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Q3.1(i):
From the rate expression for the following reactions, determine their order of reaction and the dimensions of the rate constants. (i) \(3NO(g) \rightarrow N_{2}O (g)\) Rate = \(k[NO]^{2}\)

Solution :

Step 1: Identifying the Order of Reaction

The rate law for the given reaction is provided as:

$Rate = k[NO]^{2}$

The order of a reaction is defined as the sum of the powers of the concentration terms in the rate law expression [Per the definition of Rate Law].

  • The concentration term is $[NO]$.
  • The exponent associated with $[NO]$ is $2$.

Therefore, the order of the reaction is $n = 2$ [By summation of rate exponents].

Step 2: Deriving the Dimensions of the Rate Constant ($k$)

The rate equation is given by $Rate = k[Concentration]^{n}$. To find the units of the rate constant $k$, we rearrange the equation as follows:

$k = \frac{Rate}{[Concentration]^{n}}$

Substituting the standard units for the variables involved:

  • $Rate$ is expressed in units of concentration per unit time: $mol \cdot L^{-1} \cdot s^{-1}$.
  • $[Concentration]$ is expressed in molarity: $mol \cdot L^{-1}$.
  • The order of the reaction $n = 2$.

Substituting these values into the rearranged equation:

$k = \frac{mol \cdot L^{-1} \cdot s^{-1}}{(mol \cdot L^{-1})^{2}}$

$k = \frac{mol \cdot L^{-1} \cdot s^{-1}}{mol^{2} \cdot L^{-2}}$

$k = mol^{(1-2)} \cdot L^{(-1 - (-2))} \cdot s^{-1}$

$k = mol^{-1} \cdot L^{1} \cdot s^{-1}$

Step 3: Tabular Summary of Findings

Parameter Calculated Value/Unit
Reaction Order 2 (Second Order)
Rate Constant Dimension $L \cdot mol^{-1} \cdot s^{-1}$
Second Order Kinetics (Rate = k[A]²) [NO] Rate

Final Solution: The order of the reaction is 2, and the dimensions of the rate constant are $L \cdot mol^{-1} \cdot s^{-1}$.


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