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Asked by Abdul Last Modified
Answer Because there is data type mismatch between the actual and formal parameters.
In the method declaration for zool(), you have declared variable a as type int and variable b as type String. Here a and b are not the actual values. They are the formal parameters which will receive the actual values when the method is invoked.
When you invoked zool() inside the main method, you passed two random characters.
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Facing errors while invoking a method in Java can occur due to various reasons. It's important to analyze the specific error message and understand the context in which it occurs to determine the root cause. Here are some common reasons for encountering errors when invoking a method in Java:
1. Compilation Error
2. Null point exception
3. Method Signature Mismatch
4. Classpath Issues:
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