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Ashish Anil Wadaye Engineering Diploma Tuition trainer in Mumbai

Ashish Anil Wadaye

locationImg CBD Belapur, Mumbai
4 yrs of Exp
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I can teach maths, science and physics from standard 8th to 12th very easily and make it stronger for the students.I have 4+years of experience.

Languages Spoken

English

Marathi

Hindi

Education

University of Mumbai 2012

Bachelor of Engineering (B.E.)

Address

CBD Belapur, Mumbai, India - 410210

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Teaches

Engineering Diploma Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Engineering Diploma Tuition

4

Engineering Diploma Branch

Mechanical Engineering Diploma, Automobile Engineering Diploma

Mechanical Engineering Diploma Subject

Production Processes, Automobile Engineering, Mechanical Engineering Drawing

Automobile Engineering Diploma Subject

Mechanical Engineering Drawing, Automobile Systems, Hydraulics and Pnumatics, Theory of Machines & Mechanisms, Strength of Materials, Automibile Engines

Type of class

Regular Classes

Class strength catered to

Group Classes, One on one/ Private Tutions

Taught in School or College

Yes

Class 11 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

4

Board

IGCSE, International Baccalaureate, CBSE, ISC/ICSE, State

Subjects taught

Mathematics, Physics

Taught in School or College

Yes

Class 12 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

4

Board

IGCSE, International Baccalaureate, CBSE, ISC/ICSE, State

Subjects taught

Physics, Mathematics

Taught in School or College

Yes

Class 6 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

4

Board

State, CBSE, ICSE

Subjects taught

EVS, Mathematics, Science, Physics

Taught in School or College

Yes

Class 7 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

4

Board

State, CBSE, ICSE

Subjects taught

Science, Mathematics, EVS, Physics

Taught in School or College

Yes

Class 8 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

4

Board

State, CBSE, ICSE

Subjects taught

Mathematics, Science, EVS, Physics

Taught in School or College

Yes

Class 9 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

4

Board

State, IGCSE, CBSE, ICSE, International Baccalaureate

Subjects taught

EVS, Science, Physics, Mathematics

Taught in School or College

Yes

Class 10 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

4

Board

State, IGCSE, CBSE, ICSE, International Baccalaureate

Subjects taught

Physics, EVS, Mathematics, Science

Taught in School or College

Yes

Class I-V Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

4

Board

Cambridge Assessment International Education (CAIE), CBSE, ICSE, State, International Baccalaureate

Subjects taught

Computer Science, Mathematics, Science

Taught in School or College

Yes

Reviews

No Reviews yet!

Answers by Ashish Anil Wadaye

Answered on 07/12/2017 Learn CBSE - Class 9/Mathematics +1

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Post a Lesson

mean of 100 observations = 50 Hence sum of observations = 50 × 100 = 5000 Given that one observation 50 is replaced with 150, which means and additional 100 is added to the sum of the observations. So we need to add this 100 to the sum of the observations to get the correct sum of observations. Hence... ...more
mean of 100 observations = 50 Hence sum of observations = 50 × 100 = 5000 Given that one observation 50 is replaced with 150, which means and additional 100 is added to the sum of the observations. So we need to add this 100 to the sum of the observations to get the correct sum of observations. Hence correct sum of observations = 5000 + 100 = 5100 Therefore the correct mean or resulting mean = 5100 / 100 = 51
Answers 49 Comments
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Answered on 07/12/2017 Learn CBSE - Class 10/Mathematics +1

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In Δ ACB, we have AC = √(AB2 − BC2) = √ = √(8)(50) = √400 = 20 units So, sin θ = AC/AB = 20/29, cos θ = BC/AB = 21/29. Now, (i) cos2θ + sin2θ = (29/21)2 + 21/292 = (202 + 212)/292 = (400 + 441)/841 = 1, and (ii) cos2θ -- sin2θ = (29/21)2 -- 21/292 = / 292 = 41/841 ...more
In Δ ACB, we have AC = √(AB2 − BC2) = √[(29)2 − (21) 2) = √[(29 − 21)(29 + 21)] = √(8)(50) = √400 = 20 units So, sin θ = AC/AB = 20/29, cos θ = BC/AB = 21/29. Now, (i) cos2θ + sin2θ = (29/21)2 + 21/292 = (202 + 212)/292 = (400 + 441)/841 = 1, and (ii) cos2θ – sin2θ = (29/21)2 – 21/292 = [(21 + 20)(21 – 20)] / 292 = 41/841
Answers 11 Comments
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Answered on 07/12/2017 Learn CBSE - Class 9/Science +1

Ask a Question

Post a Lesson

When perfume is released from the bottle it quickly changes into vapour. ... The kinetic energy of the gas molecules is high and the rate of diffusion is high .Hence, we can get the smell of perfume sitting several meters away.
Answers 16 Comments
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Answered on 07/12/2017 Learn CBSE - Class 9/Science +1

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Post a Lesson

The term has a specific meaning in chemistry. A pure substance is a sample of matter with both definite and constant composition with distinct chemical properties. Ex. water diamond gold table salt (sodium chloride) ethanol brass bronze saline solution
Answers 13 Comments
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Answered on 07/12/2017 Learn CBSE - Class 9/Science +1

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Post a Lesson

A major fraction of the alpha particles bombarded towards the gold foil through it without any deflections and hence most space in atom is empty some a-particles deflects a little so +ve charge is not uniformly distributed it is in a small volume very few are deflected back and even fewer particles... ...more
A major fraction of the alpha particles bombarded towards the gold foil through it without any deflections and hence most space in atom is empty some a-particles deflects a little so +ve charge is not uniformly distributed it is in a small volume very few are deflected back and even fewer particles have 180 degree deflection so +vely charged particles in an atom is very small in volume in an atom
Answers 8 Comments
Dislike Bookmark
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Please select a Tag

