Bilhari, Jabalpur, India - 482020.
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Hindi Proficient
English Proficient
St Aloysius college Pursuing
Bachelor of Science (B.Sc.)
Bilhari, Jabalpur, India - 482020
Phone Verified
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
2
Board
ICSE, CBSE, State
Subjects taught
Sanskrit, Social studies, EVS, Hindi, Science, Mathematics, Social Science, English
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
2
Board
State, ICSE, CBSE
Experience in School or College
Its was just awesome while teaching i not only teach i get to know a lot i learn alot and just my students are my friends
Subjects taught
Chemistry, Science, Mathematics, English Literature, Sanskrit, Geography, Home Science, English, History and Civics, Hindi, Social Science, EVS, Biology
Taught in School or College
Yes
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
2
Board
State, CBSE, ISC/ICSE
Subjects taught
Home Science, Chemistry, Hindi, Sanskrit, History, Mathematics, Biology, Geography, EVS, English, English Literature
Taught in School or College
No
1. Which school boards of Class 1-5 do you teach for?
ICSE, CBSE and State
2. Have you ever taught in any School or College?
No
3. Which classes do you teach?
I teach Class 10 Tuition, Class 11 Tuition and Class I-V Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 2 years.
Answered on 29/06/2020 Learn CBSE/Class 11
We need ∫logxdx∫logxdx
It can be done by using integration by parts,
i.e., ∫udv=uv−∫vdu∫udv=uv−∫vdu
By ILATE, log function should have more priority than algebraic function,
So, u=logx,u=logx,
dv=dx⇒v=xdv=dx⇒v=x
So, ∫logxdx=logx.(x)−∫x.(logx)′∫logxdx=logx.(x)−∫x.(logx)′
⇒xlogx−∫x.1xdx⇒xlogx−∫x.1xdx
⇒xlogx−∫dx⇒xlogx−∫dx
⇒xlogx−x+C⇒xlogx−x+C
∴∫logxdx=xlogx−x+C∴∫logxdx=xlogx−x+C
Where C is the integration constant.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
2
Board
ICSE, CBSE, State
Subjects taught
Sanskrit, Social studies, EVS, Hindi, Science, Mathematics, Social Science, English
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
2
Board
State, ICSE, CBSE
Experience in School or College
Its was just awesome while teaching i not only teach i get to know a lot i learn alot and just my students are my friends
Subjects taught
Chemistry, Science, Mathematics, English Literature, Sanskrit, Geography, Home Science, English, History and Civics, Hindi, Social Science, EVS, Biology
Taught in School or College
Yes
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
2
Board
State, CBSE, ISC/ICSE
Subjects taught
Home Science, Chemistry, Hindi, Sanskrit, History, Mathematics, Biology, Geography, EVS, English, English Literature
Taught in School or College
No
Answered on 29/06/2020 Learn CBSE/Class 11
We need ∫logxdx∫logxdx
It can be done by using integration by parts,
i.e., ∫udv=uv−∫vdu∫udv=uv−∫vdu
By ILATE, log function should have more priority than algebraic function,
So, u=logx,u=logx,
dv=dx⇒v=xdv=dx⇒v=x
So, ∫logxdx=logx.(x)−∫x.(logx)′∫logxdx=logx.(x)−∫x.(logx)′
⇒xlogx−∫x.1xdx⇒xlogx−∫x.1xdx
⇒xlogx−∫dx⇒xlogx−∫dx
⇒xlogx−x+C⇒xlogx−x+C
∴∫logxdx=xlogx−x+C∴∫logxdx=xlogx−x+C
Where C is the integration constant.
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