Madeena

Gaddiannaram, Hyderabad, India - 500060

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Madeena

Gaddiannaram, Hyderabad, India - 500060.

3.4

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Details verified of Madeena

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Education

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Overview

I am a graduate from JNTU in mechanical engineering. I have a sound knowledge on Telugu, Hindi, English, Mathematics and physical science. I can also teach social studies.

Languages Spoken

Telugu Mother Tongue (Native)

English Proficient

Hindi Proficient

Education

Jntu 2018

Bachelor of Technology (B.Tech.)

Address

Gaddiannaram, Hyderabad, India - 500060

Verified Info

Phone Verified

Email Verified

Demo Class

No

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Class 10 Tuition Overview

Class 10 Tuition

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Board

State

CBSE Subjects taught

Mathematics, English, Hindi, Telugu

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Social Science, Hindi, Telugu, English

Reviews

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FAQs

1. Which classes do you teach?

I teach Class 10 Tuition, Class 8 Tuition, Class 9 Tuition and Class I-V Tuition Classes.

2. Do you provide a demo class?

No, I don't provide a demo class.

3. How many years of experience do you have?

I have been teaching for less than a year.

Answers by Madeena (2)

Answered on 24 Jun Tuition

x3 + y3 + z3 – 3xyz = (x+ y + z) (x2 + y2 + z2 – xy – yz – zx). So, by your question, R.H.S becomes zero. Then, x3 + y3 + z3 = 3xyz. So the answer is 3xyz ...more

x3 + y3 + z3 – 3xyz = (xy + z) (x2 + y2 + z2 – xy – yz – zx). So, by your question, R.H.S becomes zero. Then, x3 + y3 + z3 = 3xyz. So the answer is 3xyz

Answers 276 Comments
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Answered on 24 Jun CBSE/Class 10/English

Each of you come here
Answers 142 Comments
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MadeenaDirections

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Class 10 Tuition 3.4

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Board

State

CBSE Subjects taught

Mathematics, English, Hindi, Telugu

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Social Science, Hindi, Telugu, English

Class I-V Tuition 3.4

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Hindi, English, Mathematics, Social Science, Science, Telugu

Class 9 Tuition 3.4

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Social Science, Hindi, Telugu, English

Class 8 Tuition 3.4

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Telugu, Social science, Mathematics, Hindi, English

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Answers by Madeena (2)

Answered on 24 Jun Tuition

x3 + y3 + z3 – 3xyz = (x+ y + z) (x2 + y2 + z2 – xy – yz – zx). So, by your question, R.H.S becomes zero. Then, x3 + y3 + z3 = 3xyz. So the answer is 3xyz ...more

x3 + y3 + z3 – 3xyz = (xy + z) (x2 + y2 + z2 – xy – yz – zx). So, by your question, R.H.S becomes zero. Then, x3 + y3 + z3 = 3xyz. So the answer is 3xyz

Answers 276 Comments
Dislike Bookmark

Answered on 24 Jun CBSE/Class 10/English

Each of you come here
Answers 142 Comments
Dislike Bookmark

Madeena conducts classes in Class 10 Tuition, Class 8 Tuition and Class 9 Tuition. Madeena is located in Gaddiannaram, Hyderabad. Madeena takes at students Home and Regular Classes- at her Home. Madeena has completed Bachelor of Technology (B.Tech.) from Jntu in 2018. She is well versed in English, Telugu and Hindi.

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