Begumpet, Hyderabad, India - 500016.
1
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Telugu Mother Tongue (Native)
English Proficient
Hindi Proficient
Anurag group of institutions 2018
Bachelor of Technology (B.Tech.)
Begumpet, Hyderabad, India - 500016
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
ISC/ICSE, CBSE, International Baccalaureate, State
IB Subjects taught
Mathematics, Physics, Chemistry, English, Geography, History, Economics, Biology, Computer Science
ISC/ICSE Subjects taught
Chemistry, Computer Science, Geography, Economics, English, History, Mathematics, Physics
CBSE Subjects taught
Mathematics, Economics, History, Physics, Chemistry, Geography, Political Science, Engineering Graphics
Taught in School or College
No
State Syllabus Subjects taught
Telugu, Mathematics, Chemistry, Engineering Graphics, Sanskrit, Geography, Physics, English, Economics, Electronics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE, ICSE, State
CBSE Subjects taught
Mathematics, Science, Sanskrit, Social science, Telugu, English
ICSE Subjects taught
History and Civics, English, Mathematics, English Literature, Chemistry, Biology, Geography, Economic Application, Physics
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, Science, Social Science, Telugu, Sanskrit, English
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
ISC/ICSE, CBSE, State
ISC/ICSE Subjects taught
Chemistry, Geography, Economics, English, Biology, Mathematics, Physics
CBSE Subjects taught
Economics, Mathematics, Biotechnology, Physics, Chemistry, Geography, Biology, English, Computer Science
Taught in School or College
No
State Syllabus Subjects taught
History, Telugu, Mathematics, Biology, Chemistry, Engineering Graphics, Geography, Physics, English, Economics, Electronics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BTech Tuition
1
BTech Electrical & Electronics subjects
Discrete Fourier Transforms And Digital Filter Design, Electrical Circuit Analysis, Power System Engineering, Circuit Theory, Data Structures & Algorithms, Applications of Digital Signal Processing (DSP), Alternative Energy Sources, Power Electronics, Power System Protection, Regulation & Security, Electromagnetic Theory, Electric Drives, Switchgear And Protection, Electric Energy Systems, High-Voltage Engineering, Design Of Embedded Controllers, Embedded Processor Architecture, Control Systems, (Dc- Ac) Direct Current-Alternatiing Current System Interaction, High-Voltage Direct Current (Hvdc) Transmission, Analog And Digital Communication, Direct Energy Conversion
BTech Branch
BTech Electrical & Electronics, BTech 1st Year Engineering
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
Taught in School or College
No
BTech 1st Year subjects
Environmental Studies, Basic Electrical Technology, Engineering Graphics, Engineering Physics, Computer science, Basic Electronics, Engineering Chemistry, Engineering Mathematics (M1), Advanced Mathematics (M2)
1. Which school boards of Class 12 do you teach for?
ISC/ICSE, CBSE, International Baccalaureate and others
2. Have you ever taught in any School or College?
No
3. Which classes do you teach?
I teach BTech Tuition, Class 10 Tuition, Class 11 Tuition and Class 12 Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 1 year.
Answered on 06/09/2019 Learn CBSE/Class 12/Mathematics/Differential Equations/NCERT Solutions/Miscellaneous Exercise 9
Answered on 05/09/2019 Learn CBSE/Class 12/Mathematics/Application of Derivatives/NCERT Solutions/Exercise 6.3
Slope of normal and slope of tangent are perpendicular to each other.
