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Q4:

Thirty women were examined in a hospital by a doctor and the number of heartbeats per minute were recorded and summarised as follows. Find the mean heartbeats per minute for these women, choosing a suitable method.

Solution :

Given: A frequency distribution of the number of heartbeats per minute for 30 women.

To Find: The mean number of heartbeats per minute using a suitable method.

Data Table:

Number of heartbeats per minute (Class Interval) Number of women ($f_i$)
65 - 682
68 - 714
71 - 743
74 - 778
77 - 807
80 - 834
83 - 862

Method Selection: Since the class intervals are uniform and the values are manageable, we will use the Assumed Mean Method to calculate the mean ($\bar{x}$).

Formula: $\bar{x} = a + \frac{\sum f_i d_i}{\sum f_i}$, where $a$ is the assumed mean and $d_i = x_i - a$.

Step 1: Constructing the Calculation Table

Class Interval Frequency ($f_i$) Class Mark ($x_i$) Deviation ($d_i = x_i - a$) $f_i d_i$
65 - 68266.5-9-18
68 - 71469.5-6-24
71 - 74372.5-3-9
74 - 77875.5 (a)00
77 - 80778.5321
80 - 83481.5624
83 - 86284.5918
Total$\sum f_i = 30$--$\sum f_i d_i = 12$

Step 2: Defining Variables

Let the assumed mean $a = 75.5$.

The class size $h = 68 - 65 = 3$.

The sum of frequencies $\sum f_i = 30$.

The sum of deviations $\sum f_i d_i = (-18) + (-24) + (-9) + 0 + 21 + 24 + 18 = 12$.

Step 3: Applying the Formula

$\bar{x} = a + \frac{\sum f_i d_i}{\sum f_i}$

$\bar{x} = 75.5 + \frac{12}{30}$ [Substituting the values]

$\bar{x} = 75.5 + 0.4$ [Simplifying the fraction $12/30 = 2/5 = 0.4$]

$\bar{x} = 75.9$

Final Answer: The mean number of heartbeats per minute for these women is 75.9.


More Questions from Class 10 Mathematics Statistics EXERCISE 13.1


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