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Q8:

A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent. 

Solution :

Given: The frequency distribution of the number of days 40 students were absent during a term.

To Find: The mean number of days a student was absent.

Data Representation:

Number of days Number of students ($f_i$)
0 - 611
6 - 1010
10 - 147
14 - 204
20 - 284
28 - 383
38 - 401
Total$\sum f_i = 40$

Step 1: Calculate the Class Mark ($x_i$) for each interval.

The class mark is calculated using the formula: $x_i = \frac{\text{Upper Limit} + \text{Lower Limit}}{2}$.

  • For 0 - 6: $x_1 = \frac{0+6}{2} = 3$
  • For 6 - 10: $x_2 = \frac{6+10}{2} = 8$
  • For 10 - 14: $x_3 = \frac{10+14}{2} = 12$
  • For 14 - 20: $x_4 = \frac{14+20}{2} = 17$
  • For 20 - 28: $x_5 = \frac{20+28}{2} = 24$
  • For 28 - 38: $x_6 = \frac{28+38}{2} = 33$
  • For 38 - 40: $x_7 = \frac{38+40}{2} = 39$

Step 2: Calculate the product of frequency and class mark ($f_i x_i$).

Class Interval $f_i$ $x_i$ $f_i x_i$
0 - 611333
6 - 1010880
10 - 1471284
14 - 2041768
20 - 2842496
28 - 3833399
38 - 4013939
Total40-499

Step 3: Apply the Direct Method formula for Mean ($\bar{x}$).

The formula for the mean is given by: $\bar{x} = \frac{\sum f_i x_i}{\sum f_i}$

Substituting the values obtained from the table:

$\sum f_i x_i = 33 + 80 + 84 + 68 + 96 + 99 + 39 = 499$

$\sum f_i = 40$

$\bar{x} = \frac{499}{40}$

Step 4: Final Calculation.

$\bar{x} = 12.475$

Final Answer: The mean number of days a student was absent is 12.475 days.


More Questions from Class 10 Mathematics Statistics EXERCISE 13.1


CBSE Solutions for Class 10 Mathematics Statistics


Chapters in CBSE - Class 10 Mathematics


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