e.g., slope of normal
x = 1 - a sinθ
differentiate x with respect to θ,
dx/dθ = 0 - a.d(sinθ)/dθ = - a.cosθ ------(1)
y = bcos²θ
differentiate y with respect to θ,
dy/dθ = b. d(cos²θ)/dθ
= b. 2cosθ. (-sinθ)
= -2bsinθ.cosθ --------(2)
dividing equations (2) by (1),
dividing equations (2) by (1),
dy/dx = -2bsinθ.cosθ/-acosθ = 2b/a sinθ
at θ = π/2 , dy/dx = 2b/a sinπ/2 = 2b/a
so, slope of normal = -1/slope of tangent
= -1/(2b/a) = -a/2b
Answered on 05/09/2019 Learn CBSE/Class 12/Mathematics/Determinants/NCERT Solutions/Miscellaneous Exercise 4
(x+a)×[(x+a)² - x²] - x [x(x+a) - x²] + x [ x²- x(x+a)] =0
(x+a) ×[ x²+2ax+a² - x²] - x[ x² + ax -x²] + x [ x² - x² - ax] = 0
(x+a) [2ax + a²] - ax² -ax² =0
2ax² + a²x + 2a²x + a³ -2ax² = 0
3a²x +a³ = 0
a² (3x + a) = 0
a != 0, ( 3x + a)= 0
3x = -a
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
ISC/ICSE, CBSE, International Baccalaureate, State
IB Subjects taught
Mathematics, Physics, Chemistry, English, Geography, History, Economics, Biology, Computer Science
ISC/ICSE Subjects taught
Chemistry, Computer Science, Geography, Economics, English, History, Mathematics, Physics
CBSE Subjects taught
Mathematics, Economics, History, Physics, Chemistry, Geography, Political Science, Engineering Graphics
Taught in School or College
No
State Syllabus Subjects taught
Telugu, Mathematics, Chemistry, Engineering Graphics, Sanskrit, Geography, Physics, English, Economics, Electronics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE, ICSE, State
CBSE Subjects taught
Mathematics, Science, Sanskrit, Social science, Telugu, English
ICSE Subjects taught
History and Civics, English, Mathematics, English Literature, Chemistry, Biology, Geography, Economic Application, Physics
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, Science, Social Science, Telugu, Sanskrit, English
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
ISC/ICSE, CBSE, State
ISC/ICSE Subjects taught
Chemistry, Geography, Economics, English, Biology, Mathematics, Physics
CBSE Subjects taught
Economics, Mathematics, Biotechnology, Physics, Chemistry, Geography, Biology, English, Computer Science
Taught in School or College
No
State Syllabus Subjects taught
History, Telugu, Mathematics, Biology, Chemistry, Engineering Graphics, Geography, Physics, English, Economics, Electronics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in BTech Tuition
1
BTech Electrical & Electronics subjects
Discrete Fourier Transforms And Digital Filter Design, Electrical Circuit Analysis, Power System Engineering, Circuit Theory, Data Structures & Algorithms, Applications of Digital Signal Processing (DSP), Alternative Energy Sources, Power Electronics, Power System Protection, Regulation & Security, Electromagnetic Theory, Electric Drives, Switchgear And Protection, Electric Energy Systems, High-Voltage Engineering, Design Of Embedded Controllers, Embedded Processor Architecture, Control Systems, (Dc- Ac) Direct Current-Alternatiing Current System Interaction, High-Voltage Direct Current (Hvdc) Transmission, Analog And Digital Communication, Direct Energy Conversion
BTech Branch
BTech Electrical & Electronics, BTech 1st Year Engineering
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions
Taught in School or College
No
BTech 1st Year subjects
Environmental Studies, Basic Electrical Technology, Engineering Graphics, Engineering Physics, Computer science, Basic Electronics, Engineering Chemistry, Engineering Mathematics (M1), Advanced Mathematics (M2)
Answered on 06/09/2019 Learn CBSE/Class 12/Mathematics/Differential Equations/NCERT Solutions/Miscellaneous Exercise 9
Answered on 05/09/2019 Learn CBSE/Class 12/Mathematics/Application of Derivatives/NCERT Solutions/Exercise 6.3
Slope of normal and slope of tangent are perpendicular to each other.
e.g., slope of normal
x = 1 - a sinθ
differentiate x with respect to θ,
dx/dθ = 0 - a.d(sinθ)/dθ = - a.cosθ ------(1)
y = bcos²θ
differentiate y with respect to θ,
dy/dθ = b. d(cos²θ)/dθ
= b. 2cosθ. (-sinθ)
= -2bsinθ.cosθ --------(2)
dividing equations (2) by (1),
dividing equations (2) by (1),
dy/dx = -2bsinθ.cosθ/-acosθ = 2b/a sinθ
at θ = π/2 , dy/dx = 2b/a sinπ/2 = 2b/a
so, slope of normal = -1/slope of tangent
= -1/(2b/a) = -a/2b
Answered on 05/09/2019 Learn CBSE/Class 12/Mathematics/Determinants/NCERT Solutions/Miscellaneous Exercise 4
(x+a)×[(x+a)² - x²] - x [x(x+a) - x²] + x [ x²- x(x+a)] =0
(x+a) ×[ x²+2ax+a² - x²] - x[ x² + ax -x²] + x [ x² - x² - ax] = 0
(x+a) [2ax + a²] - ax² -ax² =0
2ax² + a²x + 2a²x + a³ -2ax² = 0
3a²x +a³ = 0
a² (3x + a) = 0
a != 0, ( 3x + a)= 0
3x = -a
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