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IIT JEE Coaching

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C

Chetana 13 May in  IIT JEE Coaching classes

Write three important factors which justify the need of modulating a message signal. Show diagrammatically how an amplitude modulate wave is obtained when a modulating signal is superimposed on a carrier wave.

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Quest Academy replied | 13 May

Three important factors which justify the need of modulating a message signal:
1. Size of antenna or aerial: For communication within the effective length of the antennas, the transmitting frequencies should be high, so modulation is required.
2. Effective power which is radiated by antenna: Since the power radiated from a linear antenna is inversely proportional to the...  more»
Three important factors which justify the need of modulating a message signal:
1. Size of antenna or aerial: For communication within the effective length of the antennas, the transmitting frequencies should be high, so modulation is required.
2. Effective power which is radiated by antenna: Since the power radiated from a linear antenna is inversely proportional to the square of the transmitting wavelength. As high powers are needed for good transmission so, higher frequency is required which can be achieved by modulation.
3. The interference of signals from different transmitters: To avoid the interference of the signals there is need of high frequency which can be achieved by the modulation. «less

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Antesh Chirag replied | 13 May

In order to obtain only low frequency signal (a) it will need antenna of very large length i.e. 5 kms (b) get significant attenuation since power radiated by antenna is inversely proportional to square of wave length (c) mixing up of transmitted signals emitted from different stations

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P

Priya 13 May in  IIT JEE Coaching classes

Using Bohr’s postulates, obtain the expression for the total energy of the electron in the stationary states of the hydrogen atom. Hence draw the energy level diagram showing how the line spectra corresponding to Balmer series occur due to transition between energy levels.

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Chaitanya replied | 07 Jun

The answer to the query that you have posted can be found in the NCERT text book Part II.
Kindly refer to page number 424 and 425 for your answer.
Also, the energy level diagram can be found on page number 429.

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Birjesh Choudhary replied | 05 Jul

I hope this would clarify your doubt.

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A

Aditi 13 May in  IIT JEE Coaching classes

Distinguish between myopia and hypermetropia.

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Ritul replied | 13 May

Myopia is short sightedness( one can easily see nearby objects clearly & has problems in seeing objects which are far) whereas hypermetropia is long sightedness ( the eye cannot focus clearly on the objects at shorter distance).
Myopia happens usually because of deficiencies in the body or due to other external factors like over use light emitting devices, reading from very...  more»
Myopia is short sightedness( one can easily see nearby objects clearly & has problems in seeing objects which are far) whereas hypermetropia is long sightedness ( the eye cannot focus clearly on the objects at shorter distance).
Myopia happens usually because of deficiencies in the body or due to other external factors like over use light emitting devices, reading from very close range etc. Whereas hypermetropia is usually genetic in nature. «less

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Shivaji replied | 15 Jun

Both Myopia (short-sightedness) and Hypermetropia (long-sightedness) are common eye conditions that mean light does not focus on the retina of the eye. Both conditions can be easily corrected using prescription glasses or contact lenses or in mild cases by laser eye surgery.

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P

Prabhu 13 May in  IIT JEE Coaching classes

Why are OH, NH, and FH bonds so polar?

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Dr.s replied | 13 May

Because the ddifference of electonegetivity of O and H, N and H and F and H is very high, which cause the pulling of shared electron pair clouds towards most eelectronegative atom.

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Shivaji replied | 15 Jun

Hydrogen atoms are very small (with an atomic radius of about 37 pm, they're smaller than any other atom but helium). So when a bonded electronegative atom pulls electrons away from the hydrogen atom, the positive charge that results is tightly concentrated. The small size of the hydrogen atom is one factor responsible for the unusual strength of the dipole-dipole interaction we...  more»
Hydrogen atoms are very small (with an atomic radius of about 37 pm, they're smaller than any other atom but helium). So when a bonded electronegative atom pulls electrons away from the hydrogen atom, the positive charge that results is tightly concentrated. The small size of the hydrogen atom is one factor responsible for the unusual strength of the dipole-dipole interaction we call "hydrogen bonding". «less

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M

Mukesh 12 May in  IIT JEE Coaching classes

Which of the following waves can be polarized (i) Heat waves (ii) Sound waves?

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U.k. replied | 13 May

Heat waves can be polarized because heat waves are transverse waves whereas sound waves cannot be polarized because sound waves are longitudinal waves.

Transverse waves can oscillate in the direction perpendicular to the direction of its propagation but sound waves oscillate only along the direction of its propagation. So,sound waves cannot be polarized.

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Quest Academy replied | 13 May

Heat waves can be polarized because heat waves are transverse waves whereas sound waves cannot be polarized because sound waves are longitudinal waves.

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Answer

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P

Prasad 12 May in  IIT JEE Coaching classes

State Lenz’s Law. A metallic rod held horizontally along east-west direction, is allowed to fall under gravity. Will there be an emf induced at its ends? Justify your answer.

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Birjesh Choudhary replied | 05 Jul

The vertical component of earth's magnetic field will be cut by the movement of the horizontal rod,so a motional emf will be generated across the ends of the rod.

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Amit replied | 08 Jul

yes, Because earth horizontal magentic field is from south to north, and because of gain in vel due to fall there will be induced emf vBl (vel * horizontal earth magnetic field * lenght of rod)

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Answer

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P

Poonam 12 May in  IIT JEE Coaching classes

A capacitor has been charged by a dc source. What are the magnitudes of conduction and displacement currents, when it is fully charged?

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Chaitanya replied | 07 Jun

Electric flux through the plates of the capacitor is given by,
? = q/?0 .(1)
Value of q is constant when capacitor is fully charged.
Hence from (1), ? will also be constant.
Displacement current = ID = ?0 (d? / dt) = 0 (? ? is constant)
Conduction current = Ic = C (dV/dt) = 0 (? V is constant)
? Ic = ID = 0 when...  more»
Electric flux through the plates of the capacitor is given by,
? = q/?0 …………….(1)
Value of q is constant when capacitor is fully charged.
Hence from (1), ? will also be constant.
Displacement current = ID = ?0 (d? / dt) = 0 (? ? is constant)
Conduction current = Ic = C (dV/dt) = 0 (? V is constant)
? Ic = ID = 0 when the capacitor is fully charged. «less

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C

Chitra 12 May in  IIT JEE Coaching classes

The given graph shows the variation of photo-electric current (I) versus applied voltage (V) for two different photosensitive materials and for two different intensities of the incident radiation. Identify the pairs of curves that correspond to different materials but same intensity of incident radiation.

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Chaitanya replied | 07 Jun

Curves 1 and 2 represent same materials while curves 3 and 4 represent different materials, since the value of stopping potential for the pair of curves (1 & 2) and (3 & 4) are same.
For the given frequency of the incident radiation the stopping potential is independent of its intensity.
So the pair of curves (1 & 3) and (2 & 4) correspond to different materials but same...  more»
Curves 1 and 2 represent same materials while curves 3 and 4 represent different materials, since the value of stopping potential for the pair of curves (1 & 2) and (3 & 4) are same.
For the given frequency of the incident radiation the stopping potential is independent of its intensity.
So the pair of curves (1 & 3) and (2 & 4) correspond to different materials but same intensity of incident radiation. «less

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N

Neelima 12 May in  IIT JEE Coaching classes

A convex lens of focal length 25 cm is placed coaxially in contact with a concave lens of focal length 20 cm. Determine the power of the combination. Will the system be converging or diverging in nature?

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Bikramjeet replied | 13 May

power will be -1Dioptre..as P= 1/F..for convex lens it is + 25 cm and for concave it is -20cm,,...as power is in -ve, combination will be diverging

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Quest Academy replied | 13 May

We have focal length of convex lens,
f1 = +25 cm or +0.25 m and the focal length of concave lens (f2) = -20 cm or -0.20 m
Equivalent focal length F= 1/f1 + 1/f2 = 1/0.25 + 1/-0.20 = -1/100
Therefore F= -100 cm
Power of convex lens P1 = 1/f1 = 1/0.25
Power of concave lens P2 = 1/f2 = 1/-0.20
Power of the combination P = P1 + P2 = 1/0.25 +1/-0.20 = -1D
The...  more»
We have focal length of convex lens,
f1 = +25 cm or +0.25 m and the focal length of concave lens (f2) = -20 cm or -0.20 m
Equivalent focal length F= 1/f1 + 1/f2 = 1/0.25 + 1/-0.20 = -1/100
Therefore F= -100 cm
Power of convex lens P1 = 1/f1 = 1/0.25
Power of concave lens P2 = 1/f2 = 1/-0.20
Power of the combination P = P1 + P2 = 1/0.25 +1/-0.20 = -1D
The focal length of the combination = ?1 m = ?100 cm.
As the focal length is in negative, the system will be diverging in nature. «less

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T

Thamaraikannan 11 May in  IIT JEE Coaching classes

What ate permanent magnets? Give one example

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Praveen Kumar Rao replied | 12 May

An object made from a material that is magnetized and creates its own magnetic field.
Eg: Refrigerator magnet used to hold notes on a refrigerator door.

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Bikramjeet replied | 13 May

as it clear from the name magnet which donot loss its magnetic properties in the absence of current or induced field,earth is good example

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H

Himanshu 11 May in  IIT JEE Coaching classes

What is the geometrical shape of equipotential surfaces due to a single isolated charge?

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Praveen Kumar Rao replied | 12 May

sphere centered on the point charge

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Quest Academy replied | 13 May

For an isolated charge the equipotential surfaces are co-centric spherical shells and the distance between the shells increases with the decrease in electric field.

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Answer

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V

Vikna 11 May in  IIT JEE Coaching classes

Define mutual inductance and write its S.I. units.

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U.k. replied | 11 May

units of mutual inductance is Henry

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U.k. replied | 11 May

If two coils of wire are brought into close proximity with each other so the magnetic field from one links with the other then a voltage is generated in the second coil. This phenomenon is called mutual inductance: when voltage is applied in one coil it induces a voltage in another.

example : transformer

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Answer

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N

Name 10 May in  IIT JEE Coaching classes

In a double slit experiment using light of wavelength 600 nm, the angular width of the fringe formed on a distant screen is 0.1°. Find the spacing between the two slits.

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Dr K Venkateswarlu replied | 12 Jun

Fringe Width (w)=(lamda X D)/(slit seperation=2d) wher D is seperation b/w plane of slits and screen. therefore 2d=(lamda X D)/w. but for large values of D, angular width (theta in radians)= w/D. Hence finally 2d=lamda/(theta in radians). substituting the given values we get 2d=0.34 mm

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Dr K Venkateswarlu replied | 12 Jun

Spacing b/w two slits (2d)= (lamda)/(theta in radians), where theta is angular width in radians. So substituting the given values, 2d= 0.34 mm

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Answer

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U.k. 12 May in  IIT JEE Coaching classes

Which of the following waves can be polarized (i) Heat waves (ii) Sound waves? Give reason to support your answer.

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Shivaji replied | 08 Jun

heat waves can be polarized because heat waves are transverse waves whereas sound waves cannot be polarized because sound waves are longitudinal waves
Transverse waves can be oscillate in the direction perpendicular to the direction of its propagation but longitudinal waves like sound waves oscillate only along the direction of its propagation , so longitudinal waves cannot be polarized

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Answer

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U.k. 12 May in  IIT JEE Coaching classes

A capacitor has been charged by a dc source. What are the magnitude of conduction and displacement current, when it is fully charged?

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Chaitanya replied | 07 Jun

Ans. Electric flux through plates of capacitor, ?E ? q .

? o

Here, q ? constant, the capacitor is fully charged.

? q ?
d ?

d?E ? ?
Displacement current , ID ??? ??? ? o ? ? 0
o dt o dt


Conduction current, I ? C dVdt

when...  more»
Ans. Electric flux through plates of capacitor, ?E ? q .

? o

Here, q ? constant, the capacitor is fully charged.

? q ?
d ?

d?E ? ?
Displacement current , ID ??? ??? ? o ? ? 0
o dt o dt


Conduction current, I ? C dVdt

when the capacitor becomes fully charged.

Transverse waves can oscillate in the direction perpendicular to the direction of its propagation but longitudinal waves like sound waves oscillate only along the direction of its propagation. So, longitudinal waves cannot be polarized «less

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Answer

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U.k. 12 May in  IIT JEE Coaching classes

Write the relationship between angle of incidence “i”™, angle of prism “A”™ and angle of minimum deviations for a triangular prism.

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Chaitanya replied | 07 Jun

i=A+delta m/2

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Birjesh Choudhary replied | 12 Jul

Angle of deviation for a prism is,
D= i+e-A
For minimum deviation,i=e
Dmin = 2i-A

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Answer

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U.k. 12 May in  IIT JEE Coaching classes

A capacitor has been charged by a dc source. What are the magnitude of conduction and displacement current, when it is fully charged?

0 0

Chaitanya replied | 07 Jun

Ans. Electric flux through plates of capacitor, ?E ? q .

? o

Here, q ? constant, the capacitor is fully charged.

? q ?
d ?

d?E ? ?
Displacement current , ID ??? ??? ? o ? ? 0
o dt o dt


Conduction current, I ? C dVdt

when...  more»
Ans. Electric flux through plates of capacitor, ?E ? q .

? o

Here, q ? constant, the capacitor is fully charged.

? q ?
d ?

d?E ? ?
Displacement current , ID ??? ??? ? o ? ? 0
o dt o dt


Conduction current, I ? C dVdt

when the capacitor becomes fully charged.

Transverse waves can oscillate in the direction perpendicular to the direction of its propagation but longitudinal waves like sound waves oscillate only along the direction of its propagation. So, longitudinal waves cannot be polarized «less

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Answer

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U.k. 12 May in  IIT JEE Coaching classes

A metallic rod held horizontally along east-west direction, is allowed to fall under gravity. Will there be an emf induced at its ends? Justify your answer.

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Chaitanya replied | 07 Jun

when a metalic rod is held horizantally along east-west direction,is allowed to fall under gravity i.e. it falls from north to south,the intensity of magnetic lines of earth's magnetic field changes through it i.e. the magnetic flux changes and hence the induced emf in it.

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Answer

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U.k. 12 May in  IIT JEE Coaching classes

A convex lens of focal length 25 cm is placed coaxially in contact with a concave lens of focal length 20 cm. Determine the power of the combination. Will the system be converging or diverging in nature?

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Chaitanya replied | 07 Jun

f1=0.25m,f2=-0.20m,F=(1/f1)+(1/f2)=-1m
since the focal length is negative,system will be diverging in nature.

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Birjesh Choudhary replied | 05 Jul

Total power is the sum of the powers of lenses in contact.
P=P1+P2
focal length=1/(Power of lens)
Total Power= 1/.25 + 1/(-.2) =-1D
Since, power is negative, the system will act a diverging lens.

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Answer

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S

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Chaitanya replied | 10 May

These are impure semiconductors . When a small quantity of impurity is mixed in a pure or intrinsic conductor , conductivity of semiconductor increases . Such an impure semiconductor is called extrinsic semiconductor

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U.k. replied | 11 May

Intrinsic Semiconductor :
1.)These are pure semiconductor without any significant dopant species present. it is also called i-type semicondoctor. The number of charge carriers is therefore determined by the properties of the material itself instead of the amount of impurities.
2.) Conductivity of intrinsic semiconductors is poor .
3.) Number of electrons in conduction...  more»
Intrinsic Semiconductor :
1.)These are pure semiconductor without any significant dopant species present. it is also called i-type semicondoctor. The number of charge carriers is therefore determined by the properties of the material itself instead of the amount of impurities.
2.) Conductivity of intrinsic semiconductors is poor .
3.) Number of electrons in conduction band and holes in valence band are approximately equal .
4.) Fermi energy level lies at the centre of forbidden energy gap.

Extrinsic Semiconductors :
1.) These are impure semiconductors . When a small quantity of impurity is mixed in a pure or intrinsic conductor , conductivity of semiconductor increases . Such an impure semiconductor is called extrinsic semiconductor.
2.) Conductivity of extrinsic semiconductors is large.
3.) If it is an n-type semiconductor , electrons are majority carrier and holes are minority carrier and if it is a p-type semiconductor ,holes are majority carrier and electrons are minority carrier.
4.) In n-type semiconductor,Fermi-level lies near the bottom of conductioin band and in p-type semiconductor, fermi - level lies near the top of valence band . «less

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Answer

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R

Rekha 10 May in  IIT JEE Coaching classes

How are side bands produced ?

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Quest Academy replied | 10 May

Side bands are produced by the method of amplitude modulation. It produces two new frequencies (fc + fm) and (fc – fm) around original frequency (fc), which are called side band frequencies.
Upper side band frequency = USB = fc + fm
and Lower side band frequency = LSB = fc – fm.

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U.k. replied | 11 May

A sideband is a band of frequencies higher than or lower than the carrier frequency which contain power as a result of the modulation process. All forms of modulation produce sidebands.
he signal components above the carrier frequency constitute the upper sideband (USB), and those below the carrier frequency constitute the lower sideband (LSB).

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Answer

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Y

Yashraj 10 May in  IIT JEE Coaching classes

Find an expression for intensity of transmitted light when a polaroid sheet is rotated between two crossed polaroids. In which position of the polaroid sheet will the transmitted intensity be maximum ?

1 0

Shivaji replied | 09 Jun

The plane-polarised light is the light in which the vibrations of the electric vector occurring in a
plane perpendicular to direction of propagation of light are confined to a single direction in the plane .
Let intensity of light after passing through polarizer P1 is I0 , then intensity of light I1 after passing
through P2, according to Malus law
For I2 is to...  more»
The plane-polarised light is the light in which the vibrations of the electric vector occurring in a
plane perpendicular to direction of propagation of light are confined to a single direction in the plane .
Let intensity of light after passing through polarizer P1 is I0 , then intensity of light I1 after passing
through P2, according to Malus law
For I2 is to be maximum
2
sin 2? should be maximum which gives,
45
4
? «less

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Answer

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N

Navneet 10 May in  IIT JEE Coaching classes

Use Kirchhoff’s rules to obtain conditions for the balance condition in a Wheatstone bridge.

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Chaitanya replied | 10 May

R1/R3=R2/R4

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Nakshatratuitions And replied | 11 May

Yes

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B

Bindu 09 May in  IIT JEE Coaching classes

Show previous answers

Chaitanya replied | 10 May

Xc=1/wc, si unit ohm

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U.k. replied | 11 May

In an AC circuit in which the applied voltage signal is continually changing from a positive to a negative polarity at a rate determined by the frequency of the supply, as in the case of a sine wave voltage, for example, the capacitor is either being charged or discharged on a continuous basis at a rate determined by the supply frequency.
As the capacitor charges or discharges,...  more»
In an AC circuit in which the applied voltage signal is continually changing from a positive to a negative polarity at a rate determined by the frequency of the supply, as in the case of a sine wave voltage, for example, the capacitor is either being charged or discharged on a continuous basis at a rate determined by the supply frequency.
As the capacitor charges or discharges, a current flows through it which is restricted by the internal resistance of the capacitor. This internal resistance is commonly known as Capacitive Reactance.
it is inversely proportional to the angular frequency and the capacitance and is due to the presence of capacitance in an alternating-current circuit.

its S.I. unit is in Ohms. «less

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J

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Smita replied | 11 May

Since refractive index of lens is less than refractive index of surroundings, it will behave as a convex lens.

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Natarajan replied | 11 Jul

from this problem we may knoq that the refractive index of the given lens is less than the refractive index of surroundings, so it will behave as a convex lens.

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