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Post a LessonAnswered on 07 Mar Learn CBSE/Class 7/Maths/Perimeter and Area

Sadika

To find the area of a square with a side length of 16.5 decameters (dam) in square meters: Area = side^2 = (16.5 dam)^2 = 16.5^2 dam^2 = 272.25 m^2 So, the area of the square is 272.25 square meters. read more

To find the area of a square with a side length of 16.5 decameters (dam) in square meters:

Area = side^2 = (16.5 dam)^2 = 16.5^2 dam^2 = 272.25 m^2

So, the area of the square is 272.25 square meters.

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Answers 1 Comments Answered on 07 Mar Learn CBSE/Class 7/Maths/Perimeter and Area

Sadika

To find the area of a rectangular field in acres with sides of 200 meters and 125 meters: Then, we convert the area from square meters to acres. Since 1 acre is equal to 4046.86 square meters: So, the area of the rectangular field is approximately 6.18 acres. read more

To find the area of a rectangular field in acres with sides of 200 meters and 125 meters:

Then, we convert the area from square meters to acres. Since 1 acre is equal to 4046.86 square meters:

So, the area of the rectangular field is approximately 6.18 acres.

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Answers 1 Comments Answered on 07 Mar Learn CBSE/Class 7/Maths/Perimeter and Area

Sadika

To find the cost of painting the wall, we first need to calculate the area of the wall excluding the area covered by the door, and then multiply it by the cost per square meter. Calculate the cost: Cost per square meter = Rs 2.50Total cost = Area of the wall excluding the door × Cost per square... read more

To find the cost of painting the wall, we first need to calculate the area of the wall excluding the area covered by the door, and then multiply it by the cost per square meter.

**Calculate the cost**:

- Cost per square meter = Rs 2.50

Total cost = Area of the wall excluding the door × Cost per square meter

So, the cost of painting the wall is Rs 235.

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Answers 1 Comments Answered on 07 Mar Learn CBSE/Class 7/Maths/Perimeter and Area

Sadika

First, let's find the perimeter of the rectangle, which is equal to the length of the wire: Perimeter of the rectangle = 2 * (length + breadth) = 2 * (40 cm + 22 cm) = 2 * 62 cm = 124 cm Since the wire is bent to form a square, the perimeter of the square will also be 124 cm. Now, let's find... read more

First, let's find the perimeter of the rectangle, which is equal to the length of the wire:

Perimeter of the rectangle = 2 * (length + breadth) = 2 * (40 cm + 22 cm) = 2 * 62 cm = 124 cm

Since the wire is bent to form a square, the perimeter of the square will also be 124 cm.

Now, let's find the measure of each side of the square:

Perimeter of the square = 4 * side

So, 4 * side = 124 cm

Dividing both sides by 4:

side = 124 cm / 4 = 31 cm

Each side of the square will measure 31 cm.

Now, let's find the area enclosed by each shape:

Area of the rectangle = length * breadth = 40 cm * 22 cm = 880 cm²

Area of the square = side * side = 31 cm * 31 cm = 961 cm²

Comparing the two areas, we find that the square encloses more area than the rectangle.

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Answers 1 Comments Answered on 07 Mar Learn CBSE/Class 7/Maths/Perimeter and Area

Sadika

To find the total area of glass required for 12 panes, we first find the area of one pane and then multiply it by the number of panes. Area of one pane = Length × Breadth = 25 cm × 16 cm = 400 cm² Now, we have to convert the area from square centimeters to square meters,... read more

To find the total area of glass required for 12 panes, we first find the area of one pane and then multiply it by the number of panes.

Area of one pane = Length × Breadth = 25 cm × 16 cm = 400 cm²

Now, we have to convert the area from square centimeters to square meters, as 1 square meter equals 10,000 square centimeters.

So, 400 cm² = 400 / 10,000 m² ≈ 0.04 m²

Therefore, the area of one pane is approximately 0.04 square meters.

To find the total area required for 12 panes, we multiply the area of one pane by the number of panes:

Total area = Area of one pane × Number of panes = 0.04 m² × 12 = 0.48 m²

So, 0.48 square meters of glass will be required for 12 panes.

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