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At present , the ratio between the ages of P and Q is 5:7 respectively. If the difference between Q's present age and P's age after 6years is 2 ,what is the total age of P's and Q's present age

 

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Let the age of P =5x and age of Q=7x Age of P after 6 years =(5x+6) 7x-(5x+6)=2 7x-5x-6=2 2x-6=2 2x=2+6 2x=8 X=8/2=4 P=5x=5*4=20 years Q=7x=7*4=28 years P+Q=20+28=48
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Let's assume P and Q's present ages are pp and qq So p:q=5:7p:q=5:7 ie p/q=5/7p/q=5/7 ie p=5/7×qp=5/7×q As per second statement q−(p+6)=2q−(p+6)=2 {Replace p's value from eqn 1 into eqn 2} q−(5/7×q+6)=2q−(5/7×q+6)=2 ie 2/7×q=82/7×q=8 ie...
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Let's assume P and Q's present ages are pp and qq

So p:q=5:7p:q=5:7 ie p/q=5/7p/q=5/7 ie p=5/7×qp=5/7×q

As per second statement

q(p+6)=2q−(p+6)=2

{Replace p's value from eqn 1 into eqn 2}

q(5/7×q+6)=2q−(5/7×q+6)=2

ie 2/7×q=82/7×q=8

ie q=8×7/2=28q=8×7/2=28

So p=20p=20

So total of their present age is 48.

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Sum of ages =10+14 24
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48 years
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Given , the ratio between the ages of P and Q is 5:7 respectively.=7x-(5x+6x)=2 =X=4 ,sum of their present age =5x+7x =12x =12×4=48 years
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Total age of p is 5 year Present age of q is 7 year
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Present ages of P and Q = 5x and 7x respectively. ATP : 7x - (5x + 6) = 2 7x - 5x - 6 = 2 2x = 2 + 6 x = 8 ÷ 2 x = 4 Total age = 12x = 12 x 4 = 48
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Maths and science teacher with 3 years of experience.

Since, ratio of P's and Q's age is 5:7 We can assume that present age of P and Q are 5x and 7x respectively. Now, according to question : the difference between Q's present age and P's age after 6years is 2 i.e. 7x- (5x+6)=2 i.e. 7x- 5x- 6=2 2x = 2+6 2x= 8 x = 8/2 ...
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Since, ratio of P's and Q's age is 5:7 We can assume that present age of P and Q are 5x and 7x respectively. Now, according to question : the difference between Q's present age and P's age after 6years is 2 i.e. 7x- (5x+6)=2 i.e. 7x- 5x- 6=2 2x = 2+6 2x= 8 x = 8/2 *x=4* So, P's present age = 5x=5×4=20 years And Q's present age = 7x =7×4=28 years Therefore , total of P's and Q's present age = 20 + 28 = " 48 years". read less
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