Teaches

Engineering Diploma Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Engineering Diploma Tuition

4

Engineering Diploma Branch

Mechanical Engineering Diploma, Automobile Engineering Diploma

Mechanical Engineering Diploma Subject

Production Processes, Automobile Engineering, Mechanical Engineering Drawing

Automobile Engineering Diploma Subject

Mechanical Engineering Drawing, Automobile Systems, Hydraulics and Pnumatics, Theory of Machines & Mechanisms, Strength of Materials, Automibile Engines

Type of class

Regular Classes

Class strength catered to

Group Classes, One on one/ Private Tutions

Taught in School or College

Yes

Class 11 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

4

Board

IGCSE, International Baccalaureate, CBSE, ISC/ICSE, State

Subjects taught

Mathematics, Physics

Taught in School or College

Yes

Class 12 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

4

Board

IGCSE, International Baccalaureate, CBSE, ISC/ICSE, State

Subjects taught

Physics, Mathematics

Taught in School or College

Yes

Class 6 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

4

Board

State, CBSE, ICSE

Subjects taught

EVS, Mathematics, Science, Physics

Taught in School or College

Yes

Class 7 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

4

Board

State, CBSE, ICSE

Subjects taught

Science, Mathematics, EVS, Physics

Taught in School or College

Yes

Class 8 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

4

Board

State, CBSE, ICSE

Subjects taught

Mathematics, Science, EVS, Physics

Taught in School or College

Yes

Class 9 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

4

Board

State, IGCSE, CBSE, ICSE, International Baccalaureate

Subjects taught

EVS, Science, Physics, Mathematics

Taught in School or College

Yes

Class 10 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

4

Board

State, IGCSE, CBSE, ICSE, International Baccalaureate

Subjects taught

Physics, EVS, Mathematics, Science

Taught in School or College

Yes

Class I-V Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

4

Board

Cambridge Assessment International Education (CAIE), CBSE, ICSE, State, International Baccalaureate

Subjects taught

Computer Science, Mathematics, Science

Taught in School or College

Yes

No Reviews yet!

Answers by Ashish Anil Wadaye

Answered on 07/12/2017 Learn CBSE - Class 9/Mathematics +1

Ask a Question

Post a Lesson

mean of 100 observations = 50 Hence sum of observations = 50 × 100 = 5000 Given that one observation 50 is replaced with 150, which means and additional 100 is added to the sum of the observations. So we need to add this 100 to the sum of the observations to get the correct sum of observations. Hence... ...more
mean of 100 observations = 50 Hence sum of observations = 50 × 100 = 5000 Given that one observation 50 is replaced with 150, which means and additional 100 is added to the sum of the observations. So we need to add this 100 to the sum of the observations to get the correct sum of observations. Hence correct sum of observations = 5000 + 100 = 5100 Therefore the correct mean or resulting mean = 5100 / 100 = 51
Answers 49 Comments
Dislike Bookmark

Answered on 07/12/2017 Learn CBSE - Class 10/Mathematics +1

Ask a Question

Post a Lesson

In Δ ACB, we have AC = √(AB2 − BC2) = √ = √(8)(50) = √400 = 20 units So, sin θ = AC/AB = 20/29, cos θ = BC/AB = 21/29. Now, (i) cos2θ + sin2θ = (29/21)2 + 21/292 = (202 + 212)/292 = (400 + 441)/841 = 1, and (ii) cos2θ -- sin2θ = (29/21)2 -- 21/292 = / 292 = 41/841 ...more
In Δ ACB, we have AC = √(AB2 − BC2) = √[(29)2 − (21) 2) = √[(29 − 21)(29 + 21)] = √(8)(50) = √400 = 20 units So, sin θ = AC/AB = 20/29, cos θ = BC/AB = 21/29. Now, (i) cos2θ + sin2θ = (29/21)2 + 21/292 = (202 + 212)/292 = (400 + 441)/841 = 1, and (ii) cos2θ – sin2θ = (29/21)2 – 21/292 = [(21 + 20)(21 – 20)] / 292 = 41/841
Answers 11 Comments
Dislike Bookmark

Answered on 07/12/2017 Learn CBSE - Class 9/Science +1

Ask a Question

Post a Lesson

When perfume is released from the bottle it quickly changes into vapour. ... The kinetic energy of the gas molecules is high and the rate of diffusion is high .Hence, we can get the smell of perfume sitting several meters away.
Answers 16 Comments
Dislike Bookmark

Answered on 07/12/2017 Learn CBSE - Class 9/Science +1

Ask a Question

Post a Lesson

The term has a specific meaning in chemistry. A pure substance is a sample of matter with both definite and constant composition with distinct chemical properties. Ex. water diamond gold table salt (sodium chloride) ethanol brass bronze saline solution
Answers 13 Comments
Dislike Bookmark

Answered on 07/12/2017 Learn CBSE - Class 9/Science +1

Ask a Question

Post a Lesson

A major fraction of the alpha particles bombarded towards the gold foil through it without any deflections and hence most space in atom is empty some a-particles deflects a little so +ve charge is not uniformly distributed it is in a small volume very few are deflected back and even fewer particles... ...more
A major fraction of the alpha particles bombarded towards the gold foil through it without any deflections and hence most space in atom is empty some a-particles deflects a little so +ve charge is not uniformly distributed it is in a small volume very few are deflected back and even fewer particles have 180 degree deflection so +vely charged particles in an atom is very small in volume in an atom
Answers 8 Comments
Dislike Bookmark
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Please enter your Question

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