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If l, b, h, S and V are length, breadth, height, surface area and volume respectively of a cuboid, prove that: 1/V = 2/S(1/l + 1/b + 1/h)?

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TEACHING IS MY PASSION-I STILL STRIVE TO BETTER MY TEACHING ABILITIES

If l, b, h, S and V are length, breadth, height, surface area and volume respectively of a cuboid, Then, V = lbh Let us take the relation S = 2 (lb +bh + lh). Now dividing both sides with V * S, we get:- 1/V = 2 ( lb + bh = lh )/ (V * S) = 2 ( lb + bh = lh )/ (lbh * S) ...... ( Substituting lbh for...
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If l, b, h, S and V are length, breadth, height, surface area and volume respectively of a cuboid, Then, V=lbh Let us take the relation S=2 (lb +bh + lh). Now dividing both sides with V * S, we get:- 1/V = 2 ( lb + bh=lh )/ (V * S) = 2 ( lb + bh=lh )/ (lbh * S) ...... ( Substituting lbh for V) ==> 1/V = =2 [(lb/lbh )+( bh/lbh ) + (lh/ibh )] / S==> 1/V = 2/S(1/l + 1/b + 1/h) proved. read less
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TEACHING IS MY PASSION-I STILL STRIVE TO BETTER MY TEACHING ABILITIES

If l, b, h, S and V are length, breadth, height, surface area and volume respectively of a cuboid, Then We have S = 2( lb + bh + lh ) and V = lbh Let us take the relation S = 2(lb +bh + lh). Now dividing both sides with V * S, we get 1/V = 2 ( lb + bh = lh )/ (V * S) = 2 ( lb + bh +lh )/ (lbh *...
read more
If l, b, h, S and V are length, breadth, height, surface area and volume respectively of a cuboid, Then We have S=2( lb + bh + lh ) and V=lbh Let us take the relation S=2(lb +bh + lh). Now dividing both sides with V * S, we get 1/V = 2 ( lb + bh=lh )/ (V * S) = 2 ( lb + bh +lh )/ (lbh * S) ...... ( after Substituting lbh for V) ==> 1/V = 2 [(lb/lbh )+( bh/lbh ) + (lh/lbh )] / S==> 1/V = 2/S(1/l + 1/b + 1/h) proved. read less
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