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Q1:
A die is rolled. Let E be the event “die shows 4” and F be the event “die shows even number”. Are E and F mutually exclusive?

Solution :

Step 1: Defining the Sample Space ($S$)

When a standard six-faced die is rolled, the set of all possible outcomes, denoted as the sample space $S$, is defined as:

$S = \{1, 2, 3, 4, 5, 6\}$

[By the definition of a discrete sample space for a fair die]

Step 2: Identifying Event Outcomes

Event $E$ is defined as the event where the die shows a 4. Thus:

$E = \{4\}$

Event $F$ is defined as the event where the die shows an even number. The even numbers in the sample space $S$ are 2, 4, and 6. Thus:

$F = \{2, 4, 6\}$

Step 3: Calculating the Intersection of Events ($E \cap F$)

To determine if two events are mutually exclusive, we must calculate the intersection of the two sets. Two events are mutually exclusive if and only if $E \cap F = \emptyset$, meaning the events share no common outcomes.

$E \cap F = \{4\} \cap \{2, 4, 6\}$

$E \cap F = \{4\}$

[Per the set-theoretic definition of intersection]

Step 4: Evaluating Mutually Exclusive Criteria

Since $E \cap F = \{4\}$, and $\{4\} \neq \emptyset$ (the intersection is not the empty set), there is an outcome common to both events.

E F 4 2, 6

Analytical Conclusion

Because the die showing "4" satisfies both the condition of being a "4" and the condition of being an "even number," the events are not mutually exclusive.

Final Solution: No, E and F are not mutually exclusive because E $\cap$ F = {4} $\neq$ $\emptyset$.


More Questions from Class 11 Mathematics Probability EXERCISE 14.1


CBSE Solutions for Class 11 Mathematics Probability


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