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Q4:

Thirty women were examined in a hospital by a doctor and the number of heartbeats per minute were recorded and summarised as follows. Find the mean heartbeats per minute for these women, choosing a suitable method.

Solution :

Given: A frequency distribution of the number of heartbeats per minute for 30 women.

To Find: The mean number of heartbeats per minute using a suitable method.

Data Table:

Number of heartbeats per minute (Class Interval) Number of women ($f_i$)
65 - 682
68 - 714
71 - 743
74 - 778
77 - 807
80 - 834
83 - 862

Method Selection: Since the class intervals are uniform and the values are manageable, we will use the Assumed Mean Method to calculate the mean ($\bar{x}$).

Formula: $\bar{x} = a + \frac{\sum f_i d_i}{\sum f_i}$, where $a$ is the assumed mean and $d_i = x_i - a$.

Step 1: Constructing the Calculation Table

Class Interval Frequency ($f_i$) Class Mark ($x_i$) Deviation ($d_i = x_i - a$) $f_i d_i$
65 - 68266.5-9-18
68 - 71469.5-6-24
71 - 74372.5-3-9
74 - 77875.5 (a)00
77 - 80778.5321
80 - 83481.5624
83 - 86284.5918
Total$\sum f_i = 30$--$\sum f_i d_i = 12$

Step 2: Defining Variables

Let the assumed mean $a = 75.5$.

The class size $h = 68 - 65 = 3$.

The sum of frequencies $\sum f_i = 30$.

The sum of deviations $\sum f_i d_i = (-18) + (-24) + (-9) + 0 + 21 + 24 + 18 = 12$.

Step 3: Applying the Formula

$\bar{x} = a + \frac{\sum f_i d_i}{\sum f_i}$

$\bar{x} = 75.5 + \frac{12}{30}$ [Substituting the values]

$\bar{x} = 75.5 + 0.4$ [Simplifying the fraction $12/30 = 2/5 = 0.4$]

$\bar{x} = 75.9$

Final Answer: The mean number of heartbeats per minute for these women is 75.9.


More Questions from Class 10 Mathematics Statistics EXERCISE 13.1


CBSE Solutions for Class 10 Mathematics Statistics


Chapters in CBSE - Class 10 Mathematics


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