I am taking CAT tuition from Sandip sir. He explains in s very simple manner so that I can easily follow. He takes personal care and I am highly motivated and satisfied. Great teacher.
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Contonment, Kolkata Details verified of Sandip Gupta✕
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Tutor's home I am taking CAT tuition from Sandip sir. He explains in s very simple manner so that I can easily follow. He takes personal care and I am highly motivated and satisfied. Great teacher.
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Bengali Mother Tongue (Native)
Hindi Basic
IIEST 1981
Bachelor of Engineering (B.E.)
Contonment, Kolkata, India - 700028
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Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in BBA Entrance Coaching classes
20+
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
20+
Board
IGCSE, International Baccalaureate, CBSE, State, ICSE
Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
20+
Board
ISC/ICSE, CBSE, IGCSE, State, International Baccalaureate
Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
20+
Board
ISC/ICSE, CBSE, IGCSE, State, International Baccalaureate
Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
20+
Board
ICSE, CBSE, International Baccalaureate, Cambridge Assessment International Education (CAIE), State
Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
20+
Board
IGCSE, International Baccalaureate, CBSE, State, ICSE
Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Engineering Entrance Coaching classes
20+
Engineering Entrance Exams
EAMCET, IIT JEE Coaching Classes, Delhi CEE Coaching Classes, BITSAT Coaching Classes, GATE Coaching Classes
IITJEE Coaching
IIT JEE Crash Course, IIT JEE Integrated Coaching, IIT JEE Foundation Course, IIT JEE Mains Coaching
Type of class
Regular Classes, Crash Course
IIT-JEE Subjects
Maths
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in GMAT Coaching classes
20+
Background
Teacher
Awards and Recognition
Yes
Experience in taking GMAT Exam
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in MBA Entrance Coaching classes
20+
MBA Exams
HP University Management Aptitude Test (HPU-MAT), Karnataka Management Aptitude Test (KMAT), AIMS Test for Management Admissions (ATMA), Symbiosis National Aptitude (SNAP), Tamil Nadu Common Entrance Test (TANCET) Â , MICATÂ , Common Admission Test (CAT), KIITEE Management Test (KIITEE MBA)Â , Common Management Admission Test (CMAT), Management Aptitude Test (MAT), Xavier Aptitude Test (XAT), Telangana State Integrated Common Entrance Test (TSICET), ICFAI Business School Aptitude Test (IBSAT), Odisha Joint Entrance Examination (OJEE) MBA, Andhra Pradesh - Integrated Common Entrance Test (APICET), Indian Institute of Foreign Trade (IIFT) Exam, Maharashtra Common Entrance Test (MAH-CET), NMAT by GMAC
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in SAT Coaching classes
20+
5 out of 5 1 review
Rupanjali Paul
"I am taking CAT tuition from Sandip sir. He explains in s very simple manner so that I can easily follow. He takes personal care and I am highly motivated and satisfied. Great teacher. "
Reply by Sandip
Thanks a lot.
Have you attended any class with Sandip?
Answered on 23/08/2019 Learn CBSE - Class 10/Mathematics/UNIT VII: Statistics and probability/Probability/NCERT Solutions/Exercise 15.1
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Post a Lesson
Probability that two students are not having same birthday P (
) = 0.992
Probability that two students are having same birthday P (E) = 1 − P ()
= 1 − 0.992
= 0.008
Like 0 
Answers 2 
Comments Answered on 17/08/2019 Learn CBSE - Class 10/Mathematics/Quadratic Equations/NCERT Solutions/Exercise 4.4
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Post a Lesson
Like 0 Answers 3 Comments Answered on 07/08/2019 Learn Teaching Jobs
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Like 0 Answers 6 Comments Answered on 19/07/2019 Learn CBSE - Class 10/Mathematics/Arithmetic Progression/NCERT Solutions/Exercise 5.2
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First term =a; common difference = d; number of terms = n; n th term = tn = a+(n-+).d.
So, sum of 4th and 8th terms = a+(4-1).d + a+(8-1).d = 2a+10d =24 (given) .... ( i)
Sum of 6th and 10th terms = a+(6-1)d + a+(10-1)d = 2a + 14d = 44 ....( ii)
By ( ii) - ( i), 4d = 20, or, d =5.
So, putting d in ( i), 2a+ 50 = 24,
Or, 2a = - 26, or, a = -13.
So, the first 3 terms of the AP are: a, a+d, a+2d = -13,-8,-3 ( Ans)
Like 0 Answers 1 Comments Answered on 19/07/2019 Learn CBSE - Class 10/Mathematics/Arithmetic Progression/NCERT Solutions/Exercise 5.2
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Post a Lesson
Let the first terms of the two APs be a and b and the common difference of each be d. If number of terms = n and n th term is tn, then, tn = a+(n-1).d and b+(n-1)d.
