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Vanga Goutham Reddy Class 12 Tuition trainer in Hyderabad

Vanga Goutham Reddy

locationImg Begumpet, Hyderabad
1 yrs of Exp
students 1 student
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I am a engineering graduate student . I am good at all subjects. I am graduated from JNTUH. I want to teach the tuitions as I want to share my knowledge to other students.

Languages Spoken

Telugu Mother Tongue (Native)

English Proficient

Hindi Proficient

Education

Anurag group of institutions 2018

Bachelor of Technology (B.Tech.)

Address

Begumpet, Hyderabad, India - 500016

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Teaches

Class 12 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

1

Board

State, International Baccalaureate, ISC/ICSE, CBSE

Subjects taught

Engineering Graphics, Chemistry, Sanskrit, Economics, Computer Science, Electronics, Political Science, English, Geography, Telugu, History, Biology, Physics, Mathematics

Taught in School or College

No

Class 10 Tuition
1 Student

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

ICSE, CBSE, State

Subjects taught

Economic Application, English Literature, History and Civics, Telugu, Science, Chemistry, Physics, Biology, Sanskrit, Geography, English, Mathematics, Social Science

Taught in School or College

No

Class 11 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

State, ISC/ICSE, CBSE

Subjects taught

Mathematics, Engineering Graphics, Chemistry, Biotechnology, Physics, Telugu, History, English, Economics, Electronics, Biology, Geography, Computer Science

Taught in School or College

No

BTech Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in BTech Tuition

1

BTech Electrical & Electronics subjects

(Dc- Ac) Direct Current-Alternatiing Current System Interaction, Electromagnetic Theory, Design Of Embedded Controllers, High-Voltage Direct Current (Hvdc) Transmission, Analog And Digital Communication, Switchgear And Protection, Embedded Processor Architecture, Power System Protection, Regulation & Security, Direct Energy Conversion, Applications of Digital Signal Processing (DSP), Control Systems, Electrical Circuit Analysis, Alternative Energy Sources, Circuit Theory, Discrete Fourier Transforms And Digital Filter Design, High-Voltage Engineering, Power System Engineering, Electric Drives, Electric Energy Systems, Data Structures & Algorithms, Power Electronics

BTech Branch

BTech 1st Year Engineering, BTech Electrical & Electronics

Type of class

Regular Classes

Class strength catered to

One on one/ Private Tutions

Taught in School or College

No

BTech 1st Year subjects

Basic Electronics, Basic Electrical Technology, Engineering Graphics, Engineering Mathematics (M1), Engineering Chemistry, Advanced Mathematics (M2), Engineering Physics, Environmental Studies, Computer science

Reviews

No Reviews yet!

Answers by Vanga Goutham Reddy

Answered on 05/09/2019 Learn CBSE - Class 12/Mathematics/Application of Derivatives/NCERT Solutions/Exercise 6.3

Ask a Question

Post a Lesson

Slope of normal and slope of tangent are perpendicular to each other.e.g., slope of normal x = 1 - a sinθdifferentiate x with respect to θ,dx/dθ = 0 - a.d(sinθ)/dθ = - a.cosθ ------(1)y = bcos²θdifferentiate y with respect to θ,dy/dθ = b. d(cos²θ)/dθ=... ...more

Slope of normal and slope of tangent are perpendicular to each other.
e.g., slope of normal 

x = 1 - a sinθ
differentiate x with respect to θ,
dx/dθ = 0 - a.d(sinθ)/dθ = - a.cosθ ------(1)
y = bcos²θ
differentiate y with respect to θ,
dy/dθ = b. d(cos²θ)/dθ
= b. 2cosθ. (-sinθ)
= -2bsinθ.cosθ --------(2)

dividing equations (2) by (1),

dividing equations (2) by (1),
dy/dx = -2bsinθ.cosθ/-acosθ = 2b/a sinθ
at θ = π/2 , dy/dx = 2b/a sinπ/2 = 2b/a
so, slope of normal = -1/slope of tangent
= -1/(2b/a) = -a/2b

Answers 5 Comments
Dislike Bookmark

Answered on 05/09/2019 Learn CBSE - Class 12/Mathematics/Determinants/NCERT Solutions/Miscellaneous Exercise 4

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Post a Lesson

(x+a)× - x + x =0 (x+a) × - x + x = 0 (x+a) - ax² -ax² =0 2ax² + a²x + 2a²x + a³ -2ax² = 0 3a²x +a³ = 0 a² (3x + a) = 0 a != 0, ( 3x + a)= 0 3x = -a ...more

(x+a)×[(x+a)² - x²] - x [x(x+a) - x²] + x [ x²- x(x+a)]  =0

(x+a) ×[ x²+2ax+a² - x²] - x[ x² + ax -x²] + x [ x² - x² - ax] = 0

(x+a) [2ax + a²] - ax² -ax² =0

2ax² + a²x + 2a²x + a³ -2ax² = 0

3a²x +a³ = 0

a² (3x + a) = 0

a != 0, ( 3x + a)= 0

3x = -a

 

