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Q14.4(a):
Use the formula (v) = (\sqrt{\frac{\gamma P}{\rho}}) to explain why the speed of sound in air is independent of pressure,

Solution :

Step 1: Establishing the Theoretical Framework

The speed of sound ($v$) in an ideal gas is governed by the Newton-Laplace equation, which accounts for the adiabatic nature of sound propagation in air:

$v = \sqrt{\frac{\gamma P}{\rho}}$

Where:

  • $\gamma$ = Adiabatic index (Ratio of specific heats, $C_p/C_v$)
  • $P$ = Pressure of the gas
  • $\rho$ = Density of the gas
[Per the Adiabatic Propagation Hypothesis by Laplace, sound waves travel too rapidly for heat exchange to occur, making the process adiabatic rather than isothermal.]

Step 2: Integrating the Ideal Gas Law

To analyze the dependence of $v$ on $P$, we utilize the Ideal Gas Equation for one mole of gas:

$PV = RT$

Since density ($\rho$) is defined as mass ($M$) divided by volume ($V$), we can express the density as:

$\rho = \frac{M}{V} \implies V = \frac{M}{\rho}$

Substituting this into the Ideal Gas Equation:

$P\left(\frac{M}{\rho}\right) = RT$

Rearranging for the ratio of pressure to density:

$\frac{P}{\rho} = \frac{RT}{M}$

[By the definition of State Variables in Kinetic Theory of Gases]

Step 3: Analytical Substitution and Derivation

Now, substitute the expression for $\frac{P}{\rho}$ derived in Step 2 into the original speed of sound formula:

$v = \sqrt{\gamma \left(\frac{P}{\rho}\right)}$

$v = \sqrt{\frac{\gamma RT}{M}}$

Where:

  • $R$ = Universal Gas Constant ($8.314 \, J \cdot mol^{-1} \cdot K^{-1}$)
  • $T$ = Absolute Temperature in Kelvin
  • $M$ = Molar mass of the gas

Step 4: Conclusion on Pressure Independence

Observing the final derived expression $v = \sqrt{\frac{\gamma RT}{M}}$:

  • The variables on the right side of the equation are $\gamma$, $R$, $T$, and $M$.
  • The term $P$ (Pressure) has been algebraically cancelled out by the proportional change in $\rho$ (Density) when temperature remains constant.
  • According to Boyle's Law ($P \propto \rho$ at constant temperature), if $P$ increases, $\rho$ increases by the same factor, keeping the ratio $\frac{P}{\rho}$ constant.
Constant Temperature (Isothermal State) P / ρ Constant Ratio (P/ρ)

Final Solution: Because the density of an ideal gas is directly proportional to its pressure at a constant temperature ($\rho \propto P$), any change in pressure results in a proportional change in density. This keeps the ratio $\frac{P}{\rho}$ invariant, thereby proving that the speed of sound is independent of pressure.


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