The difference of squares of two numbers is 180. The square of the smaller number is 8 times the larger number. Find the two numbers

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Quantitative aptitude and logical reasoning trainer with more than 6 months of experience.

Supoose two numbers are a and b. ........(1) And ...........(2) Put the value of equation (2) in equation (1) , , , (a+10) (a-18) =0, a= -10 is not possible because cannot be negative , so a= 18 and b= 12. Therefore the larger number is 18 and the smaller number is 12.
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Supoose two numbers are a and b. ........(1) And ...........(2) Put the value of equation (2) in equation (1) , , , (a+10) (a-18) =0, a= -10 is not possible because cannot be negative , so a= 18 and b= 12. Therefore the larger number is 18 and the smaller number is 12. read less
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A NIT Graduate Teacher with passion to Teach and uplift the Students.

18 and 12
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An Engineer

According to the problem statement: ________(i) ________(ii) Putting the value of in equation (i) we get
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According to the problem statement:________(i) ________(ii) Putting the value ofin equation (i) we get read less
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Professional Structural Designer

x2-y2=180 y2= 8 x2-8x-180=0 x=18 y2=18*8=144 y= 12 18,12 and 18,-12
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Best Tuition for CBSE 10 Class Maths!

x=18, y=12
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B.Tech, M.Tech, Delhi, 15 yrs teaching experience engineering maths expert

18 and 12
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Two Numbers are: larger: 18, smaller 12
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Maths and Science Grade 8-10 SSC and CBSE tuitions

Smaller no..12 Larger no ...18
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Computer & maths teacher experience 8years in icse and cbse board

One number is 18 and another 12
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Let the sides of first and second square be X and Y . Area of first square = (X)²And,Area of second square = (Y)²According to question,(X)² + (Y)² = 468 m² ------------(1).Perimeter...
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Find the roots of the following equations:

i) Multiply by x this resembles a Quadratic equation. a=1,b=-3,c=-1 ii) Multiplying both sides by x(x-1)-2(x-1)=0 (x-1)(x-2)=0 x=1 or x=2
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The diagonal of a rectangular field is 60 metres more than the shorter side. If the longer side is 30 metres more than the shorter side, find the sides of the field.
Let the length of the shorter side be x metres. The length of the diagonal= 60+x metres The length of the longer side =30+x metres Applying Pythagoras theorem, Diagonal²=longer side²+shorter...
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