At present , the ratio between the ages of P and Q is 5:7 respectively. If the difference between Q's present age and P's age after 6years is 2 ,what is the total age of P's and Q's present age

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Let the age of P =5x and age of Q=7x Age of P after 6 years =(5x+6) 7x-(5x+6)=2 7x-5x-6=2 2x-6=2 2x=2+6 2x=8 X=8/2=4 P=5x=5*4=20 years Q=7x=7*4=28 years P+Q=20+28=48
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Given , the ratio between the ages of P and Q is 5:7 respectively.=7x-(5x+6x)=2 =X=4 ,sum of their present age =5x+7x =12x =12×4=48 years
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Let's assume P and Q's present ages are pp and qq So p:q=5:7p:q=5:7 ie p/q=5/7p/q=5/7 ie p=5/7×qp=5/7×q As per second statement q−(p+6)=2q−(p+6)=2 {Replace p's value from eqn 1 into eqn 2} q−(5/7×q+6)=2q−(5/7×q+6)=2 ie 2/7×q=82/7×q=8 ie...
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Let's assume P and Q's present ages areppandqq Sop:q=5:7p:q=5:7iep/q=5/7p/q=5/7iep=5/7×qp=5/7×q As per second statement q−(p+6)=2q−(p+6)=2 {Replace p's value from eqn 1 into eqn 2} q−(5/7×q+6)=2q−(5/7×q+6)=2 ie2/7×q=82/7×q=8 ieq=8×7/2=28q=8×7/2=28 Sop=20p=20 Sototal of their present age is 48. read less
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P's present age -20 and Q's present age -28, Total age of P's and Q's present age is - 20+28 = 48.
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I'm a tutor with ten years of experience

48 years
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Mathematics teacher with 20 years of experience

Sum of ages =10+14 24
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Total age of p is 5 year Present age of q is 7 year
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