Begumpet, Hyderabad 
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Anurag group of institutions 2018
Bachelor of Technology (B.Tech.)
Begumpet, Hyderabad, India - 500016
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Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
International Baccalaureate, CBSE, State, ISC/ICSE
Subjects taught
Geography, Political Science, Economics, Biology, English, Mathematics, Engineering Graphics, Physics, Electronics, History, Chemistry, Telugu, Computer Science, Sanskrit
Taught in School or College
No
1 Student Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
ICSE, CBSE, State
Subjects taught
Science, Social Science, Telugu, English Literature, Geography, Mathematics, Economic Application, Sanskrit, History and Civics, Physics, Biology, English, Chemistry
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
CBSE, State, ISC/ICSE
Subjects taught
Mathematics, Chemistry, Biotechnology, Engineering Graphics, Computer Science, Economics, Physics, Electronics, Telugu, Geography, History, Biology, English
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in BTech Tuition
1
BTech Electrical & Electronics subjects
Circuit Theory, Data Structures & Algorithms, High-Voltage Engineering, Power System Engineering, Switchgear And Protection, Analog And Digital Communication, High-Voltage Direct Current (Hvdc) Transmission, Embedded Processor Architecture, Applications of Digital Signal Processing (DSP), Alternative Energy Sources, Discrete Fourier Transforms And Digital Filter Design, Electric Drives, Electrical Circuit Analysis, Electromagnetic Theory, Power System Protection, Regulation & Security, Direct Energy Conversion, Design Of Embedded Controllers, Power Electronics, Control Systems, Electric Energy Systems, (Dc- Ac) Direct Current-Alternatiing Current System Interaction
BTech Branch
BTech 1st Year Engineering, BTech Electrical & Electronics
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
Taught in School or College
No
BTech 1st Year subjects
Basic Electrical Technology, Engineering Chemistry, Engineering Mathematics (M1), Basic Electronics, Engineering Physics, Advanced Mathematics (M2), Environmental Studies, Engineering Graphics, Computer science
Answered on 06/09/2019 Learn CBSE - Class 12/Mathematics/Differential Equations/NCERT Solutions/Miscellaneous Exercise 9
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Post a Lesson
Like 0 
Answers 4 
Comments Answered on 05/09/2019 Learn CBSE - Class 12/Mathematics/Application of Derivatives/NCERT Solutions/Exercise 6.3
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Post a Lesson
Slope of normal and slope of tangent are perpendicular to each other.
e.g., slope of normal
x = 1 - a sinθ
differentiate x with respect to θ,
dx/dθ = 0 - a.d(sinθ)/dθ = - a.cosθ ------(1)
y = bcos²θ
differentiate y with respect to θ,
dy/dθ = b. d(cos²θ)/dθ
= b. 2cosθ. (-sinθ)
= -2bsinθ.cosθ --------(2)
dividing equations (2) by (1),
dividing equations (2) by (1),
dy/dx = -2bsinθ.cosθ/-acosθ = 2b/a sinθ
at θ = π/2 , dy/dx = 2b/a sinπ/2 = 2b/a
so, slope of normal = -1/slope of tangent
= -1/(2b/a) = -a/2b
Like 0 Answers 5 Comments Answered on 05/09/2019 Learn CBSE - Class 12/Mathematics/Determinants/NCERT Solutions/Miscellaneous Exercise 4
Ask a Question
Post a Lesson
(x+a)×[(x+a)² - x²] - x [x(x+a) - x²] + x [ x²- x(x+a)] =0
(x+a) ×[ x²+2ax+a² - x²] - x[ x² + ax -x²] + x [ x² - x² - ax] = 0
(x+a) [2ax + a²] - ax² -ax² =0
