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Playing With Numbers

Playing With Numbers relates to CBSE/Class 6/Maths

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1
Karagathahalli, Palacode
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Jankipuram, Kursi Road, Lucknow
5 yrs of Exp
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Mylapore, Chennai
250per hour
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I am Shraddha Agarwal. I am an engineering graduate and also a MBA degree holder.. I am passionate about teaching and I have 2 years experience in...

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Civil Lines Hargovind Pura, Ludhiana
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My name is Sushma, and I have an M.A. (English) in B.ed. I am giving tuition for 1st to 12th-class students. Special classes in English grammar are...

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Uttam Nagar, Delhi
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7 yrs of Exp
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Hi, I am an experienced science and maths teacher. I have done my post graduation in M.Sc Bioinformatics from BHU. I have an experience of 7 years...

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Sector 83, Gurgaon
2 yrs of Exp
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Playing With Numbers Lessons

Understand what LCM and HCF is.
LCM- LCM stands for least common multiple The least common multiple of two numbers is the smallest number that is a multiple of both of them or the number which can be commonly multiplied by both the...
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Playing With Numbers Questions

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Answered on 24 Feb Learn CBSE/Class 6/Maths/Playing With Numbers

Sadika

The sum of any two even numbers is always an even number. Let's denote two even numbers as 2n2n and 2m2m, where nn and mm are integers. The sum of these two even numbers is: 2n+2m=2(n+m)2n+2m=2(n+m) Since nn and mm are integers, n+mn+m is also an integer. Therefore, the sum 2(n+m)2(n+m) is an even... read more

The sum of any two even numbers is always an even number.

Let's denote two even numbers as 2n2n and 2m2m, where nn and mm are integers.

The sum of these two even numbers is: 2n+2m=2(n+m)2n+2m=2(n+m)

Since nn and mm are integers, n+mn+m is also an integer. Therefore, the sum 2(n+m)2(n+m) is an even number because it is divisible by 22. Thus, the sum of any two even numbers is an even number.

 
 
 
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Answered on 24 Feb Learn CBSE/Class 6/Maths/Playing With Numbers

Sadika

To find the product of two numbers given their least common multiple (LCM) and highest common factor (HCF), you can use the relationship between the product, LCM, and HCF of two numbers. Let the two numbers be xx and yy. Given: LCM of xx and yy = 15 HCF of xx and yy = 4 We know that the product... read more

To find the product of two numbers given their least common multiple (LCM) and highest common factor (HCF), you can use the relationship between the product, LCM, and HCF of two numbers.

Let the two numbers be xx and yy.

Given:

  1. LCM of xx and yy = 15
  2. HCF of xx and yy = 4

We know that the product of two numbers is equal to the product of their LCM and HCF. That is:

x×y=LCM(x,y)×HCF(x,y)x×y=LCM(x,y)×HCF(x,y)

Substitute the given values:

x×y=15×4x×y=15×4

x×y=60x×y=60

So, the product of the two numbers is 6060.

 
 
 
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Answered on 24 Feb Learn CBSE/Class 6/Maths/Playing With Numbers

Sadika

To find the highest common factor (HCF) of two numbers, we find the largest number that divides both of them without leaving a remainder. For the numbers 5 and 7, the only common factor they share is 1, since both 5 and 7 are prime numbers. Since there are no other common factors besides 1, the HCF... read more

To find the highest common factor (HCF) of two numbers, we find the largest number that divides both of them without leaving a remainder.

For the numbers 5 and 7, the only common factor they share is 1, since both 5 and 7 are prime numbers. Since there are no other common factors besides 1, the HCF of 5 and 7 is 1.

 
 
 
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Answered on 28/06/2023 Learn CBSE/Class 6/Maths/Playing With Numbers

Srishti K.

To find the multiples of a number, we multiply that number by different integers. In this case, we want to find the first three multiples of 25. Multiples of 25: 1 × 25 = 25 2 × 25 = 50 3 × 25 = 75 Therefore, the first three multiples of 25 are 25, 50, and 75. read more

To find the multiples of a number, we multiply that number by different integers. In this case, we want to find the first three multiples of 25.

Multiples of 25:

1 × 25 = 25

2 × 25 = 50

3 × 25 = 75

Therefore, the first three multiples of 25 are 25, 50, and 75.

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Answered on 24 Feb Learn CBSE/Class 6/Maths/Playing With Numbers

Sadika

To find the factors of a number, you need to identify all the numbers that divide the given number evenly, including 1 and the number itself. Let's find the factors for each: (a) Factors of 12: 1, 2, 3, 4, 6, 12 (b) Factors of 18: 1, 2, 3, 6, 9, 18 These are all the possible factors of 12 and 18. ... read more

To find the factors of a number, you need to identify all the numbers that divide the given number evenly, including 1 and the number itself.

Let's find the factors for each:

(a) Factors of 12: 1, 2, 3, 4, 6, 12

(b) Factors of 18: 1, 2, 3, 6, 9, 18

These are all the possible factors of 12 and 18.

 
 
 
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