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Q6(vi):
Two dice are thrown. The events A, B and C are as follows: A: getting an even number on the first die. B: getting an odd number on the first die. C: getting the sum of the numbers on the dice $ \le 5$. Describe the events (vi) B or C

Solution :

Step 1: Establishing the Sample Space ($S$)

When two six-sided dice are thrown, each die has an outcome set of $\{1, 2, 3, 4, 5, 6\}$. The total sample space $S$ consists of $6 \times 6 = 36$ ordered pairs $(d_1, d_2)$, where $d_1$ is the result of the first die and $d_2$ is the result of the second die.

$S = \{(1,1), (1,2), \dots, (6,6)\}$ [By the Fundamental Counting Principle].

Step 2: Defining Event $B$ and Event $C$

Event $B$ is defined as "getting an odd number on the first die." Thus, $d_1 \in \{1, 3, 5\}$.

$B = \{(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6)\}$

Event $C$ is defined as "getting the sum of the numbers on the dice $\le 5$."

$C = \{(1,1), (1,2), (1,3), (1,4), (2,1), (2,2), (2,3), (3,1), (3,2), (4,1)\}$

Step 3: Calculating the Union ($B \cup C$)

The event "B or C" is represented by the union $B \cup C$. This set includes all outcomes that are in $B$, or in $C$, or in both [Set Theory Definition of Union].

Elements exclusively in $B$Elements in $B \cap C$Elements exclusively in $C$
(1,5), (1,6), (3,3), (3,4), (3,5), (3,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6)(1,1), (1,2), (1,3), (1,4), (3,1), (3,2)(2,1), (2,2), (2,3), (4,1)

Step 4: Final Compilation of Outcomes

Combining the sets and removing duplicates:

$B \cup C = \{(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6)\}$

B C B ∪ C Representation

Final Solution: The set $B \cup C = \{(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6)\}$


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