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Anjal Kumar

JNTU, Kukatpally, Hyderabad, India- 500085.

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Details verified of Anjal Kumar

Identity

Education

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Identity is verified based on matching the details uploaded by the Tutor with government databases.

Overview

I can teach each and every topics very easily and make it stronger for the students.

Demo Class

No

Languages Spoken

English, Telugu

Education

Bachelor of Technology (B.Tech.) from JNTUH -Pursuing.

Address

JNTU, Kukatpally, Hyderabad, India- 500085.

Class I-V Tuition Overview

Class I-V Tuition

Board

CBSE, State

CBSE Subjects taught

Mathematics, Science

Experience in School or College

Taught in School or College

No

State Syllabus Subjects taught

English, Mathematics, Science

Class Location

Student's Home

Years of Experience in Class I-V Tuition

1

View all Classes

Reviews

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No Reviews yet! Be the first one to Review

Answers by Anjal Kumar (4)

"Let X and 1/X be the two zeros of given polynomial Comparing given polynomial with az2+ bz +c we get a=5 b=13 c=-p Product of two zeros=-p But product of zeros =x× 1/X=1 hence p= -1" in   CBSE/Class 10/Mathematics, Tuition/Class IX-X Tuition

Your process is absolutely correct but product of zeros=c/a. Here c=-p and a=5 and x(1/x)=1 so c/a=1and -p/a=1and-p/5=1andp=-5

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"If one zero of the polynomial 5z2 + 13z – p is reciprocal of the other, then find p." in   CBSE/Class 10/Mathematics, Tuition/Class IX-X Tuition

Given 5z2 + 13z -p Let x be one zero then other zero will be 1/x as given both the zeroes are reciprocal to each other. Therefore 5x2+13x-p=0. ---------------->1 5(1/x)^2+(13/x)-p=0----------->2 Solving above equations we get p=-5

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"What is Law of conservation of mass and Law of constant proportions?" in   CBSE/Class 9/Science, Tuition/Class IX-X Tuition

Law of conservation of mass: Mass neither be created nor be destroyed. In chemical processes, Total mass of the reactants=Total mass of products Law of constant proportions: A given compound always contains exactly the same proportion of elements by weight. Example: %of cu. %of O2. %of Carbon Natural sample 51.35. 9.74. 38.91 Artoficial. 51.35. 9.74. 38.91 Therefore composition of elements in the two sample of CuCO3 are equal This law was proposed by Proust

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"Distinguish between Tropical Evergreen and Deciduous forests." in   CBSE/Class 9/Social Studies, Tuition/Class IX-X Tuition

Tropical Evergreen forests: These forests receive heavy rain fall as they are located near equator.These are also known as tropical rain forests.These forests are always evergreen because the trees shed their leaves at different times.These are more dense compared to deciduous. Examples:Mahagany,Ebony,Rosewood. Deciduous forests: These forests are less dense as all variety of trees shed their leaves at the same time.That is the reason why they are not evergreen. Examples:Sal,teak,peepal,neem and sheesham.

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"Name two allotrapes of carbon." in   CBSE/Class 10/Science, Tuition/Class IX-X Tuition

Natural:Diamond ,Graphite Artificial: Buckminster fullerene

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Anjal Kumar address

x
Class I-V Tuition

Board

CBSE, State

CBSE Subjects taught

Mathematics, Science

Experience in School or College

Taught in School or College

No

State Syllabus Subjects taught

English, Mathematics, Science

Class Location

Student's Home

Years of Experience in Class I-V Tuition

1

Class IX-X Tuition

Board

CBSE, State

CBSE Subjects taught

Science, Mathematics

Experience in School or College

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, English, Science

Class Location

Student's Home

Years of Experience in Class IX-X Tuition

1

Class VI-VIII Tuition

Board

State, CBSE

CBSE Subjects taught

Mathematics, Science

Experience in School or College

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Science, English

Class Location

Student's Home

Years of Experience in Class VI-VIII Tuition

1

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No Reviews yet! Be the first one to Review

"Let X and 1/X be the two zeros of given polynomial Comparing given polynomial with az2+ bz +c we get a=5 b=13 c=-p Product of two zeros=-p But product of zeros =x× 1/X=1 hence p= -1" in   CBSE/Class 10/Mathematics, Tuition/Class IX-X Tuition

Your process is absolutely correct but product of zeros=c/a. Here c=-p and a=5 and x(1/x)=1 so c/a=1and -p/a=1and-p/5=1andp=-5

0
|
0

"If one zero of the polynomial 5z2 + 13z – p is reciprocal of the other, then find p." in   CBSE/Class 10/Mathematics, Tuition/Class IX-X Tuition

Given 5z2 + 13z -p Let x be one zero then other zero will be 1/x as given both the zeroes are reciprocal to each other. Therefore 5x2+13x-p=0. ---------------->1 5(1/x)^2+(13/x)-p=0----------->2 Solving above equations we get p=-5

0
|
0

"What is Law of conservation of mass and Law of constant proportions?" in   CBSE/Class 9/Science, Tuition/Class IX-X Tuition

Law of conservation of mass: Mass neither be created nor be destroyed. In chemical processes, Total mass of the reactants=Total mass of products Law of constant proportions: A given compound always contains exactly the same proportion of elements by weight. Example: %of cu. %of O2. %of Carbon Natural sample 51.35. 9.74. 38.91 Artoficial. 51.35. 9.74. 38.91 Therefore composition of elements in the two sample of CuCO3 are equal This law was proposed by Proust

0
|
0

"Distinguish between Tropical Evergreen and Deciduous forests." in   CBSE/Class 9/Social Studies, Tuition/Class IX-X Tuition

Tropical Evergreen forests: These forests receive heavy rain fall as they are located near equator.These are also known as tropical rain forests.These forests are always evergreen because the trees shed their leaves at different times.These are more dense compared to deciduous. Examples:Mahagany,Ebony,Rosewood. Deciduous forests: These forests are less dense as all variety of trees shed their leaves at the same time.That is the reason why they are not evergreen. Examples:Sal,teak,peepal,neem and sheesham.

0
|
0

"Name two allotrapes of carbon." in   CBSE/Class 10/Science, Tuition/Class IX-X Tuition

Natural:Diamond ,Graphite Artificial: Buckminster fullerene

0
|
0

Anjal Kumar conducts classes in Class I-V Tuition, Class IX-X Tuition and Class VI-VIII Tuition. Anjal is located in JNTU, Kukatpally, Hyderabad. Anjal takes at students Home. He has 1 years of teaching experience . Anjal is pursuing Bachelor of Technology (B.Tech.) from JNTUH. He is well versed in English and Telugu.

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