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Maths relates to CBSE/Class 6

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1
Deepashree Class 6 Tuition trainer in Bangalore Featured
Basaveshwara Nagar, Bangalore
Super Tutor
12 yrs of Exp
500per hour
Classes: Class 6 Tuition, Class 9 Tuition and more.

I have 3 years of experience teaching for 6th standard students in a reputed school am very much fond of solving problems and explaining experiments...

2
Richa B. Class 6 Tuition trainer in Bangalore Featured
Agara Village, Bangalore
Super Tutor
6 yrs of Exp
700per hour
Classes: Class 6 Tuition, Hindi Language and more.

I am an experienced qualified teacher with over 7 years of teaching. I have been Certified by Urban Pro too. Students show good improvement from CBSE,...

3
Purnima Joshi Class 6 Tuition trainer in Nainital Featured
Haldwani, Nainital
Super Tutor
20 yrs of Exp
500per hour
Classes: Class 6 Tuition, Class 7 Tuition

I have more than 30 years experience of teaching in a convent school and almost two years experience of online teaching.Teaching is my passion.I am...

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Palak K. Class 6 Tuition trainer in Kolkata Featured
Tollygunge, Kolkata
Super Tutor
5 yrs of Exp
250per hour
Classes: Class 6 Tuition, Engineering Diploma Tuition and more.

I am Palak Maitra, Math. Tutor. I have a degree in Mechanical Engineering. I have 11 years of online tutoring experience on Math. Up to class 12....

5
Nagasundari Class 6 Tuition trainer in Madurai South Featured
Nethaji Nagar, Madurai South
Super Tutor
9 yrs of Exp
160per hour
Classes: Class 6 Tuition, Class I-V Tuition and more.

2 years of teaching in online.

6
Sanjukta I. Class 6 Tuition trainer in Kolkata Featured
VIP RD, Kolkata
Super Tutor
7 yrs of Exp
300per hour
Classes: Class 6 Tuition, Class 8 Tuition and more.

It was fabulous

7
Amsumathi K Class 6 Tuition trainer in Taliparamba Featured
Kunhimangalam, Taliparamba
Super Tutor
9 yrs of Exp
300per hour
Classes: Class 6 Tuition, Nursery-KG Tuition and more.

I'm a primary teacher.I am giving online tuition since 2020. I have a degree in M.A.malayalam with TTC .I have 9 years of teaching experience in CBSE...

8
Akshay Aggarwal Class 6 Tuition trainer in Delhi Featured
Badarpur, Delhi
Super Tutor
8 yrs of Exp
750per hour
Classes: Class 6 Tuition, Class 8 Tuition and more.

I am an experienced tutor with nine years of teaching under my belt. I hold a BSc degree in geography. My passion for teaching has always been my...

9
Deepak Joshi Class 6 Tuition trainer in Bangalore Featured
Ashok Nagar D' Souza Layout, Bangalore
Super Tutor
10 yrs of Exp
800per hour
Classes: Class 6 Tuition, Class 11 Tuition and more.

Ph.D candidate with over 10 years of teaching exp. (7 years at BYJU's and 3 years at DPS Gurgaon). Specialized in IB, IGCSE, CBSE & ICSE curric...

10
Shivam Pandey Class 6 Tuition trainer in Delhi Featured
Laxmi Nagar Vishwakarma Park, Delhi
Super Tutor
6 yrs of Exp
300per hour
Classes: Class 6 Tuition, Class 11 Tuition and more.

I am a dedicated Mathematics educator with 7+ years of experience teaching students from Grade 7 to 10 across various national and international boards...

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    Sindhu attended Class 6 Tuition

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    Sindhu attended Class 6 Tuition

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Answered on 24/02/2024 Learn CBSE/Class 6/Maths/Playing With Numbers

Sadika

The sum of any two even numbers is always an even number. Let's denote two even numbers as 2n2n and 2m2m, where nn and mm are integers. The sum of these two even numbers is: 2n+2m=2(n+m)2n+2m=2(n+m) Since nn and mm are integers, n+mn+m is also an integer. Therefore, the sum 2(n+m)2(n+m) is an even... read more

The sum of any two even numbers is always an even number.

Let's denote two even numbers as 2n2n and 2m2m, where nn and mm are integers.

The sum of these two even numbers is: 2n+2m=2(n+m)2n+2m=2(n+m)

Since nn and mm are integers, n+mn+m is also an integer. Therefore, the sum 2(n+m)2(n+m) is an even number because it is divisible by 22. Thus, the sum of any two even numbers is an even number.

 
 
 
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Answered on 24/02/2024 Learn CBSE/Class 6/Maths/Playing With Numbers

Sadika

To find the highest common factor (HCF) of two numbers, we find the largest number that divides both of them without leaving a remainder. For the numbers 5 and 7, the only common factor they share is 1, since both 5 and 7 are prime numbers. Since there are no other common factors besides 1, the HCF... read more

To find the highest common factor (HCF) of two numbers, we find the largest number that divides both of them without leaving a remainder.

For the numbers 5 and 7, the only common factor they share is 1, since both 5 and 7 are prime numbers. Since there are no other common factors besides 1, the HCF of 5 and 7 is 1.

 
 
 
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Answered on 24/02/2024 Learn CBSE/Class 6/Maths/Playing With Numbers

Sadika

To find the factors of a number, you need to identify all the numbers that divide the given number evenly, including 1 and the number itself. Let's find the factors for each: (a) Factors of 12: 1, 2, 3, 4, 6, 12 (b) Factors of 18: 1, 2, 3, 6, 9, 18 These are all the possible factors of 12 and 18. ... read more

To find the factors of a number, you need to identify all the numbers that divide the given number evenly, including 1 and the number itself.

Let's find the factors for each:

(a) Factors of 12: 1, 2, 3, 4, 6, 12

(b) Factors of 18: 1, 2, 3, 6, 9, 18

These are all the possible factors of 12 and 18.

 
 
 
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Answered on 24/02/2024 Learn CBSE/Class 6/Maths/Playing With Numbers

Sadika

The only even prime number is 2. It's the only even number that is prime because by definition, an even number is divisible by 2 and no other even number (except for -2) can be prime because they are all divisible by 2 and thus not satisfying the definition of a prime number. So, the number which... read more

The only even prime number is 2. It's the only even number that is prime because by definition, an even number is divisible by 2 and no other even number (except for -2) can be prime because they are all divisible by 2 and thus not satisfying the definition of a prime number. So, the number which is even as well as prime is 2.

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Answered on 24/02/2024 Learn CBSE/Class 6/Maths/Playing With Numbers

Sadika

The Fundamental Theorem of Arithmetic states that every positive integer greater than 1 can be expressed uniquely as a product of prime numbers, except for the order of the factors. In other words: Every positive integer greater than 1 can be factored into a product of prime numbers. This factorization... read more

The Fundamental Theorem of Arithmetic states that every positive integer greater than 1 can be expressed uniquely as a product of prime numbers, except for the order of the factors. In other words:

  • Every positive integer greater than 1 can be factored into a product of prime numbers.
  • This factorization is unique up to the order of the factors.

For example, let's take the number 12:

12=2×2×312=2×2×3

This is one possible prime factorization of 12. According to the Fundamental Theorem of Arithmetic, any other factorization of 12 into prime numbers will involve the same prime factors (in this case, 2 and 3), just in a different order.

This theorem is fundamental in number theory and is essential for many mathematical proofs and concepts, including the understanding of factors, divisors, and properties of numbers.

 
 
 
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