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Post a LessonAnswered on 16 Sep Learn CBSE/Class 9/Mathematics/Geometry/Triangles
Debojit Sarkar
Be the better version of yourself
Let ∠C= x°,
∴ ∠B - x°=18°
⇒ ∠B = 18°+x° ......(i)
Again, ∠A - (18°+x°)= 33°
⇒∠A = 33°+18°+x° ......(ii)
And ∠A+∠B+∠C =180°
⇒51°+18°+3x°=180°
⇒3x°=(180°-69°)
⇒x°=37°
∴ ∠C=37°, ∠B= (37+18)=55°, ∠A=(55+33)= 88° [Ans.]
read lessAnswered on 15 Sep Learn CBSE/Class 9/Mathematics/Geometry/Triangles
Debojit Sarkar
Be the better version of yourself
Diagonals of a rectangle bisect each other and they are equal in length
∴Δ AOB will be an isosceles triangle with AO=BO
In ΔAOB,
∠AOB = ∠COD .............[ Vertically opposite angles]
∠OAB=∠OBA ................[ Angle opposite to equal sides]
∴∠AOB +2∠OAB = 180°
⇒ 78º + 2∠OAB = 180°
⇒ ∠OAB = 51° [ Ans.]
read lessAnswered on 15 Sep Learn CBSE/Class 9/Mathematics/Geometry/Triangles
Debojit Sarkar
Be the better version of yourself
Answered on 15 Sep Learn CBSE/Class 9/Mathematics/Geometry/Quadrilaterals
Debojit Sarkar
Be the better version of yourself
Answered on 15 Sep Learn CBSE/Class 9/Mathematics/Geometry/Quadrilaterals
Debojit Sarkar
Be the better version of yourself
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