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Q15.12(i)(a):
For the wave on a string described in Exercise 15.11, do all the points on the string oscillate with the same (a) frequency? Explain your answers.

Solution :

Step 1: Theoretical Foundation of a Traveling Wave

A transverse wave traveling along a string is mathematically described by the standard wave function:

$y(x, t) = A \sin(kx - \omega t + \phi)$

Where:

  • $A$ = Amplitude of oscillation.
  • $k = \frac{2\pi}{\lambda}$ = Angular wave number.
  • $\omega = 2\pi\nu = \frac{2\pi}{T}$ = Angular frequency.
  • $x$ = Position along the string.
  • $t$ = Time.

[Per the principle of harmonic wave motion, every particle of the medium participates in the transfer of energy while maintaining its own simple harmonic motion (SHM).]

Step 2: Defining the Oscillation of a Fixed Point

To determine the frequency of oscillation for any specific point on the string, we fix the position coordinate at $x = x_0$. The displacement $y$ of this specific point as a function of time $t$ is given by:

$y(x_0, t) = A \sin(kx_0 - \omega t + \phi)$

This equation represents an SHM of the form $y = A \sin(\omega t + \phi')$, where $\phi' = kx_0 + \phi$. The angular frequency $\omega$ is the coefficient of the time variable $t$. [By the definition of angular frequency in SHM, $\omega = \frac{d\theta}{dt}$.]

Step 3: Comparative Analysis of Frequency

The frequency $\nu$ of the oscillation is derived from the angular frequency as $\nu = \frac{\omega}{2\pi}$. Since $\omega$ is a constant determined by the source of the wave (the mechanical oscillator) and the properties of the medium (tension and mass per unit length), it does not contain a dependence on the spatial variable $x$.

Variable Dependency on Position ($x$)
Amplitude ($A$) Constant for an ideal string
Frequency ($\nu$) Independent of $x$
Phase ($\phi'$) Dependent on $x$

Step 4: Visualizing Wave Uniformity

Point 1 Point 2 All points oscillate vertically with frequency ν

Conclusion and Justification

Because the angular frequency $\omega$ is a global constant for the entire wave propagation, every individual particle on the string must execute simple harmonic motion with the same frequency $\nu$. While the particles oscillate with the same frequency and amplitude, they differ in their phase, which is a function of their position $x$ along the string. [By the property of wave propagation in a continuous medium, spatial translation only shifts the phase of the oscillation, not the temporal frequency.]

Final Solution: Yes, all points on the string oscillate with the same frequency.


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