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Q15.6(a):
A bat emits ultrasonic sound of frequency 1000 kHz in air. If the sound meets a water surface, what is the wavelength of (a) the reflected sound, (b) the transmitted sound? Speed of sound in air is 340 m $s^{-1}$ and in water 1486 m $s^{-1}$.

Solution :

Step 1: Given Parameters and Theoretical Constants

To determine the wavelength of sound waves across different media, we utilize the fundamental wave equation relating velocity ($v$), frequency ($f$), and wavelength ($\lambda$):

$v = f \cdot \lambda \implies \lambda = \frac{v}{f}$

  • Frequency of source ($f$): $1000 \text{ kHz} = 10^6 \text{ Hz}$
  • Speed of sound in air ($v_{air}$): $340 \text{ m/s}$
  • Speed of sound in water ($v_{water}$): $1486 \text{ m/s}$
[Per the principle of wave propagation, the frequency of a wave remains invariant when it crosses an interface between two different media, whereas the velocity and wavelength change.]

Step 2: Calculating Wavelength of Reflected Sound

Reflected sound remains within the medium of origin (air). Therefore, the velocity of the reflected wave is identical to the incident wave in air.

$\lambda_{reflected} = \frac{v_{air}}{f}$

$\lambda_{reflected} = \frac{340 \text{ m/s}}{10^6 \text{ Hz}} = 3.4 \times 10^{-4} \text{ m}$

Conversion to micrometers: $3.4 \times 10^{-4} \text{ m} \times 10^6 \text{ } \mu\text{m/m} = 340 \text{ } \mu\text{m}$

Step 3: Calculating Wavelength of Transmitted Sound

Transmitted sound enters the new medium (water). The frequency $f$ remains $10^6 \text{ Hz}$, but the velocity changes to $v_{water}$.

$\lambda_{transmitted} = \frac{v_{water}}{f}$

$\lambda_{transmitted} = \frac{1486 \text{ m/s}}{10^6 \text{ Hz}} = 1.486 \times 10^{-3} \text{ m}$

Conversion to millimeters: $1.486 \times 10^{-3} \text{ m} \times 10^3 \text{ mm/m} = 1.486 \text{ mm}$

Step 4: Comparative Data Representation

Wave Type Velocity ($v$) Frequency ($f$) Wavelength ($\lambda$)
Reflected (Air) $340 \text{ m/s}$ $10^6 \text{ Hz}$ $3.4 \times 10^{-4} \text{ m}$
Transmitted (Water) $1486 \text{ m/s}$ $10^6 \text{ Hz}$ $1.486 \times 10^{-3} \text{ m}$

Visual Representation of Wave Interaction

Interface (Air/Water) Incident Reflected Transmitted

Final Solution: (a) The wavelength of the reflected sound is $3.4 \times 10^{-4} \text{ m}$ ($0.34 \text{ mm}$); (b) The wavelength of the transmitted sound is $1.486 \times 10^{-3} \text{ m}$ ($1.486 \text{ mm}$).


More Questions from Class 11 Physics Waves EXERCISES


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