2ax² + a²x + 2a²x + a³ -2ax² = 0
3a²x +a³ = 0
a² (3x + a) = 0
a != 0, ( 3x + a)= 0
3x = -a
Like 0 Answers 3 Comments Ask a Question
Also have a look at
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
International Baccalaureate, CBSE, State, ISC/ICSE
Subjects taught
Geography, Political Science, Economics, Biology, English, Mathematics, Engineering Graphics, Physics, Electronics, History, Chemistry, Telugu, Computer Science, Sanskrit
Taught in School or College
No
1 Student Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
ICSE, CBSE, State
Subjects taught
Science, Social Science, Telugu, English Literature, Geography, Mathematics, Economic Application, Sanskrit, History and Civics, Physics, Biology, English, Chemistry
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
CBSE, State, ISC/ICSE
Subjects taught
Mathematics, Chemistry, Biotechnology, Engineering Graphics, Computer Science, Economics, Physics, Electronics, Telugu, Geography, History, Biology, English
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in BTech Tuition
1
BTech Electrical & Electronics subjects
Circuit Theory, Data Structures & Algorithms, High-Voltage Engineering, Power System Engineering, Switchgear And Protection, Analog And Digital Communication, High-Voltage Direct Current (Hvdc) Transmission, Embedded Processor Architecture, Applications of Digital Signal Processing (DSP), Alternative Energy Sources, Discrete Fourier Transforms And Digital Filter Design, Electric Drives, Electrical Circuit Analysis, Electromagnetic Theory, Power System Protection, Regulation & Security, Direct Energy Conversion, Design Of Embedded Controllers, Power Electronics, Control Systems, Electric Energy Systems, (Dc- Ac) Direct Current-Alternatiing Current System Interaction
BTech Branch
BTech 1st Year Engineering, BTech Electrical & Electronics
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
Taught in School or College
No
BTech 1st Year subjects
Basic Electrical Technology, Engineering Chemistry, Engineering Mathematics (M1), Basic Electronics, Engineering Physics, Advanced Mathematics (M2), Environmental Studies, Engineering Graphics, Computer science
Answered on 06/09/2019 Learn CBSE - Class 12/Mathematics/Differential Equations/NCERT Solutions/Miscellaneous Exercise 9
Ask a Question
Post a Lesson
Like 0 Answers 4 Comments Answered on 05/09/2019 Learn CBSE - Class 12/Mathematics/Application of Derivatives/NCERT Solutions/Exercise 6.3
Ask a Question
Post a Lesson
Slope of normal and slope of tangent are perpendicular to each other.
e.g., slope of normal
x = 1 - a sinθ
differentiate x with respect to θ,
dx/dθ = 0 - a.d(sinθ)/dθ = - a.cosθ ------(1)
y = bcos²θ
differentiate y with respect to θ,
dy/dθ = b. d(cos²θ)/dθ
= b. 2cosθ. (-sinθ)
= -2bsinθ.cosθ --------(2)
dividing equations (2) by (1),
dividing equations (2) by (1),
dy/dx = -2bsinθ.cosθ/-acosθ = 2b/a sinθ
at θ = π/2 , dy/dx = 2b/a sinπ/2 = 2b/a
so, slope of normal = -1/slope of tangent
= -1/(2b/a) = -a/2b
Like 0 Answers 5 Comments Answered on 05/09/2019 Learn CBSE - Class 12/Mathematics/Determinants/NCERT Solutions/Miscellaneous Exercise 4
Ask a Question
Post a Lesson
(x+a)×[(x+a)² - x²] - x [x(x+a) - x²] + x [ x²- x(x+a)] =0
(x+a) ×[ x²+2ax+a² - x²] - x[ x² + ax -x²] + x [ x² - x² - ax] = 0
(x+a) [2ax + a²] - ax² -ax² =0
2ax² + a²x + 2a²x + a³ -2ax² = 0
3a²x +a³ = 0
a² (3x + a) = 0
a != 0, ( 3x + a)= 0
3x = -a
Like 0 Answers 3 Comments Ask a Question
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