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Q14.8(a):
A transverse harmonic wave on a string is described by (y(x, t)) = (3.0 \sin (36 t + 0.018 x + \frac{\pi}{4})) where (x) and (y) are in cm and (t) in s. The positive direction of (x) is from left to right. Is this a travelling wave or a stationary wave ? If it is travelling, what are the speed and direction of its propagation ?

Solution :

Step 1: Identifying the Mathematical Form of the Wave

The given equation for the displacement of the string is:

$y(x, t) = 3.0 \sin(36t + 0.018x + \frac{\pi}{4})$

A general harmonic travelling wave in one dimension is represented by the function $y(x, t) = f(ax \pm bt)$, where $a$ and $b$ are constants. Since the given equation is a function of the form $f(kx + \omega t)$, it represents a single, coherent travelling wave [Per the wave equation $\frac{\partial^2 y}{\partial x^2} = \frac{1}{v^2} \frac{\partial^2 y}{\partial t^2}$]. A stationary wave would require the superposition of two waves traveling in opposite directions, typically taking the form $y = A \sin(kx) \cos(\omega t)$.

Step 2: Extracting Wave Parameters

Comparing the given equation $y(x, t) = 3.0 \sin(0.018x + 36t + \frac{\pi}{4})$ to the standard travelling wave equation $y(x, t) = A \sin(kx + \omega t + \phi)$:

  • Angular frequency, $\omega = 36 \text{ rad/s}$
  • Wave number, $k = 0.018 \text{ cm}^{-1}$

Step 3: Calculating Speed and Determining Direction

The speed $v$ of a travelling wave is defined by the ratio of the angular frequency to the wave number [By the relation $v = \frac{\omega}{k}$]:

$v = \frac{36}{0.018}$

$v = \frac{36 \times 1000}{18}$

$v = 2 \times 1000 = 2000 \text{ cm/s}$

$v = 20 \text{ m/s}$

To determine the direction, we observe the sign of the $x$ and $t$ terms. In the expression $(kx + \omega t)$, when the sign between the spatial and temporal terms is positive, it indicates that the wave is propagating in the negative x-direction (i.e., from right to left).

Visual Representation of Wave Parameters

Wave propagation direction: Negative x-axis x=0 v = 20 m/s

Summary of Analytical Results

Parameter Value
Wave Type Travelling Wave
Speed ($v$) $20 \text{ m/s}$
Direction Negative $x$-direction (Right to Left)

Final Solution: The equation describes a travelling wave propagating in the negative x-direction with a speed of 20 m/s.


More Questions from Class 11 Physics Waves EXERCISES


CBSE Solutions for Class 11 Physics Waves


Chapters in CBSE - Class 11 Physics


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