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Engineering Diploma Tuition > Engineering Diploma Tuition in Mumbai > Engineering Diploma Tuition in CBD Belapur > Ashish Anil Wadaye

Ashish Anil Wadaye Engineering Diploma Tuition trainer in Mumbai

Ashish Anil Wadaye

experience 4 yrs of Exp
locationImg CBD Belapur, Mumbai
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Ashish Anil Wadaye - Tutor

Travel Student's home
Home Tutor's home
I can teach maths, science and physics from standard 8th to 12th very easily and make it stronger for the students.I have 4+years of experience.

Languages Spoken

English

Marathi

Hindi

Education

University of Mumbai 2012

Bachelor of Engineering (B.E.)

Address

CBD Belapur, Mumbai, India - 410210

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Teaches

Engineering Diploma Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Engineering Diploma Tuition

4

Engineering Diploma Branch

Mechanical Engineering Diploma, Automobile Engineering Diploma

Mechanical Engineering Diploma Subject

Production Processes, Mechanical Engineering Drawing, Automobile Engineering

Automobile Engineering Diploma Subject

Mechanical Engineering Drawing, Hydraulics and Pnumatics, Theory of Machines & Mechanisms, Strength of Materials, Automibile Engines, Automobile Systems

Type of class

Regular Classes

Class strength catered to

Group Classes, One on one/ Private Tutions

Taught in School or College

Yes

Class 11 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

4

Board

CBSE, ISC/ICSE, State, International Baccalaureate, IGCSE

Subjects taught

Physics, Mathematics

Taught in School or College

Yes

Class 12 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

4

Board

CBSE, ISC/ICSE, State, International Baccalaureate, IGCSE

Subjects taught

Physics, Mathematics

Taught in School or College

Yes

Class 6 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

4

Board

ICSE, CBSE, State

Subjects taught

Mathematics, Physics, EVS, Science

Taught in School or College

Yes

Class 7 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

4

Board

ICSE, CBSE, State

Subjects taught

Science, EVS, Mathematics, Physics

Taught in School or College

Yes

Class 8 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

4

Board

ICSE, CBSE, State

Subjects taught

Physics, EVS, Mathematics, Science

Taught in School or College

Yes

Class 9 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

4

Board

CBSE, International Baccalaureate, ICSE, IGCSE, State

Subjects taught

Science, Mathematics, Physics, EVS

Taught in School or College

Yes

Class 10 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

4

Board

CBSE, International Baccalaureate, ICSE, IGCSE, State

Subjects taught

EVS, Physics, Science, Mathematics

Taught in School or College

Yes

Class I-V Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

4

Board

State, International Baccalaureate, CBSE, Cambridge Assessment International Education (CAIE), ICSE

Subjects taught

Science, Computer Science, Mathematics

Taught in School or College

Yes

Reviews

No Reviews yet!

Answers by Ashish Anil Wadaye

Answered on 07/12/2017 Learn CBSE - Class 9/Mathematics +1 Tuition/Class IX-X Tuition

Ask a Question Ask a Question

Post a Lesson Post a Lesson

The mean of 100 observations is 50. If one of the observation which was 50 is replaced by 150 then what... ...more
The mean of 100 observations is 50. If one of the observation which was 50 is replaced by 150 then what...

mean of 100 observations = 50 Hence sum of observations = 50 × 100 = 5000 Given that one observation 50 is replaced with 150, which means and additional 100 is added to the sum of the observations. So we need to add this 100 to the sum of the observations to get the correct sum of observations. Hence... ...more
mean of 100 observations = 50 Hence sum of observations = 50 × 100 = 5000 Given that one observation 50 is replaced with 150, which means and additional 100 is added to the sum of the observations. So we need to add this 100 to the sum of the observations to get the correct sum of observations. Hence correct sum of observations = 5000 + 100 = 5100 Therefore the correct mean or resulting mean = 5100 / 100 = 51
Answer Answers 49 Comments Comments
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Answered on 07/12/2017 Learn CBSE - Class 10/Mathematics +1 Tuition/Class IX-X Tuition

Ask a Question Ask a Question

Post a Lesson Post a Lesson

Consider ?ACB, right-angled at C, in which AB = 29 units, BC = 21 units and ?ABC = ?. Determine the values... ...more
Consider ?ACB, right-angled at C, in which AB = 29 units, BC = 21 units and ?ABC = ?. Determine the values...

