE, State

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

Experience in School or College

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Class VI-VIII Tuition

Board

ICSE, CBSE, State

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

Experience in School or College

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

this is test message this is test message this is test message this is test message this is test message this is test message this is test message

No Reviews yet! Be the first one to Review

"A block is kept on the floor of an elevator at rest. The elevator starts descending with an acceleration 12 m/s. Find the displacement of the block during the first 0.2 s after the start?" in   Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching, Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/Physics

As it is freely falling body because given acceleration a=12>g=9.8 m/s^2, so u=0,a=g=9.8,t=0.2s. So the required formula is s=ut+(1/2)at^2 => s=0.196 m is the required solution.

0
|
0

"A block is kept on the floor of an elevator at rest. The elevator starts descending with an acceleration 12 m/s. Find the displacement of the block during the first 0.2 s after the start?" in   Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching, Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/Physics

As in the given question acceleration is more than the gravitational pull 'g' i.e., a=12>g=9.8m/s^2, this easily shows its a freely falling body such that a=g, u=0 (given at rest), t=0.2s (given). So substitute this in s=ut+(1/2)a(t^2) ad solve.

0
|
0

Charishma Puli describes herself as English,maths,history, environmental science ,geography,civics, untill primary level. She conducts classes in Class I-V Tuition, Class IX-X Tuition and Class VI-VIII Tuition. Charishma is located in Powai Iit, Mumbai. Charishma takes Online Classes- via online medium. She has 1 years of teaching experience . Charishma is pursuing Bachelor of Technology (B.Tech.) from Chaitanaya bharthi institute of technology. She is well versed in Hindi, English, English and Telugu.

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regular classes for the subject and test to be conducted to help students gain expertise of a subject

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