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Tanya S.

Bilhari, Jabalpur, India - 482020

Tanya S. Class I-V Tuition trainer in Jabalpur

Tanya S.

Bilhari, Jabalpur, India - 482020.

3.1

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Education

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Overview

Hello this is tanya... Basically i m student but as i love teaching i m here i give home tution as well as online too... I m currently in 3rd year of bsc... And i know studies can be fun if done in a good way..

Languages Spoken

Hindi Proficient

English Proficient

Education

St Aloysius college Pursuing

Bachelor of Science (B.Sc.)

Address

Bilhari, Jabalpur, India - 482020

Verified Info

Phone Verified

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Class I-V Tuition

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class I-V Tuition

2

Board

ICSE, CBSE, State

CBSE Subjects taught

Mathematics, English, Sanskrit, Science, EVS, Social Science, Hindi

ICSE Subjects taught

EVS, English, Sanskrit, Mathematics, Science, Hindi, Social Studies

Taught in School or College

No

State Syllabus Subjects taught

Social Science, EVS, English, Sanskrit, Hindi, Science, Mathematics

Reviews

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FAQs

1. Which school boards of Class 1-5 do you teach for?

ICSE, CBSE and State

2. Have you ever taught in any School or College?

No

3. Which classes do you teach?

I teach Class 10 Tuition, Class 11 Tuition and Class I-V Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 2 years.

Answers by Tanya S. (1)

Answered on 29 Jun CBSE/Class 11

We need ∫logxdx∫log xdx It can be done by using integration by parts, i.e., ∫udv=uv−∫vdu∫udv=uv−∫vdu By ILATE, log function should have more priority than algebraic function, So, u=logx,u=log x, dv=dx⇒v=xdv=dx⇒v=x So, ∫logxdx=logx.(x)−∫x.(logx)′∫log... ...more

We need logxdx∫log⁡xdx

It can be done by using integration by parts,

i.e., udv=uvvdu∫udv=uv−∫vdu

By ILATE, log function should have more priority than algebraic function,

So, u=logx,u=log⁡x,

dv=dxv=xdv=dx⇒v=x

So, logxdx=logx.(x)x.(logx)∫log⁡xdx=log⁡x.(x)−∫x.(log⁡x)′

xlogxx.1xdx⇒xlog⁡x−∫x.1xdx

xlogxdx⇒xlog⁡x−∫dx

xlogxx+C⇒xlog⁡x−x+C

logxdx=xlogxx+C∴∫log⁡xdx=xlog⁡x−x+C

Where C is the integration constant.

Answers 218 Comments
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Class I-V Tuition 3.1

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class I-V Tuition

2

Board

ICSE, CBSE, State

CBSE Subjects taught

Mathematics, English, Sanskrit, Science, EVS, Social Science, Hindi

ICSE Subjects taught

EVS, English, Sanskrit, Mathematics, Science, Hindi, Social Studies

Taught in School or College

No

State Syllabus Subjects taught

Social Science, EVS, English, Sanskrit, Hindi, Science, Mathematics

Class 10 Tuition 3.1

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 10 Tuition

2

Board

State, CBSE, ICSE

CBSE Subjects taught

English, Hindi, Sanskrit, Social science, Mathematics, Science

ICSE Subjects taught

Sanskrit, English Literature, Mathematics, Chemistry, History and Civics, Hindi, Biology, EVS, Geography, Home Science, English

Experience in School or College

Its was just awesome while teaching i not only teach i get to know a lot i learn alot and just my students are my friends

Taught in School or College

Yes

State Syllabus Subjects taught

English, Sanskrit, Science, Hindi, Mathematics, Social Science, EVS

Class 11 Tuition 3.1

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 11 Tuition

2

Board

State, CBSE, ISC/ICSE

ISC/ICSE Subjects taught

Mathematics, Geography, History, EVS, English, Chemistry, English Literature, Hindi, Biology

CBSE Subjects taught

Hindi, English, Geography, History, Home Science, Biology, Chemistry, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Hindi, History, Chemistry, Biology, Sanskrit, English, Geography, Home Science

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Answers by Tanya S. (1)

Answered on 29 Jun CBSE/Class 11

We need ∫logxdx∫log xdx It can be done by using integration by parts, i.e., ∫udv=uv−∫vdu∫udv=uv−∫vdu By ILATE, log function should have more priority than algebraic function, So, u=logx,u=log x, dv=dx⇒v=xdv=dx⇒v=x So, ∫logxdx=logx.(x)−∫x.(logx)′∫log... ...more

We need logxdx∫log⁡xdx

It can be done by using integration by parts,

i.e., udv=uvvdu∫udv=uv−∫vdu

By ILATE, log function should have more priority than algebraic function,

So, u=logx,u=log⁡x,

dv=dxv=xdv=dx⇒v=x

So, logxdx=logx.(x)x.(logx)∫log⁡xdx=log⁡x.(x)−∫x.(log⁡x)′

xlogxx.1xdx⇒xlog⁡x−∫x.1xdx

xlogxdx⇒xlog⁡x−∫dx

xlogxx+C⇒xlog⁡x−x+C

logxdx=xlogxx+C∴∫log⁡xdx=xlog⁡x−x+C

Where C is the integration constant.

Answers 218 Comments
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Tanya S. conducts classes in Class 10 Tuition, Class 11 Tuition and Class I-V Tuition. Tanya is located in Bilhari, Jabalpur. Tanya takes at students Home, Regular Classes- at her Home and Online Classes- via online medium. She has 2 years of teaching experience . Tanya is pursuing Bachelor of Science (B.Sc.) from St Aloysius college . She is well versed in Hindi and English.

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