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Q35:
The image of a candle flame formed by a lens is obtained on a screen placed on the other side of the lens. If the image is three times the size of the flame and the distance between lens and image is 80 cm, at what distance should the candle be placed from the lens? What is the nature of the image at a distance of 80 cm and the lens?

Solution :

Step 1: Identifying Given Parameters and Sign Convention

Based on the problem statement, we identify the following variables according to the Cartesian Sign Convention:

  • Magnification ($m$) = $-3$ (The image is real, as it is obtained on a screen, thus magnification is negative) [Per the definition of linear magnification for real images].
  • Distance of the image from the lens ($v$) = $+80\text{ cm}$ (Since the image is real and formed on the opposite side of the lens, $v$ is positive).
  • Distance of the object ($u$) = $?$
  • Nature of the lens: Since the image is real and formed on a screen, the lens must be a Convex Lens.

Step 2: Calculating Object Distance ($u$)

The magnification ($m$) of a lens is defined as the ratio of image distance ($v$) to object distance ($u$):

$m = \frac{v}{u}$

Substituting the known values into the equation:

$-3 = \frac{80}{u}$

$u = \frac{80}{-3} = -26.67\text{ cm}$

[By the lens formula magnification derivation: $m = \frac{v}{u}$ for thin lenses]. The negative sign indicates that the object is placed in front of the lens.

Step 3: Geometrical Representation

Lens Object ($u=26.7$) Image ($v=80$)

Step 4: Determining Nature of the Image and Lens

We analyze the properties determined in the previous steps:

Attribute Conclusion
Nature of Lens Convex Lens (Converging lens), as only convex lenses produce real, inverted images on a screen.
Nature of Image Real and Inverted. The positive $v$ value and the fact that it is captured on a screen confirm this [Per the properties of real images formed by convex lenses].

Final Solution: The candle should be placed at a distance of $26.67\text{ cm}$ from the lens. The lens is a convex lens, and the image is real and inverted.


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