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Q14:

The path of a ray of light coming from air passing through a rectangular glass slab traced by four students are shown as $A$, $B$, $C$ and $D$ in Figure 10.5. Which one of them is correct?

Solution :

Step 1: Theoretical Foundation of Refraction through a Rectangular Glass Slab

When a ray of light travels from an optically rarer medium (air, $n_1 \approx 1.00$) to an optically denser medium (glass, $n_2 \approx 1.5$), it undergoes refraction. Per Snell’s Law, the relationship is defined as $n_1 \sin(i) = n_2 \sin(r)$. Since $n_2 > n_1$, the angle of refraction ($r$) must be less than the angle of incidence ($i$), causing the ray to bend towards the normal [Ref: Law of Refraction].

Upon exiting the slab from the glass back into the air, the ray travels from a denser to a rarer medium. In this instance, the ray bends away from the normal at the second interface. Crucially, because the opposite faces of a rectangular glass slab are parallel, the angle of emergence ($e$) is equal to the angle of incidence ($i$), and the emergent ray is parallel to the incident ray but laterally displaced [Ref: Principle of Reversibility and Parallelism of Refraction].

Step 2: Analytical Evaluation of Paths

  • Path A: Shows the ray bending away from the normal upon entry. This violates the rule that light slows down and bends toward the normal when entering a denser medium ($n_2 > n_1$).
  • Path B: Shows the ray bending towards the normal at the entry point and away from the normal at the exit point. The emergent ray is depicted as parallel to the original incident path. This aligns perfectly with the physical laws of optics.
  • Path C: Shows the ray passing straight through without any deviation, which ignores the refractive index change between air and glass.
  • Path D: Shows an incorrect angle of refraction and an emergent ray that does not demonstrate lateral displacement relative to the incident ray.

Step 3: Visual Representation of the Correct Path (B)

Incident Ray Emergent Ray Glass Slab

Step 4: Conclusion

Based on the application of Snell's Law and the geometric properties of refraction through parallel interfaces, Path B is the only trajectory that satisfies the requirement that the angle of refraction must be less than the angle of incidence, and the emergent ray must be parallel to the incident ray.

Final Solution: The correct path traced by the student is B.


More Questions from Class 10 Science Light – Reflection and Refraction CHAPTER_10


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