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Q8.9:
A steel cable with a radius of 1.5 cm supports a chairlift at a ski area. If the maximum stress is not to exceed \(10^{8} \text{ N m}^{–2}\), what is the maximum load the cable can support ?

Solution :

Step 1: Given Variables and Physical Constants

To determine the maximum load, we define the parameters provided in the problem statement:

  • Radius of the steel cable, $r = 1.5 \text{ cm} = 1.5 \times 10^{-2} \text{ m}$
  • Maximum allowable stress, $\sigma_{max} = 10^8 \text{ N m}^{-2}$
  • Acceleration due to gravity, $g \approx 9.8 \text{ m s}^{-2}$ (if calculating mass)

Step 2: Theoretical Foundation

Stress ($\sigma$) is defined as the internal restoring force per unit area. In this equilibrium state, the load (Force, $F$) must be balanced by the stress distributed across the cross-sectional area ($A$) of the cable. The relationship is governed by the definition of mechanical stress:

$\sigma = \frac{F}{A}$ [By the definition of Normal Stress]

Step 3: Calculation of Cross-Sectional Area

Assuming the cable has a circular cross-section, the area $A$ is calculated as:

$A = \pi r^2$

$A = \pi \times (1.5 \times 10^{-2} \text{ m})^2$

$A = \pi \times 2.25 \times 10^{-4} \text{ m}^2$

$A \approx 3.14159 \times 2.25 \times 10^{-4} \text{ m}^2 \approx 7.068 \times 10^{-4} \text{ m}^2$

Step 4: Deriving the Maximum Force (Load)

Rearranging the stress formula for Force ($F_{max}$):

$F_{max} = \sigma_{max} \times A$

$F_{max} = (10^8 \text{ N m}^{-2}) \times (7.068 \times 10^{-4} \text{ m}^2)$

$F_{max} = 7.068 \times 10^4 \text{ N}$

Cable (r = 1.5 cm) Load (F = 7.07 x 10^4 N)

Step 5: Analysis of Results

The resulting force represents the limit of the elastic capacity of the steel cable before the stress threshold is breached. If mass ($m$) is required, we use $F = mg$:

$m = \frac{7.068 \times 10^4 \text{ N}}{9.8 \text{ m s}^{-2}} \approx 7.21 \times 10^3 \text{ kg}$

Final Solution: The maximum load the cable can support is $7.07 \times 10^{4} \text{ N}$ (or approximately $7.21 \times 10^{3} \text{ kg}$).


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