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Q2(v):
A die is thrown. Describe the following events: (v) E: an even number greater than 4

Solution :

Step 1: Defining the Sample Space ($S$)

When a standard fair six-faced die is rolled, the sample space ($S$) consists of all possible outcomes. A standard die is labeled with integers from 1 to 6.

$S = \{1, 2, 3, 4, 5, 6\}$

[Per the Classical Definition of Probability, the sample space is the set of all elementary outcomes of a random experiment.]

Step 2: Defining the Constraints for Event $E$

The problem defines Event $E$ based on two specific conditions that must be satisfied simultaneously:

  • Condition A: The outcome must be an even number. In set notation, this is the subset $\{2, 4, 6\}$.
  • Condition B: The outcome must be strictly greater than $4$. In set notation, this is the subset $\{5, 6\}$.

Step 3: Intersection of Conditions

To determine the set of outcomes for Event $E$, we calculate the intersection of Condition A and Condition B:

$E = \{x \in S \mid x \text{ is even and } x > 4\}$

$E = \{2, 4, 6\} \cap \{5, 6\}$

By comparing the elements, the only common element that satisfies both being an even number and being greater than 4 is $6$.

Step 4: Visual Representation

Sample Space S = {1, 2, 3, 4, 5, 6} E = {6} Event: Even and > 4

Step 5: Final Set Construction

Based on the logical intersection defined in Step 3:

$E = \{6\}$

[By the property of singleton sets, since there is exactly one outcome satisfying the criteria.]

Final Solution: The event E of getting an even number greater than 4 when a die is thrown is the set {6}.


More Questions from Class 11 Mathematics Probability EXERCISE 14.1


CBSE Solutions for Class 11 Mathematics Probability


Chapters in CBSE - Class 11 Mathematics


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