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Q6:

Beams of light are incident through the holes $A$ and $B$ and emerge out of box through the holes $C$ and $D$ respectively as shown in the Figure10.3. Which of the following could be inside the box?

Beams of light are incident through the holes A and B and emerge out of box  through the holes C and D respectively as shown in Figure. Which of the following  could

                                          

 

Solution :

Analysis of Optical Path

Based on the provided ray diagram, incident light rays entering through holes $A$ and $B$ emerge through holes $C$ and $D$ respectively, maintaining a parallel trajectory relative to each other, but shifted laterally. Specifically, the ray entering at the top ($A$) exits from the top ($C$), and the ray entering at the bottom ($B$) exits from the bottom ($D$). This suggests that the light rays have undergone a lateral shift without changing their relative orientation or undergoing inversion.

Evaluation of Optical Components

To determine the nature of the object inside the box, we evaluate the properties of standard optical elements:

  • Convex Lens: If a convex lens were placed, parallel rays would converge at the focal point, causing rays to cross and emerge inverted, which is not observed here [Per the Rules of Refraction for Convex Lenses].
  • Concave Lens: A concave lens would cause parallel rays to diverge, altering the path such that they would not emerge as parallel beams through $C$ and $D$ [Per the Properties of Diverging Lenses].
  • Glass Slab: A rectangular glass slab produces a lateral displacement of incident light rays. When a parallel beam of light passes through a rectangular glass slab, the emergent rays remain parallel to the incident rays, but are displaced laterally [By the Law of Refraction: $n_1 \sin i = n_2 \sin r$].

Geometric Representation of the Glass Slab

A C Rectangular Glass Slab

Deduction and Conclusion

The observation that the light beams exit the box parallel to their original path while maintaining their vertical order ($A$ enters top, exits $C$ top; $B$ enters bottom, exits $D$ bottom) indicates that the component inside the box is a Rectangular Glass Slab.

The lateral displacement ($\Delta x$) is given by the formula:

$$\Delta x = t \cdot \frac{\sin(i - r)}{\cos r}$$

Where:

  • $t$ = thickness of the glass slab
  • $i$ = angle of incidence
  • $r$ = angle of refraction

[Justification: The glass slab introduces a lateral shift because the incident and emergent rays are parallel, but the ray is displaced due to two successive refractions at the air-glass and glass-air interfaces per Snell's Law.]

Final Solution: The object inside the box is a Rectangular Glass Slab.


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