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Q5:

The given distribution shows the number of runs scored by some top batsmen of the world in one-day international cricket matches.

Find the mode of the data.

Solution :

Given: The frequency distribution of runs scored by top batsmen in one-day international cricket matches is as follows:

Runs Scored Number of Batsmen ($f_i$)
3000 - 4000 4
4000 - 5000 18
5000 - 6000 9
6000 - 7000 7
7000 - 8000 6
8000 - 9000 3
9000 - 10000 1
10000 - 11000 1

To Find: The mode of the given grouped frequency distribution.

Step 1: Identify the Modal Class
The modal class is the class interval with the highest frequency. Looking at the table, the highest frequency is $18$, which corresponds to the class interval $4000 - 5000$.
Therefore, the Modal Class is $4000 - 5000$.

Step 2: State the Formula for Mode
The formula for calculating the mode of grouped data is:
$\text{Mode} = l + \left( \frac{f_1 - f_0}{2f_1 - f_0 - f_2} \right) \times h$
Where:
$l$ = Lower limit of the modal class
$h$ = Size of the class interval
$f_1$ = Frequency of the modal class
$f_0$ = Frequency of the class preceding the modal class
$f_2$ = Frequency of the class succeeding the modal class

Step 3: Assign Values to Variables
From the distribution:
$l = 4000$
$h = 5000 - 4000 = 1000$
$f_1 = 18$
$f_0 = 4$
$f_2 = 9$

Step 4: Substitute Values into the Formula
$\text{Mode} = 4000 + \left( \frac{18 - 4}{2(18) - 4 - 9} \right) \times 1000$
$\text{Mode} = 4000 + \left( \frac{14}{36 - 13} \right) \times 1000$
$\text{Mode} = 4000 + \left( \frac{14}{23} \right) \times 1000$
$\text{Mode} = 4000 + \frac{14000}{23}$

Step 5: Perform the Arithmetic Calculation
Dividing $14000$ by $23$:
$14000 \div 23 \approx 608.6956...$
Rounding to two decimal places, we get $608.70$.
$\text{Mode} = 4000 + 608.70$
$\text{Mode} = 4608.70$

Final Answer: The mode of the given data is 4608.7 runs.


More Questions from Class 10 Mathematics Statistics EXERCISE 13.2


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