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FIEM Pursuing
Bachelor of Technology (B.Tech.)
KHAN ACADEMY 2018
SUMMER TEACHER CERTIFICATE
37A, Adiganga Road
Bansdroni
Bansdroni, Kolkata, India - 700070
Landmark: Masterda Surya Sen Metro Station
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Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
5
Board
CBSE, State, ISC/ICSE
Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
5
Board
CBSE, State, ISC/ICSE
Subjects taught
Physics, Mathematics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
5
Board
ICSE, CBSE, State
Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in BCom Tuition
3
BCom Subject
Business Mathematics and Statistics
Type of class
Regular Classes, Crash Course
Class strength catered to
Group Classes
Taught in School or College
No
Answered on 19/06/2019 Learn CBSE - Class 10/Mathematics/Quadratic Equations/NCERT Solutions/Exercise 4.3
Ask a Question
Post a Lesson
According to the problem statement: ________(i)
________(ii)
Putting the value of in equation (i) we get
Like 0 
Answers 13 
Comments Answered on 19/06/2019 Learn CBSE - Class 9
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Post a Lesson
Like 0 Answers 3 Comments Answered on 19/06/2019 Learn CBSE - Class 10/Mathematics/Quadratic Equations/NCERT Solutions/Exercise 4.3
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Post a Lesson
Let Mathematics marks be x and that of English be y,
Solve the following equations: x+y=30____(i)
(x+2)(y-3)=210___(ii)
In equtation (ii) substitute y in terms of x using equation (i), then we get (x+2)(27-x)=210
solving the above quadration equation two possible values(marks) of x(mathematics) exists.
At x=12, y=18 & at x=13, y=17
Like 0 Answers 6 Comments Answered on 19/06/2019 Learn CBSE - Class 10/Mathematics/Quadratic Equations/NCERT Solutions/Exercise 4.1
Ask a Question
Post a Lesson
Like 0 Answers 5 Comments Answered on 07/05/2019 Learn Tuition Fee
Ask a Question
Post a Lesson
Like 0 Answers 48 Comments Ask a Question
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Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
5
Board
CBSE, State, ISC/ICSE
Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
5
Board
CBSE, State, ISC/ICSE
Subjects taught
Physics, Mathematics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
5
Board
ICSE, CBSE, State
Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in BCom Tuition
3
BCom Subject
Business Mathematics and Statistics
Type of class
Regular Classes, Crash Course
Class strength catered to
Group Classes
Taught in School or College
No
Answered on 19/06/2019 Learn CBSE - Class 10/Mathematics/Quadratic Equations/NCERT Solutions/Exercise 4.3
Ask a Question
Post a Lesson
According to the problem statement: ________(i)
________(ii)
Putting the value of in equation (i) we get
Like 0 Answers 13 Comments Answered on 19/06/2019 Learn CBSE - Class 9
Ask a Question
Post a Lesson
Like 0 Answers 3 Comments Answered on 19/06/2019 Learn CBSE - Class 10/Mathematics/Quadratic Equations/NCERT Solutions/Exercise 4.3
Ask a Question
Post a Lesson
Let Mathematics marks be x and that of English be y,
Solve the following equations: x+y=30____(i)
(x+2)(y-3)=210___(ii)
In equtation (ii) substitute y in terms of x using equation (i), then we get (x+2)(27-x)=210
solving the above quadration equation two possible values(marks) of x(mathematics) exists.
At x=12, y=18 & at x=13, y=17
Like 0 Answers 6 Comments Answered on 19/06/2019 Learn CBSE - Class 10/Mathematics/Quadratic Equations/NCERT Solutions/Exercise 4.1
Ask a Question
Post a Lesson
Like 0 Answers 5 Comments Answered on 07/05/2019 Learn Tuition Fee
Ask a Question
Post a Lesson
Like 0 Answers 48 Comments Ask a Question
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