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Q4(x):
Which of the following are APs ? If they form an AP, find the common difference $d$ and write three more terms. (x) $a, 2a, 3a, 4a, . . .$

Solution :

Given: A sequence of numbers: $a, 2a, 3a, 4a, \dots$

To find:
1. Determine if the given sequence forms an Arithmetic Progression (AP).
2. If it forms an AP, find the common difference $d$.
3. Write the next three terms of the sequence.

Step 1: Definition of an Arithmetic Progression
A sequence $a_1, a_2, a_3, \dots, a_n$ is said to be an Arithmetic Progression if the difference between consecutive terms remains constant. This constant difference is denoted by $d$.
Mathematically, $d = a_{n} - a_{n-1}$ for all $n > 1$.

Step 2: Calculating the differences between consecutive terms
Let the terms of the sequence be:
$a_1 = a$
$a_2 = 2a$
$a_3 = 3a$
$a_4 = 4a$

Now, calculate the differences:
Difference 1 ($d_1$): $a_2 - a_1 = 2a - a = a$
Difference 2 ($d_2$): $a_3 - a_2 = 3a - 2a = a$
Difference 3 ($d_3$): $a_4 - a_3 = 4a - 3a = a$

Step 3: Verification of the AP
Since $d_1 = d_2 = d_3 = a$, the difference between consecutive terms is constant.
[Since the common difference $d$ is constant, the given sequence is an Arithmetic Progression.]

Step 4: Finding the next three terms
The common difference $d = a$.
To find the next terms, we add $d$ to the last known term ($a_4 = 4a$):
Fifth term ($a_5$): $a_4 + d = 4a + a = 5a$
Sixth term ($a_6$): $a_5 + d = 5a + a = 6a$
Seventh term ($a_7$): $a_6 + d = 6a + a = 7a$

Final Answer:
The sequence forms an AP.
The common difference $d = a$.
The next three terms are $5a, 6a, 7a$.


More Questions from Class 10 Mathematics Arithmetic Progression EXERCISE 5.1


CBSE Solutions for Class 10 Mathematics Arithmetic Progression


Chapters in CBSE - Class 10 Mathematics


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