Details verified of Vanga Goutham Reddy✕
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Online Classes Telugu Mother Tongue (Native)
English Proficient
Hindi Proficient
Anurag group of institutions 2018
Bachelor of Technology (B.Tech.)
Begumpet, Hyderabad, India - 500016
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Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
International Baccalaureate, CBSE, State, ISC/ICSE
Subjects taught
Economics, Sanskrit, History, Political Science, Computer Science, Telugu, Chemistry, English, Mathematics, Physics, Electronics, Geography, Engineering Graphics, Biology
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
ICSE, State, CBSE
Subjects taught
Economic Application, Physics, Biology, Geography, Sanskrit, Science, Social Science, Chemistry, History and Civics, Telugu, Mathematics, English Literature, English
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
CBSE, State, ISC/ICSE
Subjects taught
English, Economics, Computer Science, Telugu, Engineering Graphics, Physics, Chemistry, Electronics, Biology, Geography, History, Mathematics, Biotechnology
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in BTech Tuition
1
BTech Electrical & Electronics subjects
Circuit Theory, Embedded Processor Architecture, Electromagnetic Theory, Applications of Digital Signal Processing (DSP), Direct Energy Conversion, Electrical Circuit Analysis, Switchgear And Protection, Design Of Embedded Controllers, Electric Drives, Control Systems, (Dc- Ac) Direct Current-Alternatiing Current System Interaction, Discrete Fourier Transforms And Digital Filter Design, Analog And Digital Communication, Power Electronics, Alternative Energy Sources, Electric Energy Systems, High-Voltage Engineering, Power System Protection, Regulation & Security, Power System Engineering, High-Voltage Direct Current (Hvdc) Transmission, Data Structures & Algorithms
BTech Branch
BTech 1st Year Engineering, BTech Electrical & Electronics
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
Taught in School or College
No
BTech 1st Year subjects
Engineering Chemistry, Environmental Studies, Basic Electronics, Engineering Mathematics (M1), Computer science, Advanced Mathematics (M2), Basic Electrical Technology, Engineering Physics, Engineering Graphics
Answered on 06/09/2019 Learn CBSE - Class 12/Mathematics/Differential Equations/NCERT Solutions/Miscellaneous Exercise 9
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Answered on 05/09/2019 Learn CBSE - Class 12/Mathematics/Application of Derivatives/NCERT Solutions/Exercise 6.3
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Slope of normal and slope of tangent are perpendicular to each other.
e.g., slope of normal
x = 1 - a sinθ
differentiate x with respect to θ,
dx/dθ = 0 - a.d(sinθ)/dθ = - a.cosθ ------(1)
y = bcos²θ
differentiate y with respect to θ,
dy/dθ = b. d(cos²θ)/dθ
= b. 2cosθ. (-sinθ)
= -2bsinθ.cosθ --------(2)
dividing equations (2) by (1),
dividing equations (2) by (1),
dy/dx = -2bsinθ.cosθ/-acosθ = 2b/a sinθ
at θ = π/2 , dy/dx = 2b/a sinπ/2 = 2b/a
so, slope of normal = -1/slope of tangent
= -1/(2b/a) = -a/2b
Answered on 05/09/2019 Learn CBSE - Class 12/Mathematics/Determinants/NCERT Solutions/Miscellaneous Exercise 4
Ask a Question
(x+a)×[(x+a)² - x²] - x [x(x+a) - x²] + x [ x²- x(x+a)] =0
(x+a) ×[ x²+2ax+a² - x²] - x[ x² + ax -x²] + x [ x² - x² - ax] = 0
(x+a) [2ax + a²] - ax² -ax² =0
2ax² + a²x + 2a²x + a³ -2ax² = 0
3a²x +a³ = 0
a² (3x + a) = 0
a != 0, ( 3x + a)= 0
3x = -a
Ask a Question
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Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
International Baccalaureate, CBSE, State, ISC/ICSE
Subjects taught
Economics, Sanskrit, History, Political Science, Computer Science, Telugu, Chemistry, English, Mathematics, Physics, Electronics, Geography, Engineering Graphics, Biology
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
ICSE, State, CBSE
Subjects taught
Economic Application, Physics, Biology, Geography, Sanskrit, Science, Social Science, Chemistry, History and Civics, Telugu, Mathematics, English Literature, English
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
CBSE, State, ISC/ICSE
Subjects taught
English, Economics, Computer Science, Telugu, Engineering Graphics, Physics, Chemistry, Electronics, Biology, Geography, History, Mathematics, Biotechnology
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in BTech Tuition
1
BTech Electrical & Electronics subjects
Circuit Theory, Embedded Processor Architecture, Electromagnetic Theory, Applications of Digital Signal Processing (DSP), Direct Energy Conversion, Electrical Circuit Analysis, Switchgear And Protection, Design Of Embedded Controllers, Electric Drives, Control Systems, (Dc- Ac) Direct Current-Alternatiing Current System Interaction, Discrete Fourier Transforms And Digital Filter Design, Analog And Digital Communication, Power Electronics, Alternative Energy Sources, Electric Energy Systems, High-Voltage Engineering, Power System Protection, Regulation & Security, Power System Engineering, High-Voltage Direct Current (Hvdc) Transmission, Data Structures & Algorithms
BTech Branch
BTech 1st Year Engineering, BTech Electrical & Electronics
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
Taught in School or College
No
BTech 1st Year subjects
Engineering Chemistry, Environmental Studies, Basic Electronics, Engineering Mathematics (M1), Computer science, Advanced Mathematics (M2), Basic Electrical Technology, Engineering Physics, Engineering Graphics
Answered on 06/09/2019 Learn CBSE - Class 12/Mathematics/Differential Equations/NCERT Solutions/Miscellaneous Exercise 9
Ask a Question
Answered on 05/09/2019 Learn CBSE - Class 12/Mathematics/Application of Derivatives/NCERT Solutions/Exercise 6.3
Ask a Question
Slope of normal and slope of tangent are perpendicular to each other.
e.g., slope of normal
x = 1 - a sinθ
differentiate x with respect to θ,
dx/dθ = 0 - a.d(sinθ)/dθ = - a.cosθ ------(1)
y = bcos²θ
differentiate y with respect to θ,
dy/dθ = b. d(cos²θ)/dθ
= b. 2cosθ. (-sinθ)
= -2bsinθ.cosθ --------(2)
dividing equations (2) by (1),
dividing equations (2) by (1),
dy/dx = -2bsinθ.cosθ/-acosθ = 2b/a sinθ
at θ = π/2 , dy/dx = 2b/a sinπ/2 = 2b/a
so, slope of normal = -1/slope of tangent
= -1/(2b/a) = -a/2b
Answered on 05/09/2019 Learn CBSE - Class 12/Mathematics/Determinants/NCERT Solutions/Miscellaneous Exercise 4
Ask a Question
(x+a)×[(x+a)² - x²] - x [x(x+a) - x²] + x [ x²- x(x+a)] =0
(x+a) ×[ x²+2ax+a² - x²] - x[ x² + ax -x²] + x [ x² - x² - ax] = 0
(x+a) [2ax + a²] - ax² -ax² =0
2ax² + a²x + 2a²x + a³ -2ax² = 0
3a²x +a³ = 0
a² (3x + a) = 0
a != 0, ( 3x + a)= 0
3x = -a
Ask a Question
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