Details verified of Vanga Goutham Reddy✕
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Online Classes Telugu Mother Tongue (Native)
English Proficient
Hindi Proficient
Anurag group of institutions 2018
Bachelor of Technology (B.Tech.)
Begumpet, Hyderabad, India - 500016
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Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
State, CBSE, International Baccalaureate, ISC/ICSE
Subjects taught
Mathematics, Geography, Telugu, Electronics, History, Engineering Graphics, Computer Science, Biology, English, Sanskrit, Political Science, Chemistry, Physics, Economics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
State, ICSE, CBSE
Subjects taught
Physics, English, Mathematics, Science, Sanskrit, Biology, Telugu, Social Science, Geography, Chemistry, History and Civics, Economic Application, English Literature
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
State, CBSE, ISC/ICSE
Subjects taught
Physics, English, Economics, Biotechnology, Mathematics, Geography, History, Electronics, Biology, Computer Science, Telugu, Engineering Graphics, Chemistry
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in BTech Tuition
1
BTech Electrical & Electronics subjects
(Dc- Ac) Direct Current-Alternatiing Current System Interaction, Design Of Embedded Controllers, Embedded Processor Architecture, Power System Protection, Regulation & Security, Switchgear And Protection, Electrical Circuit Analysis, Electromagnetic Theory, Control Systems, Analog And Digital Communication, Data Structures & Algorithms, Direct Energy Conversion, Power System Engineering, Applications of Digital Signal Processing (DSP), High-Voltage Direct Current (Hvdc) Transmission, Electric Drives, Alternative Energy Sources, High-Voltage Engineering, Discrete Fourier Transforms And Digital Filter Design, Electric Energy Systems, Power Electronics, Circuit Theory
BTech Branch
BTech Electrical & Electronics, BTech 1st Year Engineering
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
Taught in School or College
No
BTech 1st Year subjects
Engineering Graphics, Advanced Mathematics (M2), Basic Electrical Technology, Computer science, Engineering Physics, Environmental Studies, Engineering Mathematics (M1), Basic Electronics, Engineering Chemistry
Answered on 06/09/2019 Learn CBSE - Class 12/Mathematics/Differential Equations/NCERT Solutions/Miscellaneous Exercise 9
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Answered on 05/09/2019 Learn CBSE - Class 12/Mathematics/Application of Derivatives/NCERT Solutions/Exercise 6.3
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Slope of normal and slope of tangent are perpendicular to each other.
e.g., slope of normal
x = 1 - a sinθ
differentiate x with respect to θ,
dx/dθ = 0 - a.d(sinθ)/dθ = - a.cosθ ------(1)
y = bcos²θ
differentiate y with respect to θ,
dy/dθ = b. d(cos²θ)/dθ
= b. 2cosθ. (-sinθ)
= -2bsinθ.cosθ --------(2)
dividing equations (2) by (1),
dividing equations (2) by (1),
dy/dx = -2bsinθ.cosθ/-acosθ = 2b/a sinθ
at θ = π/2 , dy/dx = 2b/a sinπ/2 = 2b/a
so, slope of normal = -1/slope of tangent
= -1/(2b/a) = -a/2b
Answered on 05/09/2019 Learn CBSE - Class 12/Mathematics/Determinants/NCERT Solutions/Miscellaneous Exercise 4
Ask a Question
(x+a)×[(x+a)² - x²] - x [x(x+a) - x²] + x [ x²- x(x+a)] =0
(x+a) ×[ x²+2ax+a² - x²] - x[ x² + ax -x²] + x [ x² - x² - ax] = 0
(x+a) [2ax + a²] - ax² -ax² =0
2ax² + a²x + 2a²x + a³ -2ax² = 0
3a²x +a³ = 0
a² (3x + a) = 0
a != 0, ( 3x + a)= 0
3x = -a
Ask a Question
Also have a look at
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
State, CBSE, International Baccalaureate, ISC/ICSE
Subjects taught
Mathematics, Geography, Telugu, Electronics, History, Engineering Graphics, Computer Science, Biology, English, Sanskrit, Political Science, Chemistry, Physics, Economics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
State, ICSE, CBSE
Subjects taught
Physics, English, Mathematics, Science, Sanskrit, Biology, Telugu, Social Science, Geography, Chemistry, History and Civics, Economic Application, English Literature
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Board
State, CBSE, ISC/ICSE
Subjects taught
Physics, English, Economics, Biotechnology, Mathematics, Geography, History, Electronics, Biology, Computer Science, Telugu, Engineering Graphics, Chemistry
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in BTech Tuition
1
BTech Electrical & Electronics subjects
(Dc- Ac) Direct Current-Alternatiing Current System Interaction, Design Of Embedded Controllers, Embedded Processor Architecture, Power System Protection, Regulation & Security, Switchgear And Protection, Electrical Circuit Analysis, Electromagnetic Theory, Control Systems, Analog And Digital Communication, Data Structures & Algorithms, Direct Energy Conversion, Power System Engineering, Applications of Digital Signal Processing (DSP), High-Voltage Direct Current (Hvdc) Transmission, Electric Drives, Alternative Energy Sources, High-Voltage Engineering, Discrete Fourier Transforms And Digital Filter Design, Electric Energy Systems, Power Electronics, Circuit Theory
BTech Branch
BTech Electrical & Electronics, BTech 1st Year Engineering
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
Taught in School or College
No
BTech 1st Year subjects
Engineering Graphics, Advanced Mathematics (M2), Basic Electrical Technology, Computer science, Engineering Physics, Environmental Studies, Engineering Mathematics (M1), Basic Electronics, Engineering Chemistry
Answered on 06/09/2019 Learn CBSE - Class 12/Mathematics/Differential Equations/NCERT Solutions/Miscellaneous Exercise 9
Ask a Question
Answered on 05/09/2019 Learn CBSE - Class 12/Mathematics/Application of Derivatives/NCERT Solutions/Exercise 6.3
Ask a Question
Slope of normal and slope of tangent are perpendicular to each other.
e.g., slope of normal
x = 1 - a sinθ
differentiate x with respect to θ,
dx/dθ = 0 - a.d(sinθ)/dθ = - a.cosθ ------(1)
y = bcos²θ
differentiate y with respect to θ,
dy/dθ = b. d(cos²θ)/dθ
= b. 2cosθ. (-sinθ)
= -2bsinθ.cosθ --------(2)
dividing equations (2) by (1),
dividing equations (2) by (1),
dy/dx = -2bsinθ.cosθ/-acosθ = 2b/a sinθ
at θ = π/2 , dy/dx = 2b/a sinπ/2 = 2b/a
so, slope of normal = -1/slope of tangent
= -1/(2b/a) = -a/2b
Answered on 05/09/2019 Learn CBSE - Class 12/Mathematics/Determinants/NCERT Solutions/Miscellaneous Exercise 4
Ask a Question
(x+a)×[(x+a)² - x²] - x [x(x+a) - x²] + x [ x²- x(x+a)] =0
(x+a) ×[ x²+2ax+a² - x²] - x[ x² + ax -x²] + x [ x² - x² - ax] = 0
(x+a) [2ax + a²] - ax² -ax² =0
2ax² + a²x + 2a²x + a³ -2ax² = 0
3a²x +a³ = 0
a² (3x + a) = 0
a != 0, ( 3x + a)= 0
3x = -a
Ask a Question
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