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Q3:

The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs 18. Find the missing frequency $f$. 

Solution :

Given: The frequency distribution of daily pocket allowance of children, where the mean ($\bar{x}$) is Rs 18. The data is as follows:

Daily Pocket Allowance (Rs) 11-13 13-15 15-17 17-19 19-21 21-23 23-25
Number of Children ($f_i$) 7 6 9 13 $f$ 5 4

To Find: The value of the missing frequency $f$.

Step 1: Constructing the Frequency Distribution Table

To calculate the mean using the Direct Method, we first find the class mark ($x_i$) for each interval, where $x_i = \frac{\text{Upper Limit} + \text{Lower Limit}}{2}$.

Class Interval Frequency ($f_i$) Class Mark ($x_i$) $f_i \cdot x_i$
11-1371284
13-1561484
15-17916144
17-191318234
19-21$f$20$20f$
21-23522110
23-2542496
Total$\sum f_i = 44 + f$-$\sum f_i x_i = 752 + 20f$

Step 2: Applying the Mean Formula

The formula for the mean ($\bar{x}$) using the direct method is given by:

$\bar{x} = \frac{\sum f_i x_i}{\sum f_i}$

Step 3: Substituting the Values and Solving for $f$

Given $\bar{x} = 18$, we substitute the values from our table:

$18 = \frac{752 + 20f}{44 + f}$

Multiply both sides by $(44 + f)$ to clear the denominator:

$18(44 + f) = 752 + 20f$

Distribute the 18 on the left side:

$792 + 18f = 752 + 20f$

Rearrange the terms to isolate $f$ on one side:

$792 - 752 = 20f - 18f$

$40 = 2f$

Divide by 2:

$f = \frac{40}{2}$

$f = 20$

Final Answer: The missing frequency $f$ is 20.


More Questions from Class 10 Mathematics Statistics EXERCISE 13.1


CBSE Solutions for Class 10 Mathematics Statistics


Chapters in CBSE - Class 10 Mathematics


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