So, difference between the 100th terms = [ a+(100-1).d] -[b +(100-1)d] = (a+99d) -(b+99d) = 100 (given), or, a- b = 100 ... ( i)
So, the difference between the 1000th terms =[a+(1000-1)d] - [b+(1000-1)d] = a - b =100 (Ans) [from ( i)].
Ans : 100
Like 0 Answers 1 Comments Ask a Question
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Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in BBA Entrance Coaching classes
20+
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
20+
Board
IGCSE, International Baccalaureate, CBSE, State, ICSE
Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
20+
Board
ISC/ICSE, CBSE, IGCSE, State, International Baccalaureate
Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
20+
Board
ISC/ICSE, CBSE, IGCSE, State, International Baccalaureate
Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
20+
Board
ICSE, CBSE, International Baccalaureate, Cambridge Assessment International Education (CAIE), State
Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
20+
Board
IGCSE, International Baccalaureate, CBSE, State, ICSE
Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Engineering Entrance Coaching classes
20+
Engineering Entrance Exams
EAMCET, IIT JEE Coaching Classes, Delhi CEE Coaching Classes, BITSAT Coaching Classes, GATE Coaching Classes
IITJEE Coaching
IIT JEE Crash Course, IIT JEE Integrated Coaching, IIT JEE Foundation Course, IIT JEE Mains Coaching
Type of class
Regular Classes, Crash Course
IIT-JEE Subjects
Maths
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in GMAT Coaching classes
20+
Background
Teacher
Awards and Recognition
Yes
Experience in taking GMAT Exam
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in MBA Entrance Coaching classes
20+
MBA Exams
HP University Management Aptitude Test (HPU-MAT), Karnataka Management Aptitude Test (KMAT), AIMS Test for Management Admissions (ATMA), Symbiosis National Aptitude (SNAP), Tamil Nadu Common Entrance Test (TANCET) Â , MICATÂ , Common Admission Test (CAT), KIITEE Management Test (KIITEE MBA)Â , Common Management Admission Test (CMAT), Management Aptitude Test (MAT), Xavier Aptitude Test (XAT), Telangana State Integrated Common Entrance Test (TSICET), ICFAI Business School Aptitude Test (IBSAT), Odisha Joint Entrance Examination (OJEE) MBA, Andhra Pradesh - Integrated Common Entrance Test (APICET), Indian Institute of Foreign Trade (IIFT) Exam, Maharashtra Common Entrance Test (MAH-CET), NMAT by GMAC
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in SAT Coaching classes
20+
5 out of 5 1 review
Rupanjali Paul
"I am taking CAT tuition from Sandip sir. He explains in s very simple manner so that I can easily follow. He takes personal care and I am highly motivated and satisfied. Great teacher. "
Reply by Sandip
Thanks a lot.
Have you attended any class with Sandip?
Answered on 23/08/2019 Learn CBSE - Class 10/Mathematics/UNIT VII: Statistics and probability/Probability/NCERT Solutions/Exercise 15.1
Ask a Question
Post a Lesson
Probability that two students are not having same birthday P () = 0.992
Probability that two students are having same birthday P (E) = 1 − P ()
= 1 − 0.992
= 0.008
Like 0 Answers 2 Comments Answered on 17/08/2019 Learn CBSE - Class 10/Mathematics/Quadratic Equations/NCERT Solutions/Exercise 4.4
Ask a Question
Post a Lesson
Like 0 Answers 3 Comments Answered on 07/08/2019 Learn Teaching Jobs
Ask a Question
Post a Lesson
Like 0 Answers 6 Comments Answered on 19/07/2019 Learn CBSE - Class 10/Mathematics/Arithmetic Progression/NCERT Solutions/Exercise 5.2
Ask a Question
Post a Lesson
First term =a; common difference = d; number of terms = n; n th term = tn = a+(n-+).d.
So, sum of 4th and 8th terms = a+(4-1).d + a+(8-1).d = 2a+10d =24 (given) .... ( i)
Sum of 6th and 10th terms = a+(6-1)d + a+(10-1)d = 2a + 14d = 44 ....( ii)
By ( ii) - ( i), 4d = 20, or, d =5.
So, putting d in ( i), 2a+ 50 = 24,
Or, 2a = - 26, or, a = -13.
So, the first 3 terms of the AP are: a, a+d, a+2d = -13,-8,-3 ( Ans)
Like 0 Answers 1 Comments Answered on 19/07/2019 Learn CBSE - Class 10/Mathematics/Arithmetic Progression/NCERT Solutions/Exercise 5.2
Ask a Question
Post a Lesson
Let the first terms of the two APs be a and b and the common difference of each be d. If number of terms = n and n th term is tn, then, tn = a+(n-1).d and b+(n-1)d.
So, difference between the 100th terms = [ a+(100-1).d] -[b +(100-1)d] = (a+99d) -(b+99d) = 100 (given), or, a- b = 100 ... ( i)
So, the difference between the 1000th terms =[a+(1000-1)d] - [b+(1000-1)d] = a - b =100 (Ans) [from ( i)].
Ans : 100
Like 0 Answers 1 Comments Ask a Question
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