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Q6:

A student noted the number of cars passing through a spot on a road for 100 periods each of 3 minutes and summarised it in the table given below. Find the mode of the data:

Solution :

Given: A frequency distribution table representing the number of cars passing through a spot in 100 periods of 3 minutes each.

Number of carsFrequency ($f_i$)
0 - 107
10 - 2014
20 - 3013
30 - 4012
40 - 5020
50 - 6011
60 - 7015
70 - 808

To find: The mode of the given grouped frequency distribution.

Step 1: Identify the Modal Class

The modal class is the class interval with the highest frequency. Observing the table, the highest frequency is $20$, which corresponds to the class interval $40 - 50$.

Therefore, the Modal Class is $40 - 50$.

Step 2: State the Formula for Mode

The formula for calculating the mode of grouped data is:

$\text{Mode} = l + \left( \frac{f_1 - f_0}{2f_1 - f_0 - f_2} \right) \times h$

Where:

  • $l$ = Lower limit of the modal class
  • $h$ = Size of the class interval
  • $f_1$ = Frequency of the modal class
  • $f_0$ = Frequency of the class preceding the modal class
  • $f_2$ = Frequency of the class succeeding the modal class

Step 3: Extract the Variables

Based on the modal class $40 - 50$:

  • $l = 40$
  • $h = 50 - 40 = 10$
  • $f_1 = 20$
  • $f_0 = 12$ (frequency of the class $30 - 40$)
  • $f_2 = 11$ (frequency of the class $50 - 60$)

Step 4: Substitute and Calculate

Substituting the values into the formula:

$\text{Mode} = 40 + \left( \frac{20 - 12}{2(20) - 12 - 11} \right) \times 10$

$\text{Mode} = 40 + \left( \frac{8}{40 - 23} \right) \times 10$

$\text{Mode} = 40 + \left( \frac{8}{17} \right) \times 10$

$\text{Mode} = 40 + \frac{80}{17}$

Performing the division: $80 \div 17 \approx 4.7058...$

$\text{Mode} = 40 + 4.71$ (rounded to two decimal places)

$\text{Mode} = 44.71$

Final Answer: The mode of the data is 44.71 cars.


More Questions from Class 10 Mathematics Statistics EXERCISE 13.2


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