In Δ ACB, we have AC = √(AB2 − BC2) = √ = √(8)(50) = √400 = 20 units So, sin θ = AC/AB = 20/29, cos θ = BC/AB = 21/29. Now, (i) cos2θ + sin2θ = (29/21)2 + 21/292 = (202 + 212)/292 = (400 + 441)/841 = 1, and (ii) cos2θ -- sin2θ = (29/21)2 -- 21/292 = / 292 = 41/841 ...more
In Δ ACB, we have AC = √(AB2 − BC2) = √[(29)2 − (21) 2) = √[(29 − 21)(29 + 21)] = √(8)(50) = √400 = 20 units So, sin θ = AC/AB = 20/29, cos θ = BC/AB = 21/29. Now, (i) cos2θ + sin2θ = (29/21)2 + 21/292 = (202 + 212)/292 = (400 + 441)/841 = 1, and (ii) cos2θ – sin2θ = (29/21)2 – 21/292 = [(21 + 20)(21 – 20)] / 292 = 41/841
Answer Answers 11 Comments Comments
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Answered on 07/12/2017 Learn CBSE - Class 9/Science +1 Tuition/Class IX-X Tuition

Ask a Question Ask a Question

Post a Lesson Post a Lesson

Why we can get the smell of perfume sitting several metres away?

When perfume is released from the bottle it quickly changes into vapour. ... The kinetic energy of the gas molecules is high and the rate of diffusion is high .Hence, we can get the smell of perfume sitting several meters away.
Answer Answers 16 Comments Comments
Dislike Bookmark

Answered on 07/12/2017 Learn CBSE - Class 9/Science +1 Tuition/Class IX-X Tuition

Ask a Question Ask a Question

Post a Lesson Post a Lesson

Explain pure substance.

The term has a specific meaning in chemistry. A pure substance is a sample of matter with both definite and constant composition with distinct chemical properties. Ex. water diamond gold table salt (sodium chloride) ethanol brass bronze saline solution
Answer Answers 13 Comments Comments
Dislike Bookmark

Answered on 07/12/2017 Learn CBSE - Class 9/Science +1 Tuition/Class IX-X Tuition

Ask a Question Ask a Question

Post a Lesson Post a Lesson

What do you think would be the observation if the ? -particle scattering experiment is carried out using... ...more
What do you think would be the observation if the ? -particle scattering experiment is carried out using...

A major fraction of the alpha particles bombarded towards the gold foil through it without any deflections and hence most space in atom is empty some a-particles deflects a little so +ve charge is not uniformly distributed it is in a small volume very few are deflected back and even fewer particles... ...more
A major fraction of the alpha particles bombarded towards the gold foil through it without any deflections and hence most space in atom is empty some a-particles deflects a little so +ve charge is not uniformly distributed it is in a small volume very few are deflected back and even fewer particles have 180 degree deflection so +vely charged particles in an atom is very small in volume in an atom
Answer Answers 8 Comments Comments
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Teaches

Engineering Diploma Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Engineering Diploma Tuition

4

Engineering Diploma Branch

Mechanical Engineering Diploma, Automobile Engineering Diploma

Mechanical Engineering Diploma Subject

Production Processes, Mechanical Engineering Drawing, Automobile Engineering

Automobile Engineering Diploma Subject

Mechanical Engineering Drawing, Hydraulics and Pnumatics, Theory of Machines & Mechanisms, Strength of Materials, Automibile Engines, Automobile Systems

Type of class

Regular Classes

Class strength catered to

Group Classes, One on one/ Private Tutions

Taught in School or College

Yes

Class 11 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

4

Board

CBSE, ISC/ICSE, State, International Baccalaureate, IGCSE

Subjects taught

Physics, Mathematics

Taught in School or College

Yes

Class 12 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

4

Board

CBSE, ISC/ICSE, State, International Baccalaureate, IGCSE

Subjects taught

Physics, Mathematics

Taught in School or College

Yes

Class 6 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

4

Board

ICSE, CBSE, State

Subjects taught

Mathematics, Physics, EVS, Science

Taught in School or College

Yes

Class 7 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

4

Board

ICSE, CBSE, State

Subjects taught

Science, EVS, Mathematics, Physics

Taught in School or College

Yes

Class 8 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

4

Board

ICSE, CBSE, State

Subjects taught

Physics, EVS, Mathematics, Science

Taught in School or College

Yes

Class 9 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

4

Board

CBSE, International Baccalaureate, ICSE, IGCSE, State

Subjects taught

Science, Mathematics, Physics, EVS

Taught in School or College

Yes

Class 10 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

4

Board

CBSE, International Baccalaureate, ICSE, IGCSE, State

Subjects taught

EVS, Physics, Science, Mathematics

Taught in School or College

Yes

Class I-V Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

4

Board

State, International Baccalaureate, CBSE, Cambridge Assessment International Education (CAIE), ICSE

Subjects taught

Science, Computer Science, Mathematics

Taught in School or College

Yes

No Reviews yet!

Answers by Ashish Anil Wadaye

Answered on 07/12/2017 Learn CBSE - Class 9/Mathematics +1 Tuition/Class IX-X Tuition

Ask a Question Ask a Question

Post a Lesson Post a Lesson

The mean of 100 observations is 50. If one of the observation which was 50 is replaced by 150 then what... ...more
The mean of 100 observations is 50. If one of the observation which was 50 is replaced by 150 then what...

mean of 100 observations = 50 Hence sum of observations = 50 × 100 = 5000 Given that one observation 50 is replaced with 150, which means and additional 100 is added to the sum of the observations. So we need to add this 100 to the sum of the observations to get the correct sum of observations. Hence... ...more
mean of 100 observations = 50 Hence sum of observations = 50 × 100 = 5000 Given that one observation 50 is replaced with 150, which means and additional 100 is added to the sum of the observations. So we need to add this 100 to the sum of the observations to get the correct sum of observations. Hence correct sum of observations = 5000 + 100 = 5100 Therefore the correct mean or resulting mean = 5100 / 100 = 51
Answer Answers 49 Comments Comments
Dislike Bookmark

Answered on 07/12/2017 Learn CBSE - Class 10/Mathematics +1 Tuition/Class IX-X Tuition

Ask a Question Ask a Question

Post a Lesson Post a Lesson

Consider ?ACB, right-angled at C, in which AB = 29 units, BC = 21 units and ?ABC = ?. Determine the values... ...more
Consider ?ACB, right-angled at C, in which AB = 29 units, BC = 21 units and ?ABC = ?. Determine the values...

In Δ ACB, we have AC = √(AB2 − BC2) = √ = √(8)(50) = √400 = 20 units So, sin θ = AC/AB = 20/29, cos θ = BC/AB = 21/29. Now, (i) cos2θ + sin2θ = (29/21)2 + 21/292 = (202 + 212)/292 = (400 + 441)/841 = 1, and (ii) cos2θ -- sin2θ = (29/21)2 -- 21/292 = / 292 = 41/841 ...more
In Δ ACB, we have AC = √(AB2 − BC2) = √[(29)2 − (21) 2) = √[(29 − 21)(29 + 21)] = √(8)(50) = √400 = 20 units So, sin θ = AC/AB = 20/29, cos θ = BC/AB = 21/29. Now, (i) cos2θ + sin2θ = (29/21)2 + 21/292 = (202 + 212)/292 = (400 + 441)/841 = 1, and (ii) cos2θ – sin2θ = (29/21)2 – 21/292 = [(21 + 20)(21 – 20)] / 292 = 41/841
Answer Answers 11 Comments Comments
Dislike Bookmark

Answered on 07/12/2017 Learn CBSE - Class 9/Science +1 Tuition/Class IX-X Tuition

Ask a Question Ask a Question

Post a Lesson Post a Lesson

Why we can get the smell of perfume sitting several metres away?

When perfume is released from the bottle it quickly changes into vapour. ... The kinetic energy of the gas molecules is high and the rate of diffusion is high .Hence, we can get the smell of perfume sitting several meters away.
Answer Answers 16 Comments Comments
Dislike Bookmark

Answered on 07/12/2017 Learn CBSE - Class 9/Science +1 Tuition/Class IX-X Tuition

Ask a Question Ask a Question

Post a Lesson Post a Lesson

Explain pure substance.

The term has a specific meaning in chemistry. A pure substance is a sample of matter with both definite and constant composition with distinct chemical properties. Ex. water diamond gold table salt (sodium chloride) ethanol brass bronze saline solution
Answer Answers 13 Comments Comments
Dislike Bookmark

Answered on 07/12/2017 Learn CBSE - Class 9/Science +1 Tuition/Class IX-X Tuition

Ask a Question Ask a Question

Post a Lesson Post a Lesson

What do you think would be the observation if the ? -particle scattering experiment is carried out using... ...more
What do you think would be the observation if the ? -particle scattering experiment is carried out using...

A major fraction of the alpha particles bombarded towards the gold foil through it without any deflections and hence most space in atom is empty some a-particles deflects a little so +ve charge is not uniformly distributed it is in a small volume very few are deflected back and even fewer particles... ...more
A major fraction of the alpha particles bombarded towards the gold foil through it without any deflections and hence most space in atom is empty some a-particles deflects a little so +ve charge is not uniformly distributed it is in a small volume very few are deflected back and even fewer particles have 180 degree deflection so +vely charged particles in an atom is very small in volume in an atom
Answer Answers 8 Comments Comments
Dislike Bookmark
x

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