Answers 3 Comments
Dislike Bookmark
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Please select a Tag

Teaches

Class 12 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

1

Board

State, International Baccalaureate, ISC/ICSE, CBSE

Subjects taught

Engineering Graphics, Chemistry, Sanskrit, Economics, Computer Science, Electronics, Political Science, English, Geography, Telugu, History, Biology, Physics, Mathematics

Taught in School or College

No

Class 10 Tuition
1 Student

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

ICSE, CBSE, State

Subjects taught

Economic Application, English Literature, History and Civics, Telugu, Science, Chemistry, Physics, Biology, Sanskrit, Geography, English, Mathematics, Social Science

Taught in School or College

No

Class 11 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

State, ISC/ICSE, CBSE

Subjects taught

Mathematics, Engineering Graphics, Chemistry, Biotechnology, Physics, Telugu, History, English, Economics, Electronics, Biology, Geography, Computer Science

Taught in School or College

No

BTech Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in BTech Tuition

1

BTech Electrical & Electronics subjects

(Dc- Ac) Direct Current-Alternatiing Current System Interaction, Electromagnetic Theory, Design Of Embedded Controllers, High-Voltage Direct Current (Hvdc) Transmission, Analog And Digital Communication, Switchgear And Protection, Embedded Processor Architecture, Power System Protection, Regulation & Security, Direct Energy Conversion, Applications of Digital Signal Processing (DSP), Control Systems, Electrical Circuit Analysis, Alternative Energy Sources, Circuit Theory, Discrete Fourier Transforms And Digital Filter Design, High-Voltage Engineering, Power System Engineering, Electric Drives, Electric Energy Systems, Data Structures & Algorithms, Power Electronics

BTech Branch

BTech 1st Year Engineering, BTech Electrical & Electronics

Type of class

Regular Classes

Class strength catered to

One on one/ Private Tutions

Taught in School or College

No

BTech 1st Year subjects

Basic Electronics, Basic Electrical Technology, Engineering Graphics, Engineering Mathematics (M1), Engineering Chemistry, Advanced Mathematics (M2), Engineering Physics, Environmental Studies, Computer science

No Reviews yet!

Answers by Vanga Goutham Reddy

Answered on 05/09/2019 Learn CBSE - Class 12/Mathematics/Application of Derivatives/NCERT Solutions/Exercise 6.3

Ask a Question

Post a Lesson

Slope of normal and slope of tangent are perpendicular to each other.e.g., slope of normal x = 1 - a sinθdifferentiate x with respect to θ,dx/dθ = 0 - a.d(sinθ)/dθ = - a.cosθ ------(1)y = bcos²θdifferentiate y with respect to θ,dy/dθ = b. d(cos²θ)/dθ=... ...more

Slope of normal and slope of tangent are perpendicular to each other.
e.g., slope of normal 

x = 1 - a sinθ
differentiate x with respect to θ,
dx/dθ = 0 - a.d(sinθ)/dθ = - a.cosθ ------(1)
y = bcos²θ
differentiate y with respect to θ,
dy/dθ = b. d(cos²θ)/dθ
= b. 2cosθ. (-sinθ)
= -2bsinθ.cosθ --------(2)

dividing equations (2) by (1),

dividing equations (2) by (1),
dy/dx = -2bsinθ.cosθ/-acosθ = 2b/a sinθ
at θ = π/2 , dy/dx = 2b/a sinπ/2 = 2b/a
so, slope of normal = -1/slope of tangent
= -1/(2b/a) = -a/2b

Answers 5 Comments
Dislike Bookmark

Answered on 05/09/2019 Learn CBSE - Class 12/Mathematics/Determinants/NCERT Solutions/Miscellaneous Exercise 4

Ask a Question

Post a Lesson

(x+a)× - x + x =0 (x+a) × - x + x = 0 (x+a) - ax² -ax² =0 2ax² + a²x + 2a²x + a³ -2ax² = 0 3a²x +a³ = 0 a² (3x + a) = 0 a != 0, ( 3x + a)= 0 3x = -a ...more

(x+a)×[(x+a)² - x²] - x [x(x+a) - x²] + x [ x²- x(x+a)]  =0

(x+a) ×[ x²+2ax+a² - x²] - x[ x² + ax -x²] + x [ x² - x² - ax] = 0

(x+a) [2ax + a²] - ax² -ax² =0

2ax² + a²x + 2a²x + a³ -2ax² = 0

3a²x +a³ = 0

a² (3x + a) = 0

a != 0, ( 3x + a)= 0

3x = -a

 

Answers 3 Comments
Dislike Bookmark
x

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