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Q38(iv):
A student focussed the image of a candle flame on a white screen using a convex lens. He noted down the position of the candle screen and the lens as under: Position of candle = 12.0 cm, Position of convex lens = 50.0 cm, Position of the screen = 88.0 cm. (iv) Draw a ray diagram to show the formation of the image in case (iii) as said above.

Solution :

Step 1: Identifying Optical Parameters

To construct the ray diagram, we first determine the object distance ($u$), image distance ($v$), and the focal length ($f$) of the convex lens based on the provided positions:

  • Position of candle ($P_o$): $12.0 \text{ cm}$
  • Position of lens ($P_l$): $50.0 \text{ cm}$
  • Position of screen ($P_s$): $88.0 \text{ cm}$

Calculations:

  • Object distance $u = P_o - P_l = 12.0 - 50.0 = -38.0 \text{ cm}$ [By sign convention, light travels left to right; distances against direction of light are negative].
  • Image distance $v = P_s - P_l = 88.0 - 50.0 = +38.0 \text{ cm}$ [Distance in direction of light is positive].

Since $|u| = |v| = 38.0 \text{ cm}$, the object is placed at $2F$. Thus, $2f = 38.0 \text{ cm}$, which implies the focal length $f = 19.0 \text{ cm}$. [Per the properties of convex lenses, when $u = 2f$, $v = 2f$ and the image is real, inverted, and of the same size].

Step 2: Ray Diagram Specifications

The diagram must depict an object placed at $2F_1$. Two primary rays are used to locate the image:

  1. Ray 1: Parallel to the principal axis, which refracts through the principal focus ($F_2$) on the other side.
  2. Ray 2: Passing through the optical center ($O$), which continues undeviated.

Step 3: Precise Ray Diagram Construction

O F1 2F1 F2 2F2 Object Image

Step 4: Analytical Summary of Image Formation

Attribute Description
Position At $2F_2$ ($38.0 \text{ cm}$ from lens)
Nature Real and Inverted
Size Same size as the object

Final Solution: The image is formed at 38.0 cm on the side opposite to the object (88.0 cm mark on the optical bench). The image is real, inverted, and of equal magnitude to the object, consistent with the condition $u = v = 